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Line integrals Use Green's Theorem to evaluate the following line integrals. Assume all curves are oriented counterclockwise. A sketch is helpful. \(\oint_{C} x e^{y} d x+x d y,\) where \(C\) is the boundary of the region bounded by the curves \(y=x^{2}, x=2,\) and the \(x\) -axis

Short Answer

Expert verified
Using Green's Theorem, the given line integral can be expressed as a double integral over the region D. First, we find the partial derivatives of P and Q and set up the double integral. Then, we find the limits of integration based on the region D bounded by the given curves. After evaluating the double integral, we obtain the final result of the line integral as 12 - 3e^4.

Step by step solution

01

Find the partial derivatives of P and Q

Recall that \(P = xe^y\) and \(Q = x\). Differentiate each with respect to the respective variables to obtain: \(\frac{\partial P}{\partial y} = x e^y\) \(\frac{\partial Q}{\partial x} = 1\)
02

Set up the double integral using Green's Theorem

Using Green's theorem, the given line integral becomes: \(\iint_D \left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right) dA = \iint_D (1 - xe^y) dA\)
03

Find the limits of integration

The region \(D\) is bounded by the curves \(y = x^2\), \(x = 2\), and the x-axis. To find the limits of integration, we need the intersecting points of these curves. The intersection of \(y = x^2\) and \(x = 2\) is \((2, 4)\), and the intersection of \(y = x^2\) and the x-axis is \((0,0)\) and \((2,0)\). The limits for x are 0 to 2, and the limits for y depend on x since \(y = x^2\). So, the double integral becomes: \(\int_{0}^{2} \int_{x^2}^{4} (1 - xe^y) dy dx\)
04

Evaluate the integral

First, integrate with respect to y: \(\int_{0}^{2} \left[y - xe^y \big|_{x^2}^4 \right] dx\) Next, evaluate at the limits: \(\int_{0}^{2} (4 - xe^4 - (x^2 - xe^{x^2})) dx\) Now, integrate with respect to x: \([4x - xe^4 +\frac{1}{2}x^3 - \frac{1}{2}xe^{x^2}\big|_0^2]\) Finally, evaluate at the limits: \((8 - 2e^4 + 4 - e^4) - (0) = 12 - 3e^4\) The final result for the given line integral is: \(\oint_{C} x e^{y} d x+x d y = \boxed{12 - 3e^4}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Line Integrals
Line integrals are a type of integral where we integrate a function along a curve. They are used to calculate things like work done by a force field moving along a path or circulation of a fluid. In the context of Green's Theorem, we use line integrals to relate a path integral around a closed curve to a double integral over the region bounded by the curve.
This theorem is particularly useful because it can simplify the computation of complex line integrals. Instead of integrating directly along the curve, we convert it into a double integral over the region inside the curve. This method often provides easier calculation and provides insights into the properties of vector fields.
In our given exercise, we compute the line integral of the vector field \[\oint_{C} x e^{y} \, dx + x \, dy\]where \(C\) represents the enclosing boundary of a region defined by specific curves. Green’s Theorem allowed us to transform this into a double integral over a simpler region.
Double Integral
Double integrals allow us to compute integrals over two-dimensional areas. It extends the concept of a single integral to functions of two variables and calculates volume under a surface. They are especially powerful when used within Green's Theorem to evaluate complex line integrals.
  • The limits of the integral define the region of integration, influenced by intersecting curves or surfaces.
  • In this exercise, the calculation region \(D\) is bounded by \(y = x^2\), \(x = 2\), and the x-axis.
When setting up the double integral to replace a line integral using Green’s Theorem, we need to determine the limits of integration based on intersections of the curves defining the boundary.
For example, in the solution,\[\iint_D (1 - xe^y) \, dA\]is transformed into specific limits for \(x\) and \(y\). These limits help calculate the area over which the function changes across the defined region, giving us an alternative way to evaluate the original line integral.
Partial Derivatives
Partial derivatives are derivatives taken with respect to one variable in a multivariable function, keeping the other variables constant. They are foundational in calculating changes in functions having more than one variable and are heavily used in fields such as physics and engineering.
In Green's Theorem, partial derivatives are essential as they provide the components needed to convert a line integral into a double integral. By finding partial derivatives, we are determining the rate of change along specific directions of our function.
  • For instance, in our exercise: \(P = xe^y\) and \(Q = x\).
  • We computed: \(\frac{\partial P}{\partial y} = xe^y\)
  • And: \(\frac{\partial Q}{\partial x} = 1\)
These derivatives were then used to form the double integral expression \(\iint_D (1 - xe^y) \, dA\), where the difference \(\left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right)\) describes how the function changes across the area bounded by our curve.Recognizing how to apply partial derivatives and interpreting their role in different contexts solidifies the understanding of complex integrals and the entire transformation process through Green's Theorem.

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Most popular questions from this chapter

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