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Find the divergence of the following vector fields. $$\mathbf{F}=\left\langle x^{2} y z,-x y^{2} z,-x y z^{2}\right\rangle$$

Short Answer

Expert verified
Question: Find the divergence of the vector field \(\mathbf{F}=\left\langle x^{2} y z,-x y^{2} z,-x y z^{2}\right\rangle\). Solution: The divergence of the vector field \(\mathbf{F}\) is given by \(\nabla \cdot \mathbf{F} = -2xyz\).

Step by step solution

01

Write down the vector field and del operator

We are given the vector field \(\mathbf{F}=\left\langle x^{2} y z,-x y^{2} z,-x y z^{2}\right\rangle\). The del (nabla) operator is given by $$\nabla = \left\langle \frac{\partial}{\partial x}, \frac{\partial}{\partial y}, \frac{\partial}{\partial z}\right\rangle$$
02

Calculate the partial derivatives of each component

We will now calculate the partial derivatives of each component of the vector field with respect to the corresponding variable: $$\frac{\partial}{\partial x}(x^{2} y z) = 2xy z$$ $$\frac{\partial}{\partial y}(-x y^{2} z) = -2xyz$$ $$\frac{\partial}{\partial z}(-x y z^{2}) = -2xyz$$
03

Find the sum of the partial derivatives

Now, we will sum the partial derivatives to find the divergence of the vector field \(\mathbf{F}\): $$\nabla \cdot \mathbf{F} = \frac{\partial}{\partial x}(x^{2} y z) + \frac{\partial}{\partial y}(-x y^{2} z) + \frac{\partial}{\partial z}(-x y z^{2})$$ $$\nabla \cdot \mathbf{F} = 2xyz - 2xyz - 2xyz$$
04

Simplify the expression and write the final answer

Simplifying the expression, we get the final answer for the divergence of the vector field \(\mathbf{F}\): $$\nabla \cdot \mathbf{F} = -2xyz$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Understanding partial derivatives is crucial when working with multivariable functions, such as vector fields. In essence, a \textbf{partial derivative} represents the rate at which a function changes along one axis, holding the others constant. For a function like \( f(x,y,z) \), we can think of three separate 'slices' – one for each axis (x, y, and z). When we calculate the partial derivative with respect to x (\( \frac{\partial}{\partial x} \)), we're looking at how the function changes as x changes, while y and z are held stationary.

For the vector field \( \mathbf{F} \) provided in the exercise, composed of three components each depending on all three variables (x, y, z), we must compute three separate partial derivatives, one for each component. These derivatives tell us how \( \mathbf{F} \) changes in the direction of each axis. It's as if we’re asking, 'If I move a tiny bit in the x (or y, or z) direction, how does each component of the vector field respond?'
Del Operator
The \textbf{del operator}, also known as the \textbf{nabla operator}, is a symbol (\( abla \)) used extensively in vector calculus. It's a vector differential operator represented by \( abla = \left\langle \frac{\partial}{\partial x}, \frac{\partial}{\partial y}, \frac{\partial}{\partial z}\right\rangle \). This operator can be applied in various ways to scalar and vector fields to yield different results, such as gradient, divergence, curl, and Laplacian.

When we use it to find the \textbf{divergence} of a vector field, we're looking for a scalar that describes how much the vector field spreads out or converges at a given point. Mathematically, it's akin to a dot product between the del operator and the vector field. The divergence gives us insight into the 'source' or 'sink' behavior of fields, which is particularly important in fields such as fluid dynamics and electromagnetism.
Vector Calculus
At the heart of many physics and engineering problems lies \textbf{vector calculus}, a branch of mathematics that deals with differentiation and integration of vector fields. Vector calculus provides us with tools to analyze and describe physical phenomena in terms of vectors that have both magnitudes and directions. It includes operations such as dot and cross products, divergence, curl, and line and surface integrals.

In terms of studying fluid flow, electromagnetism, or any system where the quantities have both direction and magnitude, vector calculus is indispensable. The exercise we see with the vector field \( \mathbf{F} \) is a practical example where vector calculus is applied to quantify the divergence, which ultimately helps to understand the field's behavior at any given point in space.
Nabla Notation
Diving deeper into our toolkit, we encounter the \textbf{nabla notation}, an elegant way to symbolize the del operator. This notation is marked by the 'upside down triangle' symbol (\( abla \)). Nabla notation streamlines the expression of operations such as gradient, divergence, and curl, which are central to vector calculus.

With the nabla notation, expressing complex equations becomes more intuitive and less cluttered. For example, in the step-by-step solution, we find that using nabla to symbolize the series of partial derivatives needed to calculate the divergence simplifies the communication of the mathematical process and focuses attention on the interaction between the operator and the vector field. The use and understanding of the nabla notation are fundamental to those working in fields involving advanced calculus.

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Most popular questions from this chapter

Let \(f\) be differentiable and positive on the interval \([a, b] .\) Let \(S\) be the surface generated when the graph of \(f\) on \([a, b]\) is revolved about the \(x\) -axis. Use Theorem 17.14 to show that the area of \(S\) (as given in Section 6.6 ) is $$ \int_{a}^{b} 2 \pi f(x) \sqrt{1+f^{\prime}(x)^{2}} d x $$

Green's First Identity Prove Green's First Identity for twice differentiable scalar-valued functions \(u\) and \(v\) defined on a region \(D:\) $$\iiint_{D}\left(u \nabla^{2} v+\nabla u \cdot \nabla v\right) d V=\iint_{S} u \nabla v \cdot \mathbf{n} d S$$where \(\nabla^{2} v=\nabla \cdot \nabla v .\) You may apply Gauss' Formula in Exercise 48 to \(\mathbf{F}=\nabla v\) or apply the Divergence Theorem to \(\mathbf{F}=u \nabla v\)

For the general rotation field \(\mathbf{F}=\mathbf{a} \times \mathbf{r},\) where \(\mathbf{a}\) is a nonzero constant vector and \(\mathbf{r}=\langle x, y, z\rangle,\) show that \(\operatorname{curl} \mathbf{F}=2 \mathbf{a}\).

Miscellaneous surface integrals Evaluate the following integrals using the method of your choice. Assume normal vectors point either outward or upward. $$\begin{aligned} &\iint_{S} \nabla \ln |\mathbf{r}| \cdot \mathbf{n} d S, \text { where } S \text { is the hemisphere } x^{2}+y^{2}+z^{2}=a^{2}\\\ &\text { for } z \geq 0, \text { and where } \mathbf{r}=\langle x, y, z\rangle \end{aligned}$$

Fourier's Law of heat transfer (or heat conduction ) states that the heat flow vector \(\mathbf{F}\) at a point is proportional to the negative gradient of the temperature; that is, \(\mathbf{F}=-k \nabla T,\) which means that heat energy flows from hot regions to cold regions. The constant \(k>0\) is called the conductivity, which has metric units of \(J /(m-s-K)\) A temperature function for a region \(D\) is given. Find the net outward heat flux \(\iint_{S} \mathbf{F} \cdot \mathbf{n} d S=-k \iint_{S} \nabla T \cdot \mathbf{n} d S\) across the boundary S of \(D\) In some cases, it may be easier to use the Divergence Theorem and evaluate a triple integral. Assume \(k=1 .\) \(T(x, y, z)=100+x^{2}+y^{2}+z^{2} ; D\) is the unit sphere centered at the origin.

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