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Determining the unknown constant Let $$ f(x)=\left\\{\begin{array}{ll} 2 x^{2} & \text { if } x \leq 1 \\ a x-2 & \text { if } x>1 \end{array}\right. $$ Determine a value of \(a\) (if possible) for which \(f^{\prime}\) is continuous at \(x=1\)

Short Answer

Expert verified
Solution: The value of "a" that makes the derivative of the function continuous at x=1 is 4.

Step by step solution

01

Differentiate both parts of the function with respect to x

To make sure the derivative of the function is continuous at x=1, we have to first find the derivatives of both parts of the function. For the first part, \(2x^2\): $$\frac{d}{dx}(2x^2) = 4x$$ For the second part, \(ax-2\): $$\frac{d}{dx}(ax-2) = a$$ Now, we have the derivatives of both parts: $$f'(x) = \left\\{\begin{array}{ll} 4x & \text { if } x \leq 1 \\\ a & \text { if } x>1 \end{array}\right.$$
02

Evaluate both derivatives at x = 1

Now let's evaluate both derivatives at x = 1: For the first part, \(4x\) (when \(x \leq 1\)): $$f'(1) = 4(1)=4$$ For the second part, \(a\) (when \(x > 1\)): $$f'(1) = a$$
03

Set the values equal to each other and solve for a

Since we want the derivative to be continuous at \(x=1\), we should have the same values for both expressions at x=1. Therefore, set the values equal to each other: $$4 = a$$ The value of "a" that makes the derivative of the function continuous at x=1 is 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piecewise Function Differentiation
When it comes to understanding calculus, differentiation of piecewise functions is a fundamental skill. A piecewise function is merely a function that has different expressions based on the interval of the input value, x. Differentiation of these functions involves taking the derivative of each piece separately, just as we would for standard functions.

For instance, if we have a function defined by different formulas in different intervals, we'd differentiate each formula independently within its respective interval. It's crucial to calculate these derivatives accurately because they play a pivotal role in determining the function's behavior and its continuity at specific points.
In our exercise example, the function \( f(x) \) is broken into two intervals: \( x \) less than or equal to 1, and \( x \) greater than 1. For each interval, we derived \( f'(x) \), which results in two separate expressions for the derivative. This differentiation is straightforward, but it's the subsequent step—ensuring the continuity of the derivative at the boundary between the pieces—that causes most of the challenges.
Continuity of Derivative
The continuity of a function's derivative is a deeper concept that often confuses students. Simply put, for a function to be smoothly continuous, not only the function itself but also its derivative must not have any abrupt changes or breaks.

In a mathematical context, a function's derivative is said to be continuous at a point if the left-hand limit and the right-hand limit at the point are equal. This means that for a piecewise function like the one in our exercise, we evaluate the derivative from both 'pieces' as we approach the boundary. If the two results match perfectly, the derivative is continuous, and the overall function is likely to be smooth across that region.
To achieve this continuity in our problem, we first found the derivatives separately for \( x \) less than and equal to 1 and for \( x \) greater than 1. Evaluating these at the point \( x=1 \) gave us two expressions. By setting them equal to each other, we ensured that the slopes on both sides of \( x=1 \) are the same, thus guaranteeing the smoothness of the graph at that point. This method is fundamental in calculus, as continuous derivatives usually imply a function is differentiable, and hence, much easier to work with analytically.
Determining Constants in Calculus
Calculus frequently involves finding unknown values that make a function behave in a certain way, especially when it comes to integrals, limits, and — as in our case — derivatives. When we're given a piecewise function with an unknown constant, the goal is to determine this constant so that the function meets the criteria specified in the problem, like being differentiable or continuous.

Determining constants in calculus is like solving a puzzle. We use conditions given by the problem (like continuity or a specific function value) to find an unknown constant. In our exercise, the condition was the continuity of the derivative at the boundary point of the two pieces of the piecewise function. By equating the derivatives from both intervals at the point and solving for the unknown constant \( a \), we found the value that makes the function's derivative continuous. \( a \) turned out to be 4 in this case.
This approach is not just mechanical; it involves a deep understanding of how functions and derivatives work. It's a testament to the beauty of calculus -- through a series of logical steps, we can deduce missing information that ensures the function maintains the desired behavior.

