/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 \(\begin{array}{l}{\text { (a) I... [FREE SOLUTION] | 91Ó°ÊÓ

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\(\begin{array}{l}{\text { (a) If } g(x)=2 x+1 \text { and } h(x)=4 x^{2}+4 x+7, \text { find a function }} \\ {f \text { such that } f \circ g=h . \text { (Think about what operations you }} \\ {\text { would have to perform on the formula for } g \text { to end up with }} \\ {\text { the formula for h.) }} \\ {\text { (b) If } f(x)=3 x+5 \text { and } h(x)=3 x^{2}+3 x+2, \text { find a function }} \\ {g \text { such that } f \circ g=h \text { . }}\end{array}\)

Short Answer

Expert verified
(a) \( f(u) = u^2 + 6 \). (b) \( g(x) = x^2 + x - 1 \).

Step by step solution

01

Understand the Problem (Part a)

We need to find a function \( f \) such that the composition \( f(g(x)) = h(x) \). Here, \( g(x) = 2x + 1 \) and \( h(x) = 4x^2 + 4x + 7 \). Our goal is to determine what needs to be done to \( g(x) \) to get \( h(x) \).
02

Determine Transformation for Part (a)

We want to find \( f \) such that \( f(g(x)) = h(x) \). Given \( g(x) = 2x + 1 \), we see that \( h(x) = 4x^2 + 4x + 7 \) resembles the form \((ax + b)^2\) expansion. Notice that \( (2x + 1)^2 = 4x^2 + 4x + 1 \). It seems that adding 6 to \((2x + 1)^2\) gives \( h(x) \). Hence, \( f(u) = u^2 + 6 \) should work where \( u = g(x) \).
03

Verify Solution for Part (a)

Let's check: if \( f(u) = u^2 + 6 \) and \( u = g(x) = 2x + 1 \), then \( f(g(x)) = (2x + 1)^2 + 6 \). Simplifying, we get:\[(2x + 1)^2 + 6 = 4x^2 + 4x + 1 + 6 = 4x^2 + 4x + 7\],which is equal to \( h(x) \). This confirms our function \( f(u) = u^2 + 6 \) is correct.
04

Understand the Problem (Part b)

Now, we need to find a function \( g \) such that the composition \( f(g(x)) = h(x) \), where \( f(x) = 3x + 5 \) and \( h(x) = 3x^2 + 3x + 2 \). We are looking for a transformation that when \( g(x) \) is substituted into \( f \), we obtain \( h(x) \).
05

Determine Transformation for Part (b)

For \( f(g(x)) = h(x) \), inserting \( g(x) \) into \( f \) should yield \( 3g(x)+5 = 3x^2 + 3x + 2 \). Solving the equation \( 3g(x) = 3x^2 + 3x + 2 - 5 \), simplifying gives \( 3g(x) = 3x^2 + 3x - 3 \). Thus, \( g(x) = x^2 + x - 1 \).
06

Verify Solution for Part (b)

Verify that \( g(x) = x^2 + x - 1 \). Substitute it into \( f \):\[f(g(x)) = f(x^2 + x - 1) = 3(x^2 + x - 1) + 5 = 3x^2 + 3x - 3 + 5 = 3x^2 + 3x + 2\].This is equal to \( h(x) \), confirming \( g(x) = x^2 + x - 1 \) is the correct function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Functions
Polynomial functions are mathematical expressions involving a sum of powers in one or more variables multiplied by coefficients. A polynomial in a single variable, like the ones in our exercise, takes the form:
  • Constant term
  • Linear term
  • Quadratic term
  • Cubic term
The degree of the polynomial is determined by the highest power of the variable in the expression. For instance, the polynomial \( h(x) = 4x^2 + 4x + 7 \) is a quadratic polynomial because its highest exponent is 2. Similarly, for \( f(x) = 3x + 5 \), we see a linear polynomial as the highest power is 1.
Each polynomial serves specific roles based on its structure. Quadratic polynomials are expressed as \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. Understanding these basic elements helps in analyzing and comparing polynomial functions.
Transformation of Functions
Transformation of functions involves changing a function's appearance by applying modifications. These transformations can include shifts, stretches, compressions, or reflections. In the context of our exercise, function composition is a key transformation method. Here, we apply more than one function sequentially to achieve the desired outcome.
To find a function \( f \) resulting in \( h \) through composition with \( g \), i.e., \( f \circ g = h \), we determined that \( h(x) = 4x^2 + 4x + 7 \) almost fits the squared form \((2x+1)^2 = 4x^2 + 4x + 1 \). By adding 6, we fine-tuned it to match \( h(x) \). Hence, \( f(u) = u^2 + 6 \) was formed where \( u = g(x) \).
Similarly, transformations were used in part (b) by engineering \( g \) to fit \( f \circ g \) for \( h(x) \), showing that transforming functions can significantly alter their structure and application.
Verifying Solutions
Verification is a crucial step in mathematical problem-solving to ensure the correctness of solutions. After deriving a function, it’s essential to check its validity by substituting back into the composition equation.
For instance, when we found \( f(u) = u^2 + 6 \) for the function composition in part (a), verifying involved plugging \( g(x) = 2x + 1 \) into the formula for \( f \) and simplifying. We confirmed that \( f(g(x)) = 4x^2 + 4x + 7 \), identical to \( h(x) \).
In part (b), verifying \( g(x) = x^2 + x - 1 \) was achieved by replacing \( g(x) \) in \( f \) and checking if it equates to \( h(x) = 3x^2 + 3x + 2 \). Verifying solutions by retracing steps affirms accuracy and strengthens understanding in mathematical exercises.

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