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Rank the functions \(x^{3},\) ln \(x, x^{x},\) and \(2^{x}\) in order of increasing growth rates as \(x \rightarrow \infty\)

Short Answer

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Question: Rank the functions \(x^3,\) ln \(x,\) \(x^x,\) and \(2^x\) in order of increasing growth rates as \(x \rightarrow \infty\). Answer: ln \(x, x^3, 2^x,\) and \(x^x\).

Step by step solution

01

Consider the first pair of functions \(x^3\) and ln \(x\)

For very large values of \(x\), \(x^3\) will grow faster than ln \(x\). This is because \(x^3\) has an exponential growth rate, while ln \(x\) has a logarithmic growth rate. You can also visualize this by graphing the functions and observing their slopes for large values of \(x\). Thus, ln \(x\) has a smaller growth rate compared to \(x^3\).
02

Consider the second pair of functions \(x^3\) and \(x^x\)

Now let's compare \(x^3\) and \(x^x\). For very large values of \(x\), \(x^x\) will grow faster than \(x^3\), since both of them are exponential functions, but \(x^x\) has a much higher power than \(x^3\). Thus, \(x^3\) has a smaller growth rate compared to \(x^x\).
03

Consider the third pair of functions \(x^3\) and \(2^x\)

Comparing \(x^3\) and \(2^x\), it is clear that the exponential function \(2^x\) will grow faster than the polynomial function \(x^3\) as \(x \rightarrow \infty\). Thus, \(x^3\) has a smaller growth rate compared to \(2^x\).
04

Consider the fourth pair of functions \(x^x\) and \(2^x\)

The next comparison is between \(x^x\) and \(2^x\). As \(x \rightarrow \infty\), \(x^x\) will grow much faster than \(2^x\), since it has an \(x\) in its power, which increases with increasing \(x\). Therefore, \(2^x\) has a smaller growth rate compared to \(x^x\).
05

Order the functions in increasing growth rates

From the analysis above, we can order the functions in increasing growth rates as follows: 1. ln \(x\) (smallest growth rate) 2. \(x^3\) 3. \(2^x\) 4. \(x^x\) (highest growth rate) So, the order of increasing growth rates as \(x \rightarrow \infty\) is ln \(x, x^3, 2^x,\) and \(x^x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth
A concept crucial to understanding various functions is exponential growth. Exponential functions, like \(2^x\) or \(x^x\), have the characteristic that their rate of growth continuously accelerates as the value of \(x\) increases. In simpler terms, as the value of \(x\) gets bigger, the output of these functions gets much larger, much faster. This is different from polynomial growth, such as seen with \(x^3\), where the growth rate is significant but does not accelerate at the same pace.

One way to recognize an exponential function is by its format; it typically appears with a constant base raised to a variable exponent, like \(2^x\). However, functions like \(x^x\) also exhibit exponential behavior, as the base \(x\) itself grows alongside the exponent. Exponential functions play a huge role in various fields, including biology, finance, and computer science, due to their rapid growth properties.
Logarithmic Growth
Conversely, logarithmic growth, as seen in functions like \(\ln(x)\), showcases a much more subdued growth pattern. Logarithmic functions increase as \(x\) gets larger, but the rate of this increase slows down over time. This means that every additional increase in \(x\) results in a smaller increase in the function's value compared to before.

Logarithmic functions serve as the inverse of exponential functions. While the exponential function might represent the rapid spread of a virus, the corresponding logarithmic function could represent the rate at which we can expect to find new cases, slowing as the population of susceptible individuals decreases. In mathematics, the logarithmic growth curve approaches infinity more slowly than any polynomial function, cementing its position as a marker for slow, decelerating growth.
Comparing Functions
Comparing different types of functions, such as exponential, logarithmic, and polynomial functions, is vital for understanding their behaviors and growth rates, especially as \(x \rightarrow \infty\). When \(x\) is very large, exponential functions like \(x^x\) will vastly outgrow polynomial functions like \(x^3\), which in turn surpass logarithmic functions like \(ln(x)\) in growth speed. To compare functions effectively, one can consider their algebraic properties, create graphs for a visual comparison, or use limits as \(x\) approaches large numbers.

