Chapter 1: Problem 48
\(45-50\) Find an expression for the function whose graph is the given curve. $$\begin{array}{l}{\text {The top half of the circle } x^{2}+(y-2)^{2}=4}\end{array}$$
Short Answer
Expert verified
The expression for the function is \(y = 2 + \sqrt{4 - x^2}\).
Step by step solution
01
Identify the Circle's Equation
We are given the equation \(x^2 + (y-2)^2 = 4\), which represents a circle centered at \((0, 2)\) with a radius of 2.
02
Solve for y
To find the expression for the top half of the circle, we need to solve the circle's equation for \(y\) and select the positive branch. Start by expanding \((y-2)^2\) to:\(x^2 + y^2 - 4y + 4 = 4\).Simplify it to:\(x^2 + y^2 = 4y\).Now solve for \(y\):\(y^2 - 4y = -x^2\).To solve this, use the quadratic formula \(y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 1\), \(b = -4\), and \(c = -x^2\).
03
Apply the Quadratic Formula
Substitute the values of \(a\), \(b\), and \(c\) into the quadratic formula:\[y = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(1)(-x^2)}}{2(1)}\]\[y = \frac{4 \pm \sqrt{16 + 4x^2}}{2}\]\[y = \frac{4 \pm \sqrt{4(x^2 + 4)}}{2}\]Take the positive root because it represents the top half:\[y = \frac{4 + \sqrt{4(x^2 + 4)}}{2}\]
04
Simplify the Expression for y
Simplify the expression further:\[y = \frac{4 + 2\sqrt{x^2 + 4}}{2}\]\[y = 2 + \sqrt{x^2 + 4}\]Since we are looking for the top half of the circle, \(y\) is expressed as \(y = 2 + \sqrt{4 - x^2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graph of a Function
Understanding the graph of a function is essential when analyzing mathematical equations, especially in geometry. In this context, a function graph visually represents the set of ordered pairs given by a function equation in a coordinate system. The graph of a circle is particularly interesting because it does not represent a function unless you restrict it to one half. By isolating portions of a circle, like the top half, we can deal with simpler expressions that embody specific characteristics—here, the equation for a circle becomes more straightforward.
- For a complete circle described by the equation \(x^2 + (y-2)^2 = 4\), its graph is a perfect circle with center \(0, 2\) and radius 2.
- By focusing on the top half, we're looking at one branch of the solutions for the variable \(y\).
- The goal: express the relationship between \(x\) and \(y\) such that only this upper part appears on the graph.
Quadratic Formula
The quadratic formula is a vital tool in algebra for solving quadratic equations of the form \(ax^2 + bx + c = 0\). It finds the roots of the equation—where the graph of the quadratic intersects the x-axis. In our case, we used the quadratic formula to help solve for \(y\) in the circle's equation.
- The general formula is given by \[y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
- Here, \(a = 1\), \(b = -4\), and \(c = -x^2\).
- We substitute these into the formula to get the solutions for \(y\).
Solving for y
Finding \(y\) in an equation is fundamental to expressing it as a function of \(x\). Solving for \(y\) generally involves isolating \(y\) on one side of the equation.
- Our goal is to express the curve equation \(x^2 + (y-2)^2 = 4\) in terms of \(y\).
- By manipulating the equation, removing constants, and rearranging terms, we move to an explicitly solved form for \(y\).
- This is necessary for using and applying the quadratic formula further.
Simplifying Expressions
Simplifying mathematical expressions means transforming them into a format that's easier to understand while retaining the same value. It is everywhere in math, from basic arithmetic to complex calculus.
- Start by cancelling terms, factoring expressions, and reducing complexity whenever possible.
- In our case, simplifying the polynomial expression we obtained from the quadratic formula gives us \(y = 2 + \sqrt{x^2 + 4}\).
- This expression clearly shows the top half of our circle's function.