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What trigonometric identity is useful in evaluating \(\int \sin ^{2} x d x ?\)

Short Answer

Expert verified
Answer: The trigonometric identity that is useful in evaluating the integral \(\int \sin ^{2} x dx\) is \(\sin^2(x) = \frac{1-\cos(2x)}{2}\).

Step by step solution

01

Identify the appropriate trigonometric identity

To simplify the expression and make the integration process easier, we need to express \(\sin^2 x\) in terms of a function that is easier to integrate. We can do this by using the trigonometric identity for double angle of cosine, which is given by: $$\cos(2x) = 1 - 2\sin^2(x)$$ In this case, we can isolate \(\sin^2(x)\) as follows: $$\sin^2(x) = \frac{1-\cos(2x)}{2}$$
02

Substitute the identity into the integral

Now that we have expressed \(\sin^2(x)\) in terms of an easier function to integrate, we can substitute the trigonometric identity into the integral: $$\int \sin^2(x) dx = \int \frac{1 - \cos(2x)}{2} dx$$
03

Simplify the integral

Now, we break the integral into smaller components: $$\int \frac{1 - \cos(2x)}{2} dx = \frac{1}{2}\int 1 dx - \frac{1}{2} \int \cos(2x) dx$$
04

Integrate the simplified expressions

Next, we integrate each component: $$\frac{1}{2}\int 1 dx = \frac{1}{2}x$$ $$\frac{1}{2} \int \cos(2x) dx = \frac{1}{4} \sin(2x)$$
05

Combine the results and add the integration constant

Combine the results of the two integrations and add the integration constant \(C\): $$\int \sin^2(x) dx = \frac{1}{2}x - \frac{1}{4}\sin(2x) + C$$ So, the trigonometric identity that is useful in evaluating the integral \(\int \sin ^{2} x dx\) is \(\sin^2(x) = \frac{1-\cos(2x)}{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Double Angle Formula
The double angle formula is a powerful trigonometric identity that simplifies the integration of functions like the square of sine, in our case, \(\sin^2(x)\). This formula helps transform complex trigonometric expressions into simpler ones by rewriting them in terms of double angles. In this context, the double angle formula for cosine states:
  • \(\cos(2x) = 1 - 2\sin^2(x)\)
Here, you can solve for \(\sin^2(x)\), thereby isolating it: \[\sin^2(x) = \frac{1-\cos(2x)}{2}\]This transformation converts \(\sin^2(x)\) into a form that is much easier to integrate, by reducing the quadratic sine function into a linear cosine function. This is invaluable when working with integrals involving squared trigonometric functions.
Integration
Integration is a fundamental concept in calculus, where the goal is to find the antiderivative, or integral, of a function. The process of integration is essentially the reverse operation of differentiation. In our example, integrating \(\sin^2(x)\) involves first using a trigonometric identity to convert it into a simpler function: \[\int \sin^2(x) \ dx = \int \frac{1 - \cos(2x)}{2} \ dx\]After substituting the simpler expression into the integral, the integration process itself can be simplified into separate integrals:
  • \(\int \frac{1}{2} \cdot 1 \ dx\)
  • \(- \int \frac{1}{2} \cdot \cos(2x) \ dx\)
Each part can be integrated independently, allowing for a direct approach to find the integral of trigonometric functions, leading to the solution:
  • \(\frac{1}{2}x\) for the constant part
  • \(- \frac{1}{4}\sin(2x)\) for the double-angle cosine part
Thus, integration requires breaking down complex functions into known formats using trigonometric identities to simplify calculation.
Trigonometric Integrals
Trigonometric integrals involve integrating functions that contain trigonometric expressions, like \(\sin(x)\), \(\cos(x)\), and their squares or powers. These integrals often appear in calculus problems involving cyclic or harmonic motion, waves, and oscillations. To solve these integrals, one often employs trigonometric identities like the double angle formula to simplify the function into an integrable form. For example, integrating \(\sin^2(x)\) directly is difficult, but by using the double angle identity:
  • \(\sin^2(x) = \frac{1-\cos(2x)}{2}\)
The problem becomes easier to manage. This simplification helps manage complex expressions into integrals that are much more straightforward, often using:
  • Integration by parts or substitution techniques.
  • Recognizing patterns of standard integrals.
In summary, mastering trigonometric integrals involves an understanding of key identities and strategic transformations to cleanly evaluate the area under trigonometric curves.

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Most popular questions from this chapter

Estimating error Refer to Theorem 8.1 in the following exercises. Let \(f(x)=\sqrt{x^{3}+1}\) a. Find a Midpoint Rule approximation to \(\int_{1}^{6} \sqrt{x^{3}+1} d x\) using \(n=50\) subintervals. b. Calculate \(f^{\prime \prime}(x)\) c. Use the fact that \(f^{\text {- }}\) is decreasing and positive on [1,6] to show that \(\left|f^{*}(x)\right| \leq 15 /(8 \sqrt{2})\) on [1,6] d. Use Theorem 8.1 to find an upper bound on the absolute error in the estimate found in part (a).

An integrand with trigonometric functions in the numerator and denominator can often be converted to a rational function using the substitution \(u=\tan (x / 2)\) or, equivalently, \(x=2 \tan ^{-1} u .\) The following relations are used in making this change of variables. $$A: d x=\frac{2}{1+u^{2}} d u \quad B: \sin x=\frac{2 u}{1+u^{2}} \quad C: \cos x=\frac{1-u^{2}}{1+u^{2}}$$ $$\text { Evaluate } \int \frac{d x}{1+\sin x+\cos x}$$.

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. a. Suppose \(\int_{a}^{b} f(x) d x\) is approximated with Simpson's Rule using \(n=18\) subintervals, where \(\left|f^{(4)}(x)\right| \leq 1\) on \([a, b]\) The absolute error \(E_{S}\) in approximating the integral satisfies \(E_{s} \leq \frac{(\Delta x)^{5}}{10}\) 1\. If the number of subintervals used in the Midpoint Rule is increased by a factor of \(3,\) the error is expected to decrease by a factor of \(8 .\) c. If the number of subintervals used in the Trapezoid Rule is increased by a factor of \(4,\) the error is expected to decrease by a factor of \(16 .\)

A powerful tool in solving problems in engineering and physics is the Laplace transform. Given a function \(f(t),\) the Laplace transform is a new function \(F(s)\) defined by $$F(s)=\int_{0}^{\infty} e^{-s t} f(t) d t$$ where we assume s is a positive real number. For example, to find the Laplace transform of \(f(t)=e^{-t},\) the following improper integral is evaluated using integration by parts: $$F(s)=\int_{0}^{\infty} e^{-s t} e^{-t} d t=\int_{0}^{\infty} e^{-(s+1) t} d t=\frac{1}{s+1}$$ Verify the following Laplace transforms, where a is a real number. $$f(t)=\sin a t \rightarrow F(s)=\frac{a}{s^{2}+a^{2}}$$

Show that with the change of variables \(u=\sqrt{\tan x}\) the integral \(\int \sqrt{\tan x} d x\) can be converted to an integral amenable to partial fractions. Evaluate \(\int_{0}^{\pi / 4} \sqrt{\tan x} d x\).

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