/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 A glass has circular cross secti... [FREE SOLUTION] | 91影视

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A glass has circular cross sections that taper (linearly) from a radius of 5 cm at the top of the glass to a radius of 4 cm at the bottom. The glass is 15 cm high and full of orange juice. How much work is required to drink all the juice through a straw if your mouth is 5 cm above the top of the glass? Assume the density of orange juice equals the density of water.

Short Answer

Expert verified
Answer: The work required to drink all the orange juice through a straw is approximately 59,469.75 erg.

Step by step solution

01

Calculate the volume of orange juice

To calculate the volume of the orange juice, we first need to find the volume of the conical shape formed by the glass. The volume of a cone is given by the formula: \(V = \dfrac{1}{3}蟺r^2h\) For our glass, the height (h) is given as 15 cm. However, since the radius of the glass tapers linearly (r) from 5 cm at the top to 4 cm at the bottom, we need to find the average radius to calculate the volume: \(average\;radius = \dfrac{top\;radius + bottom\;radius}{2} = \dfrac{5 + 4}{2} = 4.5\; cm\) Now we can calculate the volume of the orange juice: \(V = \dfrac{1}{3}蟺(4.5)^2(15) = 303.107\; cm^3\)
02

Calculate the force required to lift the orange juice

Next, we need to calculate the force needed to lift the orange juice to the mouth. The force can be calculated by multiplying the mass (m) of the juice with the acceleration due to gravity (g): \(F = m \times g\) First, we need to find the mass of the orange juice. The mass can be found by multiplying the volume of the juice (V) with the density (蟻) of orange juice (which is equal to the density of water): \(mass = density \times volume = 蟻 \times V\) Since the density of water is 1 g/cm鲁, the mass of the orange juice in grams is equal to the volume in cm鲁: \(mass = 303.107\; grams\) Now we can calculate the force required to lift the juice: \(F = 303.107 \times 9.81= 2,973.49\; dyne\)
03

Calculate the work done

Finally, we can calculate the work done by multiplying the force (F) with the total displacement (d), which includes the height of the glass and the extra 5 cm above the top of the glass: \(work = F \times d == 2,973.49 \times (15 + 5) = 2,973.49 \times 20 = 59,469.75\; erg\) So, the work required to drink all the orange juice through a straw is approximately 59,469.75 erg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus in Physics
Calculus plays a fundamental role in physics, as it provides the tools for modeling and solving problems that involve changes and motion. In this exercise, calculus allows us to determine the work required to drink juice through a straw. The process encompasses finding the volume of juice, the gravitational force acting upon it, and ultimately the work done in lifting the juice from the glass to the mouth.

In physics, work is defined as the product of force and displacement, both of which often depend on varying conditions. Calculus helps in integrating these variable factors over a particular path or interval to compute the total work done. In our juice-drinking scenario, calculus isn't explicitly shown but is inherently used to establish the formulas applied for volume, force, and work.
Volume of a Cone
Understanding the volume of three-dimensional shapes is crucial in a variety of contexts, including physics. The volume of a cone 鈥 a common geometric shape that tapers smoothly from a flat base to a point 鈥 is derived using the formula \( V = \frac{1}{3}\pi r^2 h \), where \( r \) is the radius of the base, and \( h \) is the height of the cone.

Applying Cone Volume to the Juice Glass

For a conical glass, like the one in our exercise, these two measurements are key. However, if the cone is not perfect and its radius changes, as with the glass that tapers from top to bottom, we calculate the volume by considering the average radius. This considers the linear change in dimension, giving a more accurate estimate of the juice volume.
Density and Mass
The concepts of density and mass are closely interlinked in physics and engineering. Density is defined as the mass per unit volume of a substance and is typically noted by the symbol \( \rho \).

