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Derivatives of products and quotients Find the derivative of the following functions by first expanding or simplifying the expression. Simplify your answers. $$f(x)=(2 x+1)\left(3 x^{2}+2\right)$$

Short Answer

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Question: Find the derivative of the function $$f(x) = (2x+1)(3x^2+2)$$ with respect to x. Answer: The derivative of the given function with respect to x is $$f'(x) = 18x^2 + 6x + 4$$.

Step by step solution

01

Expand the given expression

Using the distributive property, we can expand the expression for f(x) as follows: $$f(x)=(2x+1)\left(3x^2+2\right)= 6x^3 + 4x + 3x^2 + 2$$
02

Differentiate with respect to x

Now differentiate the expanded expression with respect to x: $$f'(x)=\frac{d}{dx}(6x^3+4x+3x^2+2)$$
03

Apply the basic rules of differentiation

Apply the power rule and the constant rule to differentiate each term in the expression: $$f'(x) = \frac{d}{dx}(6x^3) + \frac{d}{dx}(4x) + \frac{d}{dx}(3x^2) + \frac{d}{dx}(2)$$ $$f'(x) = 6\frac{d}{dx}(x^3) + 4\frac{d}{dx}(x) + 3\frac{d}{dx}(x^2) + 0$$ Using the power rule, we have: $$f'(x) = 6\cdot 3x^2 + 4\cdot 1 + 3\cdot 2x + 0$$
04

Simplify the derivative

Simplify the expression for the derivative: $$f'(x) = 18x^2 + 4 + 6x$$ The derivative of the given function is: $$f'(x) = 18x^2 + 6x + 4$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus, used to calculate the rate of change of a function with respect to a variable. At its core, differentiation gives us the derivative, represented as \( f'(x) \), which measures how a function \( f(x) \)'s output changes as its input \( x \) changes. Essentially, it's like taking a magnifying glass to a curve and examining how steep it is at any point.

For a simple understanding, consider driving a car: the speedometer shows your rate of speed (analogous to the derivative) which tells you how quickly you are covering distance (the function) over time (the variable). In the mathematical journey, differentiation is the tool that reveals this 'speed' at any moment along a function's path.
Power Rule
The power rule is a quick shortcut in calculus for finding the derivative of a function when that function can be written as \( x^n \), where \( n \) is any real number. The rule states that the derivative of \( x^n \) is \( nx^{n-1} \). It's like a formula for fast-forwarding through the differentiation process.

Understanding the Power Rule

If you have \( x \) raised to the power of 3 (\( x^3 \) ), using the power rule, the derivative is simply 3 times \( x \) raised to the power of 2 (\( 3x^2 \) ). Think of it as knocking the exponent down by one and multiplying the whole thing by the original exponent. This rule helps simplify a whole lot of manual work, making it one of the key tools in a mathematician's toolkit.
Distributive Property
The distributive property is your mathematical go-to for breaking down complex expressions into simpler parts. It works on the principle of multiplying a single term with each term in a bracketed expression. In algebraic terms, it tells us that \( a(b + c) = ab + ac \).

Picture yourself handing out apples (a) to two friends (b and c): each friend gets the same number of apples. Mathematically, whether you give out the apples one friend at a time or both at once, you’re distributing the same total amount of apples. This property is very helpful when expanding expressions, particularly in preparation for differentiation.
Simplifying Expressions
Simplifying expressions is like organizing a cluttered room so you can easily find what you need. In math, simplification means rewriting expressions in the most straightforward or simplest form without changing their value. The goal is to combine like terms, reduce fractions, or expand products.

When you simplify before differentiating, you're essentially making your calculus work more efficient. It's like clearing up the clutter before painting the room – it ensures a smooth surface to work with. This step is crucial because it makes the following differentiation process more manageable and the final derivative more accessible to understand.

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Most popular questions from this chapter

Calculating limits exactly Use the definition of the derivative to evaluate the following limits. $$\lim _{x \rightarrow e} \frac{\ln x-1}{x-e}$$

Use implicit differentiation to find\(\frac{d y}{d x}.\) $$y=\frac{x+1}{y-1}$$

An equilateral triangle initially has sides of length \(20 \mathrm{ft}\) when each vertex moves toward the midpoint of the opposite side at a rate of \(1.5 \mathrm{ft} / \mathrm{min}\). Assuming the triangle remains equilateral, what is the rate of change of the area of the triangle at the instant the triangle disappears?

Vibrations of a spring Suppose an object of mass \(m\) is attached to the end of a spring hanging from the ceiling. The mass is at its equilibrium position \(y=0\) when the mass hangs at rest. Suppose you push the mass to a position \(y_{0}\) units above its equilibrium position and release it. As the mass oscillates up and down (neglecting any friction in the system , the position y of the mass after t seconds is $$y=y_{0} \cos (t \sqrt{\frac{k}{m}})(4)$$ where \(k>0\) is a constant measuring the stiffness of the spring (the larger the value of \(k\), the stiffer the spring) and \(y\) is positive in the upward direction. A mechanical oscillator (such as a mass on a spring or a pendulum) subject to frictional forces satisfies the equation (called a differential equation) $$y^{\prime \prime}(t)+2 y^{\prime}(t)+5 y(t)=0$$ where \(y\) is the displacement of the oscillator from its equilibrium position. Verify by substitution that the function \(y(t)=e^{-t}(\sin 2 t-2 \cos 2 t)\) satisfies this equation.

Work carefully Proceed with caution when using implicit differentiation to find points at which a curve has a specified slope. For the following curves, find the points on the curve (if they exist) at which the tangent line is horizontal or vertical. Once you have found possible points, make sure that they actually lie on the curve. Confirm your results with a graph. $$x\left(1-y^{2}\right)+y^{3}=0$$

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