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Are length calculations Find the arc length of the following curves on the given interval. \(y=-8 x-3\) on [-2,6] (Use calculus.)

Short Answer

Expert verified
Answer: The arc length of the curve \(y=-8x-3\) on the interval \([-2, 6]\) is \(8\sqrt{65}\).

Step by step solution

01

Understand the arc length formula

The arc length formula for a function \(y=f(x)\), from \(x=a\) to \(x=b\), is given by: $$L = \int_a^b \sqrt{1 + (f'(x))^2} \ dx$$ Where \(L\) is the arc length, \(f'(x)\) is the derivative of the function \(f(x)\), and the integral is evaluated over the interval \([a, b]\).
02

Find the derivative of the function

Now lets find the derivative of the function \(y=-8x-3\). Using the power rule, we get: $$\frac{dy}{dx} = -8$$
03

Apply the arc length formula

We will now apply the arc length formula. First, we need to find the expression inside the square root: $$(f'(x))^2 = (-8)^2 = 64$$ So the expression becomes: $$L = \int_{-2}^6 \sqrt{1 + 64} \ dx$$ Since the expression inside the square root is a constant (\(65\)), we can simplify the integral: $$L = \sqrt{65} \int_{-2}^6 dx$$
04

Evaluate the integral

Now we will evaluate the integral. The integral of \(dx\) is simply \(x\), so we get: $$L = \sqrt{65} [x]_{-2}^6$$
05

Calculate the arc length

Finally, we will calculate the arc length by plugging in the limits of integration: $$L = \sqrt{65} (6 - (-2)) = \sqrt{65} \cdot 8$$ Therefore, the arc length of the curve \(y=-8x-3\) on the interval \([-2, 6]\) is: $$L = 8\sqrt{65}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a branch of mathematics that deals with the study of change and motion. It is divided into two main areas: differential calculus and integral calculus. Differential calculus focuses on the concept of a derivative, which represents the rate of change of a function. This is useful in various fields, including physics, engineering, and economics, to determine how a variable changes over time or responds to other changing quantities.
Integral calculus, on the other hand, centers on the concept of the integral. This is used to calculate areas under curves and the total accumulation of quantities, such as distance traveled over time.
When calculating arc lengths, calculus allows us to precisely measure the length of curved lines, which would otherwise be very difficult without this mathematical framework. This is where both derivatives and integration play crucial roles.
Derivatives
Derivatives are a fundamental concept in calculus that measure how a function changes as its input changes. In simpler terms, a derivative can be thought of as the 'slope' of a curve at a given point. For the function given in the original exercise, the derivative is important for calculating the arc length of a curve.
  • The derivative of a function, denoted as \(f'(x)\), reveals important details about the function's behavior.
  • For example, if a function is represented as \(y = -8x - 3\), the derivative \(f'(x) = -8\) indicates a constant slope.
The derivative can show how steep or flat the curve is or in which direction it slopes. This is crucial when investigating arc lengths, as it helps in shaping the curve's behavior along an interval. A constant derivative simplifies calculations, as there is no need to alter it across the different parts of the interval when determining arc length.
Integration
Integration is the process of finding the integral of a function, which can be thought of as adding up many small pieces to find a whole. In the context of arc length calculations, integration is used to add up infinitesimally small line segments along the curve to find the total length. For the arc length formula, integration is performed over a specific interval, such as [-2, 6] as in the original exercise.
  • The integral needed for arc length is given by \(L = \int_a^b \sqrt{1 + (f'(x))^2} \, dx\).
  • In the exercise, the constant integrand \(\sqrt{65}\) is simplified, making the integration straightforward.
Integration captures the cumulative total along a path, whether it turns, curves, or is straight. By using the calculated definite integral, a precise measure of the arc length is determined, capturing all small changes along the curve within the specified interval.

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Most popular questions from this chapter

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