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Parametric descriptions Give a parametric description of the form \(\mathbf{r}(u, v)=\langle x(u, v), y(u, v), z(u, v)\rangle\) for the following surfaces. The descriptions are not unique. Specify the required rectangle in the uv- plane $$\text { The plane } 2 x-4 y+3 z=16$$

Short Answer

Expert verified
Question: Convert the equation of a plane 2x - 4y + 3z = 16 into a parametric form using parameters u and v. Solution: After converting the given plane equation into parametric form using parameters u and v, we have the following vector representation of the plane: $$\mathbf{r}(u, v) = \langle 8 + 2u - \frac{3}{2}v, u, v \rangle$$ with both parameters u and v varying from \(-\infty\) to \(\infty\).

Step by step solution

01

Rewrite the equation in parametric form

To rewrite the plane equation in parametric form, first solve for one of the variables (x, y, or z): $$x = \frac{1}{2}(16 + 4y - 3z) = 8 + 2y - \frac{3}{2}z$$ Now, we will assign functions of u and v to the remaining variables y and z: $$y = u$$ $$z = v$$ Hence, we can rewrite x as a function of u and v: $$x(u, v) = 8 + 2u - \frac{3}{2}v$$ Now, we have the functions of x, y, and z in terms of u and v: $$x(u, v) = 8 + 2u - \frac{3}{2}v$$ $$y(u, v) = u$$ $$z(u, v) = v$$
02

Express the parametric description as a vector

We can now express the parametric description as a vector 饾憻(u, v): $$\mathbf{r}(u, v) = \langle x(u, v), y(u, v), z(u, v) \rangle = \langle 8 + 2u - \frac{3}{2}v, u, v \rangle$$
03

Specify the required rectangle in the uv-plane

It is important to remember that there is no unique range for the parameters u and v in the uv-plane. However, if we wish to cover the plane, both parameters should be allowed to vary from \(-\infty\) to \(\infty\). Therefore, we can write the uv-plane's required rectangle as: $$- \infty < u < \infty$$ $$- \infty < v < \infty$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Functions
A vector function is a mathematical expression in multivariable calculus that describes a curve or surface in space using vectors. These functions typically have the form \( \mathbf{r}(t) = \langle f(t), g(t), h(t) \rangle \) for curves or \( \mathbf{r}(u, v) = \langle x(u, v), y(u, v), z(u, v) \rangle \) for surfaces, where \( f, g, h \) and \( x, y, z \) are real-valued functions.

In our exercise, the vector function \( \mathbf{r}(u, v) \) represents points on a plane by transforming pairs of real numbers \( (u,v) \) into three-dimensional space. This transformation allows us to study and visualize the plane in question using the more tangible concept of vectors.

Understanding vector functions is crucial for identifying the position of objects in space, determining motion and velocity, and representing complex shapes within a given coordinate system.
Surface Parametrization
Surface parametrization involves representing a surface in three-dimensional space using two parameters. It is a two-dimensional extension of the concept of a parametric curve. Parametrization grants us the ability to describe shapes that are not easily expressed in traditional Cartesian coordinates.

In our problem, we express the plane as a surface using two parameters, \( u \) and \( v \)鈥攅ach corresponding to the traditional \( y \) and \( z \) axes, respectively. By establishing parametric equations for \( x \) as \( x(u, v) = 8 + 2u - \frac{3}{2}v \) and letting \( y = u \) and \( z = v \) directly, we create a map from the \( uv \) parameter space to points on the plane.

Parametrization is essential in various applications such as computer graphics, where it is used to texture map images onto surfaces, and in higher mathematics, where it simplifies the computation of surface integrals and other complex calculations.
Plane Equations
A plane equation in three-dimensional space is a linear equation that defines a flat, two-dimensional unbounded surface. The standard form of a plane equation is \( ax + by + cz = d \) where \( a, b, c \) are the coefficients that describe the orientation of the plane in space, and \( d \) is a constant that represents the plane's offset from the origin.

The equation given in the exercise, \( 2x-4y+3z=16 \) can be thought of as a balancing scale. Here, \( x, y, z \) are the variables that can change in value to satisfy the equation, which metaphorically keeps the scale balanced at 16. In order to visualize or work with the plane, one variable is typically isolated, as was done by solving the equation for \( x \) in our step by step solution. Isolating a variable simplifies the process of finding parametric representations, which are advantageous for plotting the plane or conducting other analyses.
Multivariable Calculus
Multivariable calculus extends the principles of calculus to functions of more than one variable. It encompasses techniques like partial differentiation, multiple integration, vector calculus, and the analysis of vector fields. These concepts are crucial in physics, engineering, economics, and more.

In the context of our exercise, multivariable calculus allows us to analyze and work with the plane equation \( 2x - 4y + 3z = 16 \) efficiently. When we transition from the standard Cartesian form to parametric or vector expressions, we utilize concepts from multivariable calculus to create a bridge between these different forms. Applications facilitated by these techniques include computing the area of surfaces, finding tangent planes, and even optimizing functions over domains in three dimensions or more. Multivariable calculus is a powerful tool for exploring and manipulating a rich diversity of high-dimensional mathematical landscapes.

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Most popular questions from this chapter

Prove that for a real number \(p,\) with \(\mathbf{r}=\langle x, y, z\rangle, \nabla \cdot \frac{\langle x, y, z\rangle}{|\mathbf{r}|^{p}}=\frac{3-p}{|\mathbf{r}|^{p}}\)

Fourier's Law of heat transfer (or heat conduction ) states that the heat flow vector \(\mathbf{F}\) at a point is proportional to the negative gradient of the temperature; that is, \(\mathbf{F}=-k \nabla T,\) which means that heat energy flows from hot regions to cold regions. The constant \(k>0\) is called the conductivity, which has metric units of \(J /(m-s-K)\) A temperature function for a region \(D\) is given. Find the net outward heat flux \(\iint_{S} \mathbf{F} \cdot \mathbf{n} d S=-k \iint_{S} \nabla T \cdot \mathbf{n} d S\) across the boundary S of \(D\) In some cases, it may be easier to use the Divergence Theorem and evaluate a triple integral. Assume \(k=1 .\) $$\begin{aligned} &T(x, y, z)=100+x^{2}+y^{2}+z^{2}\\\ &D=\\{(x, y, z): 0 \leq x \leq 1,0 \leq y \leq 1,0 \leq z \leq 1\\} \end{aligned}$$

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Stokes' Theorem on closed surfaces Prove that if \(\mathbf{F}\) satisfies the conditions of Stokes' Theorem, then \(\iint_{S}(\nabla \times \mathbf{F}) \cdot \mathbf{n} d S=0\) where \(S\) is a smooth surface that encloses a region.

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