/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Use Theorem 3. 10 to evaluate th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use Theorem 3. 10 to evaluate the following limits. $$\lim _{x \rightarrow 0} \frac{\sin a x}{b x}, \text { where } a \text { and } b \text { are constants with } b \neq 0$$

Short Answer

Expert verified
Answer: The limit of the expression \(\frac{\sin ax}{bx}\) as \(x\) approaches \(0\) is \(\frac{a}{b}\).

Step by step solution

01

Write down the given limit

Given the limit: $$\lim_{x \rightarrow 0} \frac{\sin ax}{bx}$$
02

Use a substitution

Let \(y = ax\). Then as \(x\) approaches \(0\), \(y\) also approaches \(0\). Applying the substitution, the limit now becomes: $$\lim_{y \rightarrow 0} \frac{\sin y}{b\frac{y}{a}}$$
03

Simplify the expression

Re-write the limit expression as: $$\lim_{y \rightarrow 0} \frac{a}{b} \cdot \frac{\sin y}{y}$$
04

Apply Theorem 3.10

Now, apply Theorem 3.10, which states that \(\lim_{y \rightarrow 0} \frac{\sin y}{y} = 1\): $$\frac{a}{b} \cdot \lim_{y \rightarrow 0} \frac{\sin y}{y} = \frac{a}{b} \cdot 1$$
05

Compute the final result

The result of the limit is: $$\lim_{x \rightarrow 0} \frac{\sin ax}{bx} = \frac{a}{b}$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Theorem 3.10
When studying limits, especially those involving trigonometric functions, Theorem 3.10 stands out as a crucial principle. It succinctly states that \( \lim_{y \rightarrow 0} \frac{\sin y}{y} = 1 \). This theorem is important because it applies to a special case where a sine function is being divided by its own angle in radians when that angle approaches zero. This outcome isn't immediately obvious through algebraic manipulation, but a geometric or an analytic justification can confirm its validity.

This theorem is frequently applied when dealing with trigonometric limits and it's often used in tandem with other limit properties to find the limit of more complex expressions. The elegance of this approach lies in its simplicity and its far-reaching applicability to a wide variety of problems in calculus.
Sine Function Limits
Considering the sine function when dealing with limits is pivotal in calculus. The sine function exhibits a unique behavior as the input approaches zero. This is quantified by the previously mentioned Theorem 3.10, which can be thought of as a foundational block for understanding sine function limits. Additionally, limits of the sine function as the argument approaches infinity or some other value may also be of interest, but often require different tools to evaluate.

Knowing how to manipulate and simplify expressions involving sine functions to make use of limit theorems ensures students can tackle a wider range of problems. This skill becomes particularly important in higher-level mathematics courses that deal with series and more intricate functions.
Limit Substitution Method
When confronted with complex limits, the substitution method often simplifies the process. In substitution, a new variable is introduced, replacing a part of the original function to make it easier to evaluate the limit. As seen in the exercise, the substitution \( y = ax \) is used where the limit is then evaluated at \( y \) approaching zero, which is an equivalent scenario to \( x \) approaching zero when \( a \) is a constant.

Substitution is not always straightforward – it requires a keen eye to identify what replacement will lead to a solvable limit. The main advantage of this method is that it can turn a problematic limit into one that is more manageable and directly applicable to known limit theorems or properties.
Trigonometric Limits
Trigonometric functions, which include sine, cosine, and tangent functions, often appear in limit problems. They can prove tricky due to their oscillatory behavior. Trigonometric limits are a subset of limits that specifically deal with these types of functions as the variable approaches a particular value. The process often involves understanding and applying specific limit theorems, like Theorem 3.10, or using L'Hôpital's rule when dealing with forms that involve division by zero or infinity.

As is demonstrated in this exercise, familiarity with trigonometric identities and properties can also be instrumental in evaluating these limits. For instance, the limit of the sine function divided by its angle as it approaches zero is one such property that is frequently used. By mastering these concepts, students can accurately and confidently solve calculus problems that involve evaluating trigonometric limits.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Beginning at age \(30,\) a self-employed plumber saves \(\$ 250\) per month in a retirement account until he reaches age \(65 .\) The account offers \(6 \%\) interest, compounded monthly. The balance in the account after \(t\) years is given by \(A(t)=50,000\left(1.005^{12 t}-1\right)\) a. Compute the balance in the account after \(5,15,25,\) and 35 years. What is the average rate of change in the value of the account over the intervals \([5,15],[15,25],\) and [25,35]\(?\) b. Suppose the plumber started saving at age 25 instead of age 30\. Find the balance at age 65 (after 40 years of investing). c. Use the derivative \(d A / d t\) to explain the surprising result in part (b) and the advice: Start saving for retirement as early as possible.

Use implicit differentiation to find\(\frac{d y}{d x}.\) $$x+2 y=\sqrt{y}$$

Carry out the following steps. a. Verify that the given point lies on the curve. b. Determine an equation of the line tangent to the curve at the given point. $$x^{3}+y^{3}=2 x y ;(1,1)$$ (Graph cant copy)

A mixing tank A 500 -liter (L) tank is filled with pure water. At time \(t=0,\) a salt solution begins flowing into the tank at a rate of \(5 \mathrm{L} / \mathrm{min.}\) At the same time, the (fully mixed) solution flows out of the tank at a rate of \(5.5 \mathrm{L} / \mathrm{min}\). The mass of salt in grams in the tank at any time \(t \geq 0\) is given by $$M(t)=250(1000-t)\left(1-10^{-30}(1000-t)^{10}\right)$$ and the volume of solution in the tank is given by $$V(t)=500-0.5 t$$ a. Graph the mass function and verify that \(M(0)=0\) b. Graph the volume function and verify that the tank is empty when \(t=1000 \mathrm{min}\) c. The concentration of the salt solution in the tank (in \(\mathrm{g} / \mathrm{L}\) ) is given by \(C(t)=M(t) / V(t) .\) Graph the concentration function and comment on its properties. Specifically, what are \(C(0)\) \(\underset{t \rightarrow 1000^{-}}{\operatorname{and}} C(t) ?\) d. Find the rate of change of the mass \(M^{\prime}(t),\) for \(0 \leq t \leq 1000\) e. Find the rate of change of the concentration \(C^{\prime}(t),\) for \(0 \leq t \leq 1000\) f. For what times is the concentration of the solution increasing? Decreasing?

Two boats leave a port at the same time, one traveling west at \(20 \mathrm{mi} /\) hr and the other traveling southwest \(\left(45^{\circ}\right.\) south of west) at \(15 \mathrm{mi} / \mathrm{hr}\). After 30 minutes, how far apart are the boats and at what rate is the distance between them changing? (Hint: Use the Law of Cosines.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.