Chapter 11: Problem 13
\(2-20\) Test the series for convergence or divergence. $$ \sum_{n=2}^{\infty}(-1)^{n} \frac{n}{\ln n} $$
Short Answer
Expert verified
The series diverges.
Step by step solution
01
Identify the Series
The given series is $$ \sum_{n=2}^{\infty}(-1)^{n} \frac{n}{\ln n} $$, which is an alternating series of the form $$ \sum_{n=2}^{\infty} (-1)^n a_n $$, where $$ a_n = \frac{n}{\ln n} $$.
02
Apply the Alternating Series Test
For the series $$ \sum (-1)^n a_n $$ to converge, the following conditions must hold:1. The sequence $$ a_n $$ must be positive.2. The sequence $$ a_n $$ must be decreasing: $$ a_{n+1} \leq a_n $$.3. The sequence $$ a_n $$ must converge to 0: $$ \lim_{n \to \infty} a_n = 0 $$.
03
Check if \(a_n\) is Positive
Since \( a_n = \frac{n}{\ln n} \) and both \( n > 0 \) and \( \ln n > 0 \) for \( n \geq 2 \), \( a_n \) is positive for all terms in the series.
04
Check if \(a_n\) is Decreasing
To determine if the sequence \( \frac{n}{\ln n} \) is decreasing, compare \( a_n \) and \( a_{n+1} \):\[ a_n = \frac{n}{\ln n}, \quad a_{n+1} = \frac{n+1}{\ln(n+1)} \]Calculate \( a_{n+1} - a_n \):\[ a_{n+1} - a_n = \frac{n+1}{\ln(n+1)} - \frac{n}{\ln n} \]This expression does not generally evaluate to non-positive, meaning \( a_n \) is not necessarily decreasing for \( n \geq 2 \).
05
Check Limit of \(a_n\) as \(n \to \infty\)
Calculate the limit:\[ \lim_{n \to \infty} \frac{n}{\ln n} \]As \( n \to \infty \), both \( n \) and \( \ln n \) approach infinity, but \( n \) grows much faster than \( \ln n \), leading to:\[ \lim_{n \to \infty} \frac{n}{\ln n} = \infty \]Thus, \( a_n \) does not converge to 0.
06
Conclusion
Since the sequence \( a_n = \frac{n}{\ln n} \) does not satisfy the condition \( \lim_{n \to \infty} a_n = 0 \) required by the Alternating Series Test, the series \( \sum_{n=2}^{\infty}(-1)^{n} \frac{n}{\ln n} \) diverges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Series Convergence
When we talk about the convergence of a series, we primarily want to know if the sum of its infinite terms approaches a specific number as more terms are added. In mathematics, a series like \( \sum_{n=2}^{\infty} a_n \) can be defined as convergent if this total sum reaches a particular finite value. This convergence means that as you add more terms of the series, the sum stops changing significantly and settles around a certain number.
There are different tests available to check the convergence of a series. For alternating series, the Alternating Series Test can be particularly useful. This test states that a series of the form \( \sum (-1)^n a_n \) converges if three conditions are met:
There are different tests available to check the convergence of a series. For alternating series, the Alternating Series Test can be particularly useful. This test states that a series of the form \( \sum (-1)^n a_n \) converges if three conditions are met:
- The sequence \( a_n \), without considering the alternating sign, should be positive.
- The sequence \( a_n \) must be non-increasing with respect to \( n \), which means that each term shouldn't be bigger than the previous one.
- The limit of \( a_n \) as \( n \to \infty \) should equal zero.
Divergence
When discussing divergence in series, it refers to the idea that a series does not settle to a particular value, even as you sum more and more terms. If a series diverges, its overall sum either increases indefinitely, or it behaves erratically without approaching any finite limit.
In our exercise, the alternating series \( \sum_{n=2}^{\infty}(-1)^{n} \frac{n}{\ln n} \) was shown to diverge due to the behavior of its individual terms, \( a_n = \frac{n}{\ln n} \). Even when the terms alternate signs, what's important is the magnitude and limit of \( a_n \):
In our exercise, the alternating series \( \sum_{n=2}^{\infty}(-1)^{n} \frac{n}{\ln n} \) was shown to diverge due to the behavior of its individual terms, \( a_n = \frac{n}{\ln n} \). Even when the terms alternate signs, what's important is the magnitude and limit of \( a_n \):
- The sequence \( a_n \) must approach zero as \( n \) approaches infinity for the alternating series to converge. In this case, \( \lim_{n \to \infty} a_n = \infty \), which fails this crucial condition. As such, the series diverges.
Sequence Analysis
Sequence analysis involves examining the individual terms of a sequence to make determinations about the entire series they form. For the sequence \( a_n = \frac{n}{\ln n} \), understanding its behavior helps know whether the series \( \sum_{n=2}^{\infty} (-1)^n a_n \) converges or diverges.
Analyzing \( a_n \) involves:
Analyzing \( a_n \) involves:
- **Positivity**: Since \( \ln n > 0 \) for \( n \geq 2 \), each \( a_n \) is positive. This satisfies part of the condition for the Alternating Series Test.
- **Monotonic Decrease**: Checking if the sequence is decreasing means evaluating whether \( a_{n+1} \leq a_n \). However, \( a_n = \frac{n}{\ln n} \) does not consistently decrease, particularly as \( n \) becomes large, indicating problems for convergence.
- **Limit to Zero**: Importantly, as \( n \to \infty \), \( a_n \) ideally approaches zero for series convergence. In this exercise, \( a_n \) grows because \( n \) increases much faster than \( \ln n \), violating this key principle.