/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Evaluate the indefinite integral... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the indefinite integral as an infinite series. \(\int \frac{\cos x-1}{x} d x\)

Short Answer

Expert verified
The indefinite integral is \(-\frac{x^2}{4} + \frac{x^4}{96} - \frac{x^6}{4320} + \cdots + C\).

Step by step solution

01

Represent the Function as a Series

Use the Taylor series expansion for cosine, which is: \[\cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots\]Substitute this series representation into the integrand: \[\frac{\cos x - 1}{x} = \frac{1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \cdots - 1}{x} = -\frac{x}{2!} + \frac{x^3}{4!} - \cdots \]
02

Simplify the Series

Simplify the expression by dividing each term by \(x\):\[\frac{\cos x - 1}{x} = -\frac{x}{2} + \frac{x^3}{24} - \frac{x^5}{720} + \cdots\]
03

Integrate Term by Term

Integrate each term of the simplified series with respect to \(x\). The integral of each individual term follows the formula: \[\int x^n \, dx = \frac{x^{n+1}}{n+1}\]Thus, integrating each term,\[\int \left(-\frac{x}{2} + \frac{x^3}{24} - \frac{x^5}{720} + \cdots\right) dx = \left(-\frac{x^2}{4} + \frac{x^4}{96} - \frac{x^6}{4320} + \cdots\right) + C\]
04

Write the Final Solution

Express the final solution as an infinite series:\[\int \frac{\cos x - 1}{x} \, dx = -\frac{x^2}{4} + \frac{x^4}{96} - \frac{x^6}{4320} + \cdots + C\]where \(C\) is the constant of integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Taylor Series Expansion
The Taylor series expansion is a fundamental tool in mathematics that allows us to approximate functions using infinite sums of polynomial terms. We start with a function, like \( \cos x \), and express it in the form:\[\cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots\]Here, each term in the series is derived from the successive derivatives of \( \cos x \) evaluated at zero, giving us a way to express \( \cos x \) as an infinite series when close to zero.
In the integral we're solving, we take this expansion and adjust it for our needs, which involves substituting it into the function \( \frac{\cos x - 1}{x} \).
This adjustment sets up the series to account for the additional term \( -1 \) in the numerator, leaving us with an expression simpler to integrate right away and is crucial for further steps in our solution.
Term by Term Integration
The method of term by term integration involves integrating each term in a series individually with respect to \( x \).
Given our series from the Taylor series expansion:\[-\frac{x}{2} + \frac{x^3}{24} - \frac{x^5}{720} + \cdots\]We apply the basic integral formula for power functions, \( \int x^n \, dx = \frac{x^{n+1}}{n+1} \).
This transforms each term independently as follows:
  • The term \(-\frac{x}{2}\) becomes \(-\frac{x^2}{4}\).
  • \(\frac{x^3}{24}\) becomes \(\frac{x^4}{96}\).
  • \(-\frac{x^5}{720}\) becomes \(-\frac{x^6}{4320}\).
Term by term integration is particularly useful since each step is straightforward and follows directly from the previous one, eventually forming a series solution.
Infinite Series Integration
Infinite series integration is about summing an infinite number of terms, each integrated term by term, to find a solution to an integral.
This method is helpful when direct integration is difficult or impossible.
By beginning with a Taylor expansion and simplifying, as shown in our problem, we can transform complex functions into manageable sums.
Here's how it works in a nutshell:
  • Develop a Taylor expansion of the function around a point (usually 0 for simplicity).
  • Integrate each term separately using standard integration techniques.
  • The result is presented as a sum of all these individual integrated terms, often added by an arbitrary constant \( C \) indicating the indefinite nature.
The final series answer for the problem, \( \int \frac{\cos x - 1}{x} \), was thus expressed as an infinite series:\[-\frac{x^2}{4} + \frac{x^4}{96} - \frac{x^6}{4320} + \cdots + C\]This approach provides an answer even when a function does not possess a straightforward antiderivative.

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Most popular questions from this chapter

(a) Approximate \(f\) by a Taylor polynomial with degree \(n\) at the number a. (b) Use Taylor's Inequality to estimate the accuracy of the approximation \(f(x) \approx T_{n}(x)\) when \(x\) lies in the given interval. (c) Check your result in part (b) by graphing \(\left|R_{n}(x)\right|\) $$f(x)=x \sin x, \quad a=0, \quad n=4, \quad-1 \leqslant x \leqslant 1$$

Suppose that the radius of convergence of the power series \(\sum c_{n} x^{n}\) is \(R .\) What is the radius of convergence of the power series \(\Sigma c_{n} x^{2 m} ?\)

The Cantor set, named after the German mathematician Georg Cantor \((1845-1918),\) is constructed as follows. We start with the closed interval \([0,1]\) and remove the open interval \(\left(\frac{1}{3}, \frac{2}{3}\right) .\) That leaves the two intervals \(\left[0, \frac{1}{3}\right]\) and \(\left[\frac{2}{3}, 1\right]\) and we remove the open middle third of each. Four intervals remain and again we remove the open middle third of each of them. We continue this procedure indefinitely, at each step removing the open middle third of every interval that remains from the preceding step. The Cantor set consists of the numbers that remain in \([0,1]\) after all those intervals have been removed. (a) Show that the total length of all the intervals that are removed is \(1 .\) Despite that, the Cantor set contains infinitely many numbers. Give examples of some numbers in the Cantor set. (b) The Sierpinski carpet is a two-dimensional counterpart of the Cantor set. It is constructed by removing the center one-ninth of a square of side \(1,\) then removing the centers of the eight smaller remaining squares, and so on. (The figure shows the first three steps of the construction.) Show that the sum of the areas of the removed squares is \(1 .\) This implies that the Sierpinski carpet has area \(0 .\)

Test the series for convergence or divergence. $$\sum_{n=1}^{\infty} \frac{1}{n+n \cos ^{2} n}$$

Use Definition 2 directly to prove that \(\lim _{n \rightarrow \alpha} r^{n}=0\) when \(|r|<1\)

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