Chapter 7: Problem 4
Explain the meaning of half-life.
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 7: Problem 4
Explain the meaning of half-life.
These are the key concepts you need to understand to accurately answer the question.
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Catenary arch The portion of the curve \(y=\frac{17}{15}-\cosh x\) that lies above the \(x\) -axis forms a catenary arch. Find the average height of the arch above the \(x\) -axis.
Energy consumption On the first day of the year \((t=0),\) a city uses electricity at a rate of \(2000 \mathrm{MW}\). That rate is projected to increase at a rate of \(1.3 \%\) per year. a. Based on these figures, find an exponential growth function for the power (rate of electricity use) for the city. b. Find the total energy (in MW-yr) used by the city over four full years beginning at \(t=0\) c. Find a function that gives the total energy used (in MW-yr) between \(t=0\) and any future time \(t>0\)
Equivalent growth functions The same exponential growth function can be written in the forms \(y(t)=y_{0} e^{t f}, y(t)=y_{0}(1+r)^{t}\) and \(y(t)=y_{0} 2^{1 / T_{2}}\). Write \(k\) as a function of \(r, r\) as a function of \(T_{2}\) and \(T_{2}\) as a function of \(k .\)
Designing exponential growth functions Complete the following steps for the given situation. a. Find the rate constant k and use it to devise an exponential growth function that fits the given data. b. Answer the accompanying question. Cell growth The number of cells in a tumor doubles every 6 weeks starting with 8 cells. After how many weeks does the tumor have 1500 cells?
Atmospheric pressure The pressure of Earth's atmosphere at sea level is approximately 1000 millibars and decreases exponentially with elevation. At an elevation of \(30,000 \mathrm{ft}\) (approximately the altitude of Mt. Everest), the pressure is one-third the sea-level pressure. At what elevation is the pressure half the sea-level pressure? At what elevation is it \(1 \%\) of the sea-level pressure?
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