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Find the Taylor series for \(f(x)\) centered at the given value of a. [Assume that \(f\) hat \(f\) has a power series expansion. Do not show that \(R_{n}(x) \rightarrow 0 . ]\) \(f(x)=e^{x}, \quad a=3\)

Short Answer

Expert verified
The Taylor series at \(a = 3\) is \(e^3 (1 + (x-3) + \frac{(x-3)^2}{2!} + \frac{(x-3)^3}{3!} + \ldots)\).

Step by step solution

01

Understand the Problem

We are asked to find the Taylor series expansion for the function \(f(x) = e^x\), centered at \(a = 3\). A Taylor series is an infinite sum that represents a function as a polynomial around a certain point \(a\). For \(f(x) = e^x\), this involves calculating derivatives at \(x = 3\).
02

Taylor Series Formula

The Taylor series for a function \(f(x)\) at \(a = 3\) is given by: \[ f(x) = f(3) + f'(3)(x-3) + \frac{f''(3)}{2!}(x-3)^2 + \frac{f'''(3)}{3!}(x-3)^3 + \dots \] In general:\[ \sum_{n=0}^{\infty} \frac{f^{(n)}(3)}{n!} (x-3)^n \]
03

Calculate Derivatives

For the function\( f(x) = e^x \), all derivatives are equal to \( e^x \), so:- \( f(3) = e^3 \)- \( f'(3) = e^3 \)- \( f''(3) = e^3 \), and so on. Thus, all derivatives \(f^{(n)}(3) = e^3\).
04

Construct the Taylor Series

Use the series formula to write:\[ f(x) = e^3 + e^3(x-3) + \frac{e^3}{2!}(x-3)^2 + \frac{e^3}{3!}(x-3)^3 + \dots \]
05

Simplify the Series

Factor \(e^3\) out of the series:\[ f(x) = e^3 \left( 1 + (x-3) + \frac{(x-3)^2}{2!} + \frac{(x-3)^3}{3!} + \dots \right) \] This series is now in standard form with each term using \((x-3)^n / n!\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Euler's number
Euler's number, denoted as \( e \), is approximately equal to 2.71828. It is an important constant in mathematics, particularly in calculus and complex analysis. Unlike some other constants, Euler's number is not associated with physical measurements. It arises naturally in various mathematical contexts.Euler's number plays a crucial role in exponential functions. The function \( f(x) = e^x \) is unique because its derivative and integral are both \( e^x \) as well. This property makes \( e \) essential in describing growth processes, such as population growth and compound interest.Let's explore some essential characteristics of Euler's number:
  • It is the base of the natural logarithm, \( \ln{e} = 1 \).
  • It is an irrational number, meaning it cannot be expressed as a fraction of two integers.
  • In calculus, \( e \) is the limit of \( (1 + 1/n)^n \) as \( n \) approaches infinity, which connects it to continuous growth.
Power Series Expansion
A power series expansion expresses a function as an infinite sum of terms, involving powers of a variable. For any given function, particularly analytical functions, we can find such an expansion around a specific point, yielding a powerful tool to approximate and compute functions.In our exercise, we are finding the Taylor series for \( f(x) = e^x \) around \( a = 3 \), which is a specific kind of power series expansion. The general form of a Taylor series for a function \( f \) about a point \( a \) is:\[ f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n \]where \( f^{(n)}(a) \) represents the \( n \)-th derivative of \( f \), evaluated at the point \( a \).This form allows us to approximate functions closely around \( a \), even when they are complex or transcendental, like the exponential function \( e^x \). For calculation, computing these derivatives at a particular point like \( x = 3 \) for our exercise helps in constructing the entire power series which effectively acts as a polynomial approximation.
Calculus
Calculus, a mathematical field founded on the concepts of derivatives and integrals, is indispensable in exploring the behavior of functions and modeling real-world phenomena. For exponential functions such as \( f(x) = e^x \), calculus offers powerful insights into their characteristics through differentiation and integration.**Derivatives**: In our task, we calculated the derivatives of \( e^x \) to construct its Taylor series. Since \( \frac{d}{dx}e^x = e^x \), all derivatives evaluated at any point, like \( x = 3 \), are simply \( e^3 \).**Taylor Series and Approximations**: By using derivatives, we can express \( e^x \) near \( x=3 \) as a polynomial, offering a simple yet accurate approximation:\[ f(x) = e^3 \left( 1 + (x-3) + \frac{(x-3)^2}{2!} + \frac{(x-3)^3}{3!} + \dots \right) \]In essence, calculus not only aids in understanding the instantaneous change (derivatives) and cumulative totals (integrals) but also allows the transformation of complex functions into usable forms for computation and approximation, as illustrated in Taylor and power series.

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Most popular questions from this chapter

Suppose you know that $$f^{(n)}(4)=\frac{(-1)^{n} n !}{3^{n}(n+1)}$$ and the Taylor series of \(f\) centered at 4 converges to \(f(x)\) for all \(x\) in the interval of convergence. Show that the fifth-degree Taylor polynomial approximates \(f(5)\) with error less than \(0.0002 .\)

\(27-30\) Use a power series to approximate the definite integral to six decimal places.\ $$\int_{0}^{0.2} \frac{1}{1+x^{5}} d x$$

The Fibonacci sequence was defined in Section 11.1 by the equations $$f_{1}=1, \quad f_{2}=1, \quad f_{n}=f_{n-1}+f_{n-2} \quad n \geqslant 3$$ Show that each of the following statements is true. $$\begin{array}{l}{\text { (a) } \frac{1}{f_{n-1} f_{n+1}}=\frac{1}{f_{n-1} f_{n}}-\frac{1}{f_{n} f_{n+1}}} \\ {\text { (b) } \sum_{n=2}^{\infty} \frac{1}{f_{n-1} f_{n+1}}=1} \\ {\text { (c) } \sum_{n=2}^{\infty} \frac{f_{n}}{f_{n-1} f_{n+1}}=2}\end{array}$$

The resistivity \(\rho\) of a conducting wire is the reciprocal of the conductivity and is measured in units of ohm-meters \((\Omega-m) .\) The resistivity of a given metal depends on the temperature according to the equation $$\rho(t)=\rho_{20} e^{\alpha(t-20)}$$ where \(t\) is the temperature in \(^{\circ} \mathrm{C}\) . where \(t\) is the temperature in \(^{\circ} \mathrm{C} .\) There are tables that list the values of \(\alpha\) (called the temperature coefficient) and \(\rho_{20}\) (the resistivity at \(20^{\circ} \mathrm{C} )\) for various metals. Except at very low temperatures, the resistivity varies almost linearly with temperature and so it is common to approximate the expression for \(\rho(t)\) by its first- or second-degree Taylor polynomial at \(t=20\) . (a) Find expressions for these linear and quadratic approximations. (b) For copper, the tables give \(\alpha=0.0039 /^{\circ} \mathrm{C}\) and \(\rho_{20}=1.7 \times 10^{-8} \Omega-\mathrm{m} .\) Graph the resistivity of copper and the linear and quadratic approximations for \(-250^{\circ} \mathrm{C} \leqslant t \leqslant 1000^{\circ} \mathrm{C}\) (c) For what values of \(t\) does the linear approximation agree with the exponential expression to within one percent?

Use series to approximate the definite integral to within the indicated accuracy. \(\int_{0}^{0.4} \sqrt{1+x^{4}} d x\) (\(|\) error \(|<5 \times 10^{-6}\))

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