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Most popular questions from this chapter

Earth's atmospheric pressure decreases with altitude from a sea level pressure of 1000 millibars (a unit of pressure used by meteorologists). Letting \(z\) be the height above Earth's surface (sea level) in kilometers, the atmospheric pressure is modeled by \(p(z)=1000 e^{-z / 10}\) a. Compute the pressure at the summit of Mt. Everest, which has an elevation of roughly \(10 \mathrm{km} .\) Compare the pressure on Mt. Everest to the pressure at sea level. b. Compute the average change in pressure in the first \(5 \mathrm{km}\) above Earth's surface. c. Compute the rate of change of the pressure at an elevation of \(5 \mathrm{km}\) d. Does \(p^{\prime}(z)\) increase or decrease with \(z ?\) Explain. e. What is the meaning of \(\lim _{z \rightarrow \infty} p(z)=0 ?\)

Let \(f(x)=x e^{2 x}\) a. Find the values of \(x\) for which the slope of the curve \(y=f(x)\) is 0 b. Explain the meaning of your answer to part (a) in terms of the graph of \(f\)

Assume \(f\) and \(g\) are differentiable on their domains with \(h(x)=f(g(x)) .\) Suppose the equation of the line tangent to the graph of \(g\) at the point (4,7) is \(y=3 x-5\) and the equation of the line tangent to the graph of \(f\) at (7,9) is \(y=-2 x+23\) a. Calculate \(h(4)\) and \(h^{\prime}(4)\) b. Determine an equation of the line tangent to the graph of \(h\) at \((4, h(4))\)

The number of hours of daylight at any point on Earth fluctuates throughout the year. In the Northern Hemisphere, the shortest day is on the winter solstice and the longest day is on the summer solstice. At \(40^{\circ}\) north latitude, the length of a day is approximated by $$D(t)=12-3 \cos \left(\frac{2 \pi(t+10)}{365}\right)$$ where \(D\) is measured in hours and \(0 \leq t \leq 365\) is measured in days, with \(t=0\) corresponding to January 1 a. Approximately how much daylight is there on March 1 \((t=59) ?\) b. Find the rate at which the daylight function changes. c. Find the rate at which the daylight function changes on March \(1 .\) Convert your answer to units of min/day and explain what this result means. d. Graph the function \(y=D^{\prime}(t)\) using a graphing utility. e. At what times of the year is the length of day changing most rapidly? Least rapidly?

A mixing tank A 500 -liter (L) tank is filled with pure water. At time \(t=0,\) a salt solution begins flowing into the tank at a rate of \(5 \mathrm{L} / \mathrm{min.}\) At the same time, the (fully mixed) solution flows out of the tank at a rate of \(5.5 \mathrm{L} / \mathrm{min}\). The mass of salt in grams in the tank at any time \(t \geq 0\) is given by $$M(t)=250(1000-t)\left(1-10^{-30}(1000-t)^{10}\right)$$ and the volume of solution in the tank is given by $$V(t)=500-0.5 t$$ a. Graph the mass function and verify that \(M(0)=0\) b. Graph the volume function and verify that the tank is empty when \(t=1000 \mathrm{min}\) c. The concentration of the salt solution in the tank (in \(\mathrm{g} / \mathrm{L}\) ) is given by \(C(t)=M(t) / V(t) .\) Graph the concentration function and comment on its properties. Specifically, what are \(C(0)\) \(\underset{t \rightarrow 1000^{-}}{\operatorname{and}} C(t) ?\) d. Find the rate of change of the mass \(M^{\prime}(t),\) for \(0 \leq t \leq 1000\) e. Find the rate of change of the concentration \(C^{\prime}(t),\) for \(0 \leq t \leq 1000\) f. For what times is the concentration of the solution increasing? Decreasing?

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