Chapter 2: Problem 63
Suppose \(\lim _{x \rightarrow a} f(x)=\infty\) and \(\lim _{x \rightarrow a} g(x)=\infty .\) Prove that \(\lim _{x \rightarrow a}(f(x)+g(x))=\infty\).
Short Answer
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Question: Prove that if \(\lim_{x\to a} f(x) = \infty\) and \(\lim_{x\to a} g(x) = \infty\), then \(\lim_{x\to a}(f(x) + g(x)) = \infty\).
Step by step solution
01
Given function limits
We are given the following limits:
1. \(\lim_{x\to a} f(x) = \infty\)
2. \(\lim_{x\to a} g(x) = \infty\)
We need to prove that: \(\lim_{x\to a}(f(x) + g(x)) = \infty\).
02
Set up inequality for \(f(x)\) and \(g(x)\)
Since the limit of \(f(x)\) and \(g(x)\) tend to infinity as \(x\) approaches \(a\), for any large positive real number \(M_1\) and \(M_2\), there exist \(\delta_1\) and \(\delta_2 > 0\) respectively such that if \(0 < |x - a| < \delta_1\), then \(f(x) > M_1\) and if \(0 < |x - a| < \delta_2\), then \(g(x) > M_2\).
03
Set up inequality for \(f(x)+g(x)\)
Now, note that if \(0 < |x-a| < \delta_1,\) then \(f(x) > M_1\), and if \(0 < |x-a| < \delta_2,\) then \(g(x) > M_2\). Then:
$$0 < |x-a| < \min{\{\delta_1, \delta_2}\} \Rightarrow f(x) + g(x) > M_1 + M_2$$
04
Prove the sum approaches infinity
Since we are given that \(\lim_{x\to a} f(x) = \infty\) and \(\lim_{x\to a} g(x) = \infty\), we have shown that for any large positive real number \(M_3 = M_1 + M_2\), we can find a \(\delta_3 = \min{\{\delta_1, \delta_2\}}\) such that if \(0 < |x - a| < \delta_3\), then \(f(x) + g(x) > M_3\).
This is the definition of the limit \(\lim_{x\to a}(f(x) + g(x)) = \infty\). So we have proved that \(\lim_{x\to a}(f(x) + g(x)) = \infty\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Infinity Limits
Infinity limits occur when a function grows without bounds as the input approaches a particular value. In our exercise, we focus on two functions, \( f(x) \) and \( g(x) \), both having infinity limits when \( x \) tends to \( a \). This means:
- The values of \( f(x) \) and \( g(x) \) can become arbitrarily large as \( x \) gets closer to \( a \), but never actually equals \( a \).
- The concept of infinity here denotes that there isn’t an upper bound to the values that \( f(x) \) and \( g(x) \) can take near \( a \).
Function Limits
Function limits are all about understanding how a function behaves as its input approaches a specific point, which might not necessarily be within the function's domain. When we consider limits, we often explore:
- The output values of the function as the input nears a particular number, from the left, the right, or both sides.
- The continuous behavior of the function or any potential discontinuities that define its limits.
Epsilon-Delta Definition
The epsilon-delta definition is core to the formal understanding of limits in calculus, providing a rigorous mathematical approach. It ensures that we can make any function close enough to a limit over a certain interval:
- "Epsilon" (\( \varepsilon \)) represents how close the function value should be to the limit.
- "Delta" (\( \delta \)) indicates the distance from \( a \), the point of approach, where this closeness needs to be maintained.