/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Find the net outward flux of the... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the net outward flux of the field \(\mathbf{F}=\langle 2 z-y, x,-2 x\rangle\) across the sphere of radius 1 centered at the origin.

Short Answer

Expert verified
Answer: The net outward flux of the vector field \(\mathbf{F}=\langle 2 z-y, x, -2 x\rangle\) across the sphere of radius 1 centered at the origin is 0.

Step by step solution

01

Find the divergence of the vector field

To find the divergence of the given vector field, we need to find the sum of the partial derivatives of the components with respect to their respective variables. In other words, we need to compute: \(\nabla \cdot \mathbf{F} = \frac{\partial (2z-y)}{\partial x} + \frac{\partial x}{\partial y} + \frac{\partial (-2x)}{\partial z}\). Computing the partial derivatives, we get: \(\nabla \cdot \mathbf{F} = 0 + 0 - 0 = 0\). Since the divergence is zero, the net outward flux of the vector field across the sphere is also zero. There is no need to set up and evaluate the triple integral in this case.
02

Conclude the result

The net outward flux of the vector field \(\mathbf{F}=\langle 2 z-y, x, -2 x\rangle\) across the sphere of radius 1 centered at the origin is zero, as the divergence of the vector field is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Divergence of a Vector Field
When you encounter a vector field in physics or engineering, understanding how the field behaves is critical. Divergence is a concept that helps in measuring the magnitude of a field's source or sink at a given point. For a vector field represented by \( \mathbf{F} \), the divergence at any point gives us insight into whether there is a 'net outflow' or 'net inflow' of the field lines at that point. To find this mathematically, you look at how much the vector field spreads out or converges in small regions around each point.

The formula to compute divergence is a sum of partial derivatives of the field's components and is given by \[ abla \cdot \mathbf{F} = \frac{\partial F_x}{\partial x} + \frac{\partial F_y}{\partial y} + \frac{\partial F_z}{\partial z} \], where \( F_x, F_y, \) and \( F_z \) are the components of the vector field along the three coordinate axes, respectively.

If the divergence is zero at all points, as in our problem, it means the vector field is neither converging nor diverging, implying no 'net' movement of 'fluid' or quantity represented by the field lines, thus indicating a balance.
Partial Derivatives
To understand vector fields and solve problems involving net outflow, we need to tap into the world of partial derivatives. A partial derivative represents the rate at which a function changes as one variable changes, holding all other variables constant. Imagine you're analyzing temperature variation throughout a room; a partial derivative would tell you how much temperature changes in just the north-south direction, ignoring changes in any other direction.

We denote a partial derivative with the symbol \( \partial \) instead of the usual \( d \) used in basic derivatives. For example, the partial derivative of a function \( f(x, y, z) \) with respect to \( x \) is written as \( \frac{\partial f}{\partial x} \). You calculate it by treating \( y \) and \( z \) as constants and taking the derivative with respect to \( x \) alone. This approach of differentiation was crucial in determining the divergence of our vector field, which turned out to be zero, leading us to conclude the net outward flux was also zero without the need for further integration.
Triple Integral
In situations where the divergence of a vector field is not zero, the next step often involves computing the net flux using a triple integral. A triple integral extends the concept of an integral to functions of three variables and is used to calculate the volume under the surface defined by the function in a three-dimensional space.

For example, \( \iiint_V f(x, y, z) \, dV \) represents the triple integral of \( f(x, y, z) \) over a volume \( V \) and it is a way of adding up the function's values at all points in this volume. In the context of net outward flux, we integrate the divergence of the vector field over the volume of interest. However, since we discovered that the divergence is zero in our given problem, we avoided this step completely. Nevertheless, this process is crucial in cases where reaching the final solution does require evaluating the flux through a surface surrounding a volume.

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Most popular questions from this chapter

Fourier's Law of heat transfer (or heat conduction ) states that the heat flow vector \(\mathbf{F}\) at a point is proportional to the negative gradient of the temperature; that is, \(\mathbf{F}=-k \nabla T,\) which means that heat energy flows from hot regions to cold regions. The constant \(k>0\) is called the conductivity, which has metric units of \(J /(m-s-K)\) A temperature function for a region \(D\) is given. Find the net outward heat flux \(\iint_{S} \mathbf{F} \cdot \mathbf{n} d S=-k \iint_{S} \nabla T \cdot \mathbf{n} d S\) across the boundary S of \(D\) In some cases, it may be easier to use the Divergence Theorem and evaluate a triple integral. Assume \(k=1 .\) $$\begin{aligned} &T(x, y, z)=100+x+2 y+z\\\ &D=\\{(x, y, z): 0 \leq x \leq 1,0 \leq y \leq 1,0 \leq z \leq 1\\} \end{aligned}$$

Let \(f\) be differentiable and positive on the interval \([a, b] .\) Let \(S\) be the surface generated when the graph of \(f\) on \([a, b]\) is revolved about the \(x\) -axis. Use Theorem 17.14 to show that the area of \(S\) (as given in Section 6.6 ) is $$ \int_{a}^{b} 2 \pi f(x) \sqrt{1+f^{\prime}(x)^{2}} d x $$

Consider the radial field \(\mathbf{F}=\frac{\mathbf{r}}{|\mathbf{r}|^{p}}=\frac{\langle x, y, z\rangle}{|\mathbf{r}|^{p}},\) where \(p>1\) (the inverse square law corresponds to \(p=3\) ). Let \(C\) be the line segment from (1,1,1) to \((a, a, a),\) where \(a>1,\) given by \(\mathbf{r}(t)=\langle t, t, t\rangle,\) for \(1 \leq t \leq a\) a. Find the work done in moving an object along \(C\) with \(p=2\) b. If \(a \rightarrow \infty\) in part (a), is the work finite? c. Find the work done in moving an object along \(C\) with \(p=4\) d. If \(a \rightarrow \infty\) in part (c), is the work finite? e. Find the work done in moving an object along \(C\) for any \(p>1\) f. If \(a \rightarrow \infty\) in part (e), for what values of \(p\) is the work finite?

Suppose a solid object in \(\mathbb{R}^{3}\) has a temperature distribution given by \(T(x, y, z) .\) The heat flow vector field in the object is \(\mathbf{F}=-k \nabla T,\) where the conductivity \(k>0\) is a property of the material. Note that the heat flow vector points in the direction opposite to that of the gradient, which is the direction of greatest temperature decrease. The divergence of the heat flow vector is \(\nabla \cdot \mathbf{F}=-k \nabla \cdot \nabla T=-k \nabla^{2} T(\text {the Laplacian of } T) .\) Compute the heat flow vector field and its divergence for the following temperature distributions. $$T(x, y, z)=100 e^{-x^{2}+y^{2}+z^{2}}$$

Miscellaneous surface integrals Evaluate the following integrals using the method of your choice. Assume normal vectors point either outward or upward. \(\iint_{S} x y z d S,\) where \(S\) is that part of the plane \(z=6-y\) that lies in the cylinder \(x^{2}+y^{2}=4\)

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