Chapter 10: Problem 13
Find \(d y / d x\) and \(d^{2} y / d x^{2} .\) For which values of \(t\) is the curve concave upward? $$x=t-e^{t}, \quad y=t+e^{-t}$$
Short Answer
Expert verified
The curve is concave upward for sufficiently large negative t values.
Step by step solution
01
Find dx/dt and dy/dt
Start by differentiating both given functions with respect to the parameter \( t \). For \( x(t) = t - e^t \), differentiate to get \( \frac{dx}{dt} = 1 - e^t \). For \( y(t) = t + e^{-t} \), the derivative is \( \frac{dy}{dt} = 1 - e^{-t} \).
02
Apply Parametric Derivative Formula to find dy/dx
Use the formula for the derivative of parametric equations \( \frac{dy}{dx} = \frac{dy/dt}{dx/dt} \). Substitute the derivatives: \[ \frac{dy}{dx} = \frac{1 - e^{-t}}{1 - e^t} \].
03
Differentiate dy/dx with respect to t to find d²y/dx²
Differentiate \( \frac{dy}{dx} = \frac{1 - e^{-t}}{1 - e^t} \) with respect to \( t \) using the quotient rule: If \( h(t) = \frac{u}{v} \), \( h'(t) = \frac{u'v - uv'}{v^2} \). So, \( \frac{d}{dt}\left(\frac{dy}{dx}\right) = \frac{(e^{-t})(1 - e^t) - (1 - e^{-t})(e^t)}{(1 - e^t)^2} \).
04
Simplify d²y/dx²
Plug in calculated numerator and denominator from the previous step: Simplify \[ \frac{d^2y}{dx^2} = \frac{-e^{-t} - e^t + 1 + e^{2t} - e^{-t} + e^t}{(1 - e^t)^3} \].
05
Analyze Concavity by determining sign of d²y/dx²
The curve is concave upward when \( \frac{d^2y}{dx^2} > 0 \). Set \( -2e^{-t} + e^{2t} + 1 > 0 \) and solve for \( t \) to find the intervals where this inequality holds true.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations represent two variables, typically \(x\) and \(y\), as functions of a third variable, known as the parameter,denoted by \(t\) in most cases. This approach allows for a more flexible description of curves and shapes that move beyond the typical Cartesian representation of \(y=f(x)\). Instead,\(x\) and \(y\) are expressed separately as functions of \(t\).
- Example: Consider \(x(t) = t - e^t\) and \(y(t) = t + e^{-t}\). Here, \(t\) is the parameter that helps define the curve in the coordinate plane.
- The main advantage is the ability to describe a wide range of curves, including those that cannot be expressed as functions in Cartesian forms.
Concavity
Concavity is a property of curves that describes how they "bend". A curve may be concave upward (like a cup) or concave downward (like a hill). To determine the concavity, we need to look at the second derivative,\(\frac{d^2y}{dx^2}\), of a function or parametric curve.
This examination of concavity helps illustrate how the curve changes direction or shape as \(t\) varies,
- If the second derivative is positive, \(\frac{d^2y}{dx^2} > 0\),the curve is concave upward.
- If the second derivative is negative, \(\frac{d^2y}{dx^2} < 0\),the curve is concave downward.
This examination of concavity helps illustrate how the curve changes direction or shape as \(t\) varies,
Second Derivative Test
The second derivative test is a useful tool that provides insight intothe concavity of a parametric curve and can help identify points of inflection.This involves taking the derivative of \(\frac{dy}{dx}\) with respectto the parameter \(t\) using calculus techniques such as the chain rule and quotient rule.
- Start by finding \(\frac{dy}{dx}\) using parametric differentiation methods.
- Next, derive this expression again with respect to \(t\), which involves applying rules like the quotient rule if the expression is in fractional form.
- The result, \(\frac{d^2y}{dx^2}\), will then be analyzed to see where it is greater than zero to conclude where the curve is concave upward.