Chapter 3: Problem 25
Find the derivative of the following functions. $$y=\left(x^{2}+1\right) \ln x$$
Short Answer
Expert verified
Answer: The derivative of the given function is $$\frac{d}{dx}\left((x^2 + 1)\ln x\right) = 2x\ln x + x + \frac{1}{x}$$.
Step by step solution
01
Find the derivative of each function
First, we will find the derivative of each function involved in the product:
- For $$x^2 + 1$$, it's a simple polynomial function, and its derivative is $$\frac{d}{dx}(x^2 + 1) = 2x$$.
- For $$\ln x$$, you need to remember the derivative is $$\frac{d}{dx}(\ln x) = \frac{1}{x}$$.
02
Apply the product rule
The product rule states that given two functions $$u(x)$$ and $$v(x)$$, the derivative of their product is: $$(u \cdot v)' = u' \cdot v + u \cdot v'$$.
In our case, $$u(x) = x^2 + 1$$ and $$v(x) = \ln x$$. We already found their derivatives in Step 1:
- $$u'(x) = 2x$$
- $$v'(x) = \frac{1}{x}$$
Applying the product rule, we get:
$$(x^2 + 1)(\ln x)' = (2x)(\ln x) + (x^2 + 1)\left(\frac{1}{x}\right)$$
03
Simplify the result
Now, we need to simplify the resulting expression:
$$(x^2 + 1)(\ln x)' = 2x\ln x + \frac{x^2}{x} + \frac{1}{x}$$
$$= 2x\ln x + x + \frac{1}{x}$$
So, the derivative of the given function is:
$$\frac{d}{dx}\left((x^2 + 1)\ln x\right) = 2x\ln x + x + \frac{1}{x}$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Product Rule
The product rule is a fundamental concept in calculus used when differentiating a product of two functions. If you have two differentiable functions, say \( u(x) \) and \( v(x) \), the product rule provides a structured way to compute the derivative of their product. The formula is given by:
- \((u \cdot v)' = u' \cdot v + u \cdot v'\)
- The first term is the derivative of the first function multiplied by the second function.
- The second term is the first function multiplied by the derivative of the second function.
- Identifying \( u(x) = x^2 + 1\) and \( v(x) = \ln x \).
- Computing \( u'(x) = 2x\) and \( v'(x) = \frac{1}{x}\).
- Substituting into the product rule formula gives \((2x)(\ln x) + (x^2 + 1)\left(\frac{1}{x}\right) \).
Differentiation
Differentiation is the process of finding the derivative of a function. This process helps determine the rate at which a function changes and is a vital tool in calculus for analyzing functions. In the context of the given exercise, we focus on differentiating polynomial and logarithmic functions, commonly encountered in calculus.
- The derivative of a polynomial function like \(x^2 + 1\) is calculated using simple rules where powers of \(x\) are multiplied by their respective exponents, resulting in \( 2x\).
- For logarithmic functions, such as \(\ln x\), the derivative is a standard result: \(\frac{1}{x}\).
Logarithmic Functions
Logarithmic functions are essential in calculus and come with unique differentiation rules. The most common is the natural logarithm function, denoted as \( \ln x \). Its derivative, \( \frac{d}{dx}(\ln x) = \frac{1}{x} \), is fundamental and frequently used in calculus problems.
- Logarithmic functions are defined for positive real numbers and are useful for expressing complex relationships in simpler terms.
- Their derivatives often appear in rules like the product rule or quotient rule due to their simplifying properties.