To facilitate an accurate comparison, we often look at the end behavior of the functions, as they stretch towards infinity. This perspective helps predict future values and understand the long-term implications in practical scenarios, from financial forecasts to scientific predictions.
Limits at Infinity
Limits at infinity are used to describe the behavior of functions as the input \(x\) grows without bound. When analyzing limits at infinity, we look at whether the function approaches a particular value (finite or infinite), or if the growth is unbounded. For example, the limit at infinity for \(2^x\) is infinity itself, reflecting its ceaseless exponential growth. On the other hand, polynomial functions also tend towards infinity, albeit at a slower rate compared to exponential ones.

The concept of limits at infinity is not just a theoretical construct but is key in fields such as calculus to solve problems related to growth and decay over time. By understanding the end behavior of a function through its limits, we gain insight into its long-term trends and can apply this knowledge to real-world phenomena.

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Most popular questions from this chapter

Slant height and cones Among all right circular cones with a slant height of \(3,\) what are the dimensions (radius and height) that maximize the volume of the cone? The slant height of a cone is the distance from the outer edge of the base to the vertex.

Interpret the Mean Value Theorem when it is applied to any linear function.

Consider the general cubic polynomial \(f(x)=x^{3}+a x^{2}+b x+c,\) where \(a, b,\) and \(c\) are real numbers. a. Prove that \(f\) has exactly one local maximum and one local minimum provided \(a^{2}>3 b\) b. Prove that \(f\) has no extreme values if \(a^{2}<3 b\)

Generalized Mean Value Theorem Suppose the functions \(f\) and g are continuous on \([a, b]\) and differentiable on \((a, b),\) where \(g(a) \neq g(b) .\) Then there is a point \(c\) in \((a, b)\) at which $$\frac{f(b)-f(a)}{g(b)-g(a)}=\frac{f^{\prime}(c)}{g^{\prime}(c)}$$ This result is known as the Generalized (or Cauchy's) Mean Value Theorem. a. If \(g(x)=x,\) then show that the Generalized Mean Value Theorem reduces to the Mean Value Theorem. b. Suppose \(f(x)=x^{2}-1, g(x)=4 x+2,\) and \([a, b]=[0,1]\) Find a value of \(c\) satisfying the Generalized Mean Value Theorein.

Do dogs know calculus? A mathematician stands on a beach with his dog at point \(A\). He throws a tennis ball so that it hits the water at point \(B\). The dog, wanting to get to the tennis ball as quickly as possible, runs along the straight beach line to point \(D\) and then swims from point \(D\) to point \(B\) to retrieve his ball. Assume \(C\) is the point on the edge of the beach closest to the tennis ball (see figure). a. Assume the dog runs at speed \(r\) and swims at speed \(s,\) where \(r>s\) and both are measured in meters per second. Also assume the lengths of \(B C, C D,\) and \(A C\) are \(x, y,\) and \(z,\) respectively. Find a function \(T(y)\) representing the total time it takes for the dog to get to the ball. b. Verify that the value of \(y\) that minimizes the time it takes to $$\text { retrieve the ball is } y=\frac{x}{\sqrt{r / s+1} \sqrt{r / s-1}}$$ c. If the dog runs at \(8 \mathrm{m} / \mathrm{s}\) and swims at \(1 \mathrm{m} / \mathrm{s}\), what ratio \(y / x\) produces the fastest retrieving time? d. A dog named Elvis who runs at \(6.4 \mathrm{m} / \mathrm{s}\) and swims at \(0.910 \mathrm{m} / \mathrm{s}\) was found to use an average ratio of \(y / x\) of 0.144 to retrieve his ball. Does Elvis appear to know calculus? (Source: T.Pennings, Do Dogs Know Calculus? The College Mathematics Journal, \(34,3,\) May 2003 )

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