/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 (a) If \(\left\\{a_{n}\right\\}\... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) If \(\left\\{a_{n}\right\\}\) is convergent, show that $$ \lim _{n \rightarrow \infty} a_{n+1}=\lim _{n \rightarrow \infty} a_{n} $$ (b) A sequence \(\left\\{a_{n}\right\\}\) is defined by \(a_{1}=1\) and \(a_{n+1}=1 /\left(1+a_{n}\right)\) for \(n \geqslant 1 .\) Assuming that \(\left\\{a_{n}\right\\}\) is convergent, find its limit.

Short Answer

Expert verified
(a) \( \lim_{n \to \infty} a_{n+1} = \lim_{n \to \infty} a_n \); (b) Limit is \( \frac{-1 + \sqrt{5}}{2} \).

Step by step solution

01

Understand Sequence Convergence Definition

Recall that a sequence \( \{a_n\} \) is convergent if there exists a limit \( L \) such that for every \( \epsilon > 0 \), there exists an \( N \) where for all \( n \geq N \), \( |a_n - L| < \epsilon \).
02

Establish Limit Equality for Sequential Elements

Assume \( \lim_{n \to \infty} a_n = L \). For the sequence \( \{a_n\} \) to be convergent, it implies \( \lim_{n \to \infty} a_{n+1} = L \) as well. Hence, \( \lim_{n \to \infty} a_{n+1} = \lim_{n \to \infty} a_n = L \).
03

Analyze the Given Recursive Relationship

For the sequence \( \{a_n\} \), \( a_1 = 1 \) and \( a_{n+1} = \frac{1}{1 + a_n} \). Assuming the sequence converges to a limit \( L \), both \( \lim_{n \to \infty} a_n = L \) and \( \lim_{n \to \infty} a_{n+1} = L \) must hold true.
04

Set Up Limit Equation for Recursive Formula

Apply the limit to both sides of the recursive formula: \( \lim_{n \to \infty} a_{n+1} = \lim_{n \to \infty} \frac{1}{1 + a_n} \). Thus, \( L = \frac{1}{1 + L} \).
05

Solve Limit Equation

Rearrange \( L = \frac{1}{1 + L} \) to find \( L Additional Effects = L + L^2 = 1 \). Simplify to \( L^2 + L - 1 = 0 \). Solve the quadratic equation: \( L = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \); here, \( a = 1, b = 1, c = -1 \).
06

Calculate Quadratic Roots

Using the quadratic formula: \( L = \frac{-1 \pm \sqrt{1 + 4}}{2} = \frac{-1 \pm \sqrt{5}}{2} \). The roots are \( \frac{-1 + \sqrt{5}}{2} \) and \( \frac{-1 - \sqrt{5}}{2} \).
07

Select the Feasible Root

Since \( a_n \) must be non-negative and \( \frac{-1 - \sqrt{5}}{2} < 0 \), the feasible solution is \( L = \frac{-1 + \sqrt{5}}{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Definition
Understanding the limit of a sequence is essential in calculus and analysis. A sequence\( \{a_n\} \) is said to converge to a limit \( L \) if the elements in the sequence get indefinitely close to \( L \) as \( n \) becomes very large. Mathematically, this means for every small positive number \( \epsilon \), however tiny, there exists a number \( N \) such that for all elements \( n \) greater than \( N \), the absolute difference \(|a_n - L|\) is less than \( \epsilon \).
This intuitive definition implies that after some point, the sequence remains within a narrow band around \( L \).
Consider the sequence \( a_{n+1} \), if \( \{a_n\} \) is convergent to \( L \), then \( \lim_{n \to \infty} a_{n+1} = L \) as well. This is because shifting the sequence by one, i.e., considering \( a_{n+1} \) instead of \( a_n \), doesn't change its eventual closeness to the limit \( L \). Understanding this helps us reason about sequences and their behaviors beyond initial values.
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations of the form \( ax^2 + bx + c = 0 \).
To find the roots of this equation, the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), is used. This formula directly derives from completing the square of the quadratic equation and offers a straightforward method to find the roots directly.
In sequences, particularly recursive ones, quadratic equations arise when you need to find fixed points, or limits, like the problem with the sequence \( a_{n+1} = \frac{1}{1 + a_n} \). Solving this equation requires setting \( a_{n+1} = a_n = L \), leading to the quadratic \( L^2 + L - 1 = 0 \).
By using the formula, the roots for this equation are \( L = \frac{-1 \pm \sqrt{5}}{2} \). In the context of sequence limits, examining these roots tells us whether they are feasible based on the condition of non-negativity, leading us to select the appropriate root.
Recursive Sequences
Recursive sequences define each term based on the previous ones, making initial conditions crucial. For instance, the sequence \( \{a_n\} \) starts with \( a_1 = 1 \), and each subsequent term is defined as \( a_{n+1} = \frac{1}{1 + a_n} \).
The nature of recursive sequences often leads to complex behavior that can converge, diverge, or oscillate. Examining their long-term behavior, especially convergence, often involves expressing one term in terms of the next, forming equations where solving for limits requires understanding their iterative nature.
In recursive sequences, convergence can be hypothesized by assuming a limit \( L \) exists such that \( a_n \to L \) as \( n \to \infty \). By substituting into the recursive formula, we arrive at equations to solve for \( L \). The constraint of each term in the sequence being realistic (in this case, non-negative) helps eliminate non-feasible solutions from mathematical computations. This often results in practical insights into the system described by the recursive sequence.

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Most popular questions from this chapter

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