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Find the derivative of the following functions. $$y=\frac{\cos x}{\sin x+1}$$

Short Answer

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Question: Find the derivative of the function \(y=\frac{\cos x}{\sin x+1}\). Answer: The derivative of the function \(y=\frac{\cos x}{\sin x+1}\) is \(y' = \frac{-(1+\sin x \cos x)}{(\sin x + 1)^2}\).

Step by step solution

01

Identify the numerator and the denominator functions

The given function is \(y = \frac{\cos x}{\sin x + 1}\). Here, we have \(u(x) = \cos x\) as the numerator function, and \(v(x) = \sin x + 1\) as the denominator function.
02

Find the derivatives of the numerator and the denominator

We need to find the derivatives of \(u(x) = \cos x\) and \(v(x) = \sin x + 1\). Using the knowledge of basic derivatives, we find: $$u'(x) = \frac{d}{dx}(\cos x) = -\sin x$$ and $$v'(x) = \frac{d}{dx}(\sin x + 1) = \cos x$$
03

Apply the quotient rule

To find the derivative of \(y\), we apply the quotient rule: $$y' = \frac{u'v - uv'}{v^2}$$Substitute \(u(x)\), \(u'(x)\), \(v(x)\), and \(v'(x)\) with the values found in Step 2:$$y' = \frac{(-\sin x)(\sin x + 1) - (\cos x)(\cos x)}{(\sin x + 1)^2}$$
04

Simplify the expression

Simplify the expression for \(y'\):$$y' = \frac{-\sin^{2}x - \sin x \cos x - \cos^{2}x}{(\sin x + 1)^2}$$Recall the Pythagorean identity \(\sin^{2}x + \cos^{2}x = 1\). Use this identity to simplify the expression further:$$y' = \frac{-(1+\sin x \cos x)}{(\sin x + 1)^2}$$ The derivative of the function \(y=\frac{\cos x}{\sin x+1}\) is: $$y' = \frac{-(1+\sin x \cos x)}{(\sin x + 1)^2}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
When calculating the derivative of a function that is formed by the division of two functions (\frac{f(x)}{g(x)}), we use the quotient rule. This rule is essential for finding derivatives when functions are intertwined through division.

The quotient rule formula is given by \[y' = \frac{u'v - uv'}{v^2}\] where \(u(x)\) is the numerator function, \(v(x)\) is the denominator function, \(u'(x)\) is the derivative of the numerator, and \(v'(x)\) is the derivative of the denominator. This rule is particularly useful when both \(u(x)\) and \(v(x)\) are also functions of \(x\).

Applying this rule efficiently requires the derivatives of the top and bottom functions to be determined separately before plugging them into this formula. As students work through problems, they will see the quotient rule simplifies the process of finding derivatives for complex rational functions.
Derivative of Trigonometric Functions
Trigonometric functions are the sine, cosine, tangent, and their reciprocal functions, cosecant, secant, and cotangent. The derivatives of these functions follow specific rules that are key to solving calculus problems involving trigonometry.

The basic derivatives of the primary trigonometric functions that should be memorized are: \[\frac{d}{dx}(\sin(x)) = \cos(x)\] and \[\frac{d}{dx}(\cos(x)) = -\sin(x)\].

When finding derivatives of more complex trigonometric functions, like those multiplied by other functions or standing in a quotient, we must use these basic derivatives in conjunction with the product rule, quotient rule, or chain rule as appropriate. Being familiar with these can make finding derivatives of trigonometric functions a more straightforward task.
Simplifying Expressions
After applying derivation rules, we often obtain expressions that seem complex and daunting. However, simplifying these expressions can make them more comprehensible. Simplification involves combining like terms, factoring, expanding, and cancelling where possible.

When working with derivatives in calculus, simplification can help in reducing the function to its most manageable form, which can then be used for further calculations like evaluating limits, plotting the function graphically, or finding critical points.

To effectively simplify expressions, one should be familiar with algebraic identities, properties of exponents, and trigonometric identities. It's important not to rush this step and to carry it out methodically to avoid errors. Simplified expressions often lead to clearer insights into the behavior of the function.
Pythagorean Identity
In trigonometry, the Pythagorean identity is fundamental and incredibly useful. It relates the squares of the sine and cosine of an angle and states that for any angle \(x\), the following equation holds true: \[\sin^{2}(x) + \cos^{2}(x) = 1\].

This identity is derived from the Pythagorean theorem and is valid for all real numbers \(x\). Using this identity is very helpful when simplifying expressions involving trigonometric functions, as we often encounter terms like \(\sin^{2}(x)\) and \(\cos^{2}(x)\) in calculus problems.

Applying the Pythagorean identity can turn complex trigonometric expressions into more manageable algebraic ones. For instance, substituting \(\sin^{2}(x)\) with \(1 - \cos^{2}(x)\) or vice versa can help to simplify the expression further. In our exercise, it was used to simplify the derivative of a quotient of trigonometric functions.

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Most popular questions from this chapter

86-89. Second derivatives Find \(\frac{d^{2} y}{d x^{2}}\) for the following functions. $$y=\sin x^{2}$$

Calculating limits exactly Use the definition of the derivative to evaluate the following limits. $$\lim _{h \rightarrow 0} \frac{(3+h)^{3+h}-27}{h}$$

Suppose you forgot the Quotient Rule for calculating \(\frac{d}{d x}\left(\frac{f(x)}{g(x)}\right) .\) Use the Chain Rule and Product Rule with the identity \(\frac{f(x)}{g(x)}=f(x)(g(x))^{-1}\) to derive the Quotient Rule.

Assume \(f\) and \(g\) are differentiable on their domains with \(h(x)=f(g(x)) .\) Suppose the equation of the line tangent to the graph of \(g\) at the point (4,7) is \(y=3 x-5\) and the equation of the line tangent to the graph of \(f\) at (7,9) is \(y=-2 x+23\) a. Calculate \(h(4)\) and \(h^{\prime}(4)\) b. Determine an equation of the line tangent to the graph of \(h\) at \((4, h(4))\)

The number of hours of daylight at any point on Earth fluctuates throughout the year. In the Northern Hemisphere, the shortest day is on the winter solstice and the longest day is on the summer solstice. At \(40^{\circ}\) north latitude, the length of a day is approximated by $$D(t)=12-3 \cos \left(\frac{2 \pi(t+10)}{365}\right)$$ where \(D\) is measured in hours and \(0 \leq t \leq 365\) is measured in days, with \(t=0\) corresponding to January 1 a. Approximately how much daylight is there on March 1 \((t=59) ?\) b. Find the rate at which the daylight function changes. c. Find the rate at which the daylight function changes on March \(1 .\) Convert your answer to units of min/day and explain what this result means. d. Graph the function \(y=D^{\prime}(t)\) using a graphing utility. e. At what times of the year is the length of day changing most rapidly? Least rapidly?

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