Why Density Matters in Our Calculation

To find how much work is necessary to drink the juice, we must know the mass of the juice. Given the density of a substance, like the orange juice, which is equivalent to water's density (\rho = 1 \text{g/cm}^3), we can retrieve the mass by multiplying this density by the juice's volume. As in our exercise, once we have the volume of the cone-shaped glass, we can easily calculate the juice's mass, crucial for determining the work done to drink it.
Work-Energy Principle
The work-energy principle is a powerful concept in physics that relates the work done on an object to its energy. It is rooted in the idea that work done by forces on an object results in a change in its energy 鈥 typically kinetic or potential energy.

Work Done to Drink Juice

In the context of drinking juice through a straw, we use the work-energy principle to quantify the energy transferred by the force required to lift the juice from the glass up to the mouth. Here, we calculate work by considering the force needed to overcome Earth's gravity, multiplied by the vertical displacement of the juice.

The force is the product of mass and gravitational acceleration (\( F = m \times g \) ), and work is force applied over distance \( W = F \times d \) ). By understanding how this principle operates, students can unravel the physics behind everyday activities, such as sipping a beverage, and appreciate the interplay of fundamental physical laws.

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Most popular questions from this chapter

Leaky cement bucket A 350 kg-bucket containing \(4650 \mathrm{kg}\) of cement is resting on the ground when a crane begins lifting it at a constant rate of \(5 \mathrm{m} / \mathrm{min.}\) As the crane raises the bucket, cement leaks out of the bucket at a constant rate of \(100 \mathrm{kg} / \mathrm{min.}\) How much work is required to lift the bucket a distance of \(30 \mathrm{m}\) if we ignore the weight of the crane cable attached to the bucket?

At noon \((t=0)\). Alicia starts running along a long straight road at \(4 \mathrm{mi} / \mathrm{hr}\). Her velocity decreases according to the function \(v(t)=\frac{4}{t+1},\) for \(t \geq 0 .\) At noon, Boris also starts running along the same road with a 2 -mi head start on Alicia: his velocity is given by \(u(t)=\frac{2}{t+1},\) for \(t \geq 0 .\) Assume \(t\) is measured in hours. a. Find the position functions for Alicia and Boris, where \(s=0\) corresponds to Alicia's starting point. b. When, if ever, does Alicia overtake Boris?

Surface-area-to-volume ratio (SAV) In the design of solid objects (both artificial and natural), the ratio of the surface area to the volume of the object is important. Animals typically generate heat at a rate proportional to their volume and lose heat at a rate proportional to their surface area. Therefore, animals with a low SAV ratio tend to retain heat, whereas animals with a high SAV ratio (such as children and hummingbirds) lose heat relatively quickly. a. What is the SAV ratio of a cube with side lengths \(R ?\) b. What is the SAV ratio of a ball with radius \(R ?\) c. Use the result of Exercise 38 to find the SAV ratio of an ellipsoid whose long axis has length \(2 R \sqrt[3]{4},\) for \(R \geq 1\) and whose other two axes have half the length of the long axis. (This scaling is used so that, for a given value of \(R,\) the volumes of the ellipsoid and the ball of radius \(R\) are equal.) The volume of a general ellipsoid is \(V=\frac{4 \pi}{3} A B C,\) where the axes have lengths \(2 A, 2 B,\) and \(2 C .\) d. Graph the SAV ratio of the ball of radius \(R \geq 1\) as a function of \(R\) (part (b)) and graph the SAV ratio of the ellipsoid described in part (c) on the same set of axes. Which object has the smaller SAV ratio? e. Among all ellipsoids of a fixed volume, which one would you choose for the shape of an animal if the goal were to minimize heat loss?

Mass of one-dimensional objects Find the mass of the following thin bars with the given density function. $$\rho(x)=5 e^{-2 x}, \text { for } 0 \leq x \leq 4$$

Work from force How much work is required to move an object from \(x=0\) to \(x=3\) (measured in meters) in the presence of a force (in N) given by \(F(x)=2 x\) acting along the \(x\) -axis?

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