/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Evaluate the following integrals... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following integrals. $$\int 10 \tan ^{9} x \sec ^{2} x d x$$

Short Answer

Expert verified
In this exercise, we used the trigonometric identity \(\tan^2 x = \sec^2 x - 1\) and substitution to simplify the given integral \(\int 10\tan^{9}x\sec^{2}x dx\). After rewriting the function and performing the substitution, we were able to evaluate the integral and find the final answer as \(\tan ^{10} x + C\).

Step by step solution

01

In this exercise, we will be using the trigonometric identity relating the tangent and secant functions: \(\tan^{2} x = \sec^{2} x - 1\). Additionally, remember the derivative of the tangent function is the square of the secant function: \((\tan x)' = \sec^{2} x\). #Step 2: Rewrite the integral using trigonometric identity#

Since our given function is \(\int 10\tan^{9}x\sec^{2}x dx\), we will first rewrite the tangent function to the power of 8 and leave the other \(\tan x\) in the expression: \(\int 10(\tan^{8}x)\tan x \sec^{2}x dx\). #Step 3: Perform substitution#
02

Let's perform a substitution to simplify the expression. Let \(u = \tan x\), so \(\frac{du}{dx} = \sec^{2} x\). Now, the integral becomes: \(\int 10u^{8}u\left(\frac{du}{\sec^{2} x}\right)\). #Step 4: Cancel the secants#

Now, we can cancel out the \(\sec^2 x\) in our integral: \(\int 10u^{8}u du = \int 10u^9 du\). #Step 5: Evaluate the integral#
03

Evaluating the integral with respect to \(u\) yields: \( \frac{10}{10} u^{10} + C = u^{10} + C \), where \(C\) is the constant of integration. #Step 6: Substitute back to x and put tangent back in#

Since \(u = \tan x\), our final answer in terms of \(x\) becomes: \( \tan ^{10} x + C \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Substitution
Trigonometric substitution is a technique used in calculus to simplify integrals. It involves replacing a part of the integral with a trigonometric function to make the integration process easier. This method is particularly useful when dealing with integrals that involve square roots or quadratic expressions.

In the given problem, we use trigonometric substitution to simplify the integral of \(10 \tan^9 x \sec^2 x\). The process begins by recognizing patterns that can be simplified using a simple substitution. Here, we set \(u = \tan x\) because the derivative of \(\tan x\) is \(\sec^2 x\), matching the remaining part of the integrand. This effectively transforms the problem into a polynomial form which is much easier to integrate.

Once we substitute \(u = \tan x\), and replace \(dx\) with \(du/\sec^2 x\), the integral becomes \(\int 10u^9 du\). This is a typical polynomial integration problem, straightforward to solve using the power rule of integration.
Trigonometric Identities
Trigonometric identities are equations that relate various trigonometric functions to each other. They are incredibly useful in calculus, especially for simplifying and integrating expressions. One key identity used in the problem above is \(\tan^2 x = \sec^2 x - 1\). This identity helps in rewriting expressions in a more manageable form for calculus operations.

This identity assists in decomposing higher powers of tangent into products of secant functions and lower powers of tangent. In the exercise solved, using \(\tan x\) and \(\sec^2 x\) together is beneficial because it matches the derivatives and integrals in one coherent expression, ultimately simplifying substitution.

Utilizing these identities is critical for transforming initial complex expressions into simpler ones, allowing you to apply basic calculus operations. Recognizing these identities is often the key to straightforward integration or differentiating processes.
Indefinite Integrals
Indefinite integrals, or antiderivatives, represent a family of functions whose derivative gives the original function in the integrand. The result is denoted by an integral sign without limits and includes a constant of integration, \(C\), since derivatives of constants are zero and could be any real number.

For the problem \(\int 10 \tan^9 x \sec^2 x dx\), once simplified using substitution, you get \(\int 10u^9 du\). By applying the power rule, which states \(\int u^n du = \frac{u^{n+1}}{n+1} + C\), the integral becomes \(u^{10} + C\).

Finally, substituting \(u = \tan x\) back into the result yields \(\tan^{10} x + C\). This final expression represents the indefinite integral of the original function. Understanding how substitution works allows tackling these integrals more systematically, converting more complex expressions into simpler forms for integration.

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