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A triangular region has a base that connects the vertices (0,0) and \((b, 0),\) and a third vertex at \((a, h),\) where \(a>0, b>0,\) and \(h>0\) a. Show that the centroid of the triangle is \(\left(\frac{a+b}{3}, \frac{h}{3}\right)\) b. Recall that the three medians of a triangle extend from each vertex to the midpoint of the opposite side. Knowing that the medians of a triangle intersect in a point \(M\) and that each median bisects the triangle, conclude that the centroid of the triangle is \(M.\)

Short Answer

Expert verified
Question: Prove that the centroid of a triangle with vertices (0, 0), (a, h), and (b, 0) is the intersection point of the medians of the triangle. Answer: To prove this, we first found the midpoint of each side of the triangle. Next, we calculated the centroid of the triangle by averaging the coordinates of all three vertices. Then, we found the equations of the medians, which are the lines that connect each vertex with the midpoint of the opposite side. After that, we calculated the intersection point of the medians by solving the linear system formed by the medians. Finally, we compared the coordinates of the centroid and the intersection point and found that they were equal. Therefore, we can conclude that the centroid of the triangle is the intersection point of the medians.

Step by step solution

01

Calculate the midpoints of each side of the triangle

Let's first find the midpoint of each side of the triangle. The midpoint of a line segment connecting two points \((x_1, y_1)\) and \((x_2, y_2)\) can be found using the formula: \(M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\). Using this formula, we'll find the midpoints of each side: Midpoint of side connecting \((0,0)\) and \((a,h)\): \(M_A=\left(\frac{0+a}{2}, \frac{0+h}{2}\right)=\left(\frac{a}{2},\frac{h}{2}\right)\) Midpoint of side connecting \((a,h)\) and \((b,0)\): \(M_B=\left(\frac{a+b}{2}, \frac{h+0}{2}\right)=\left(\frac{a+b}{2},\frac{h}{2}\right)\) Midpoint of side connecting \((0,0)\) and \((b,0)\): \(M_C=\left(\frac{0+b}{2}, \frac{0+0}{2}\right)=\left(\frac{b}{2},0\right)\)
02

Find the centroid of the triangle

To find the centroid of the triangle, we need to average the coordinates of all three vertices. So, we'll take the average of the x-coordinates and the average of the y-coordinates: Centroid \(G=\left(\frac{0+a+b}{3},\frac{0+h+0}{3}\right)=\left(\frac{a+b}{3},\frac{h}{3}\right)\)
03

Find the equations of the medians

Now, we will find the equations of the medians, which are the lines that connect each vertex with the midpoint of the opposite side. Median from \((0,0)\) to \(M_B:\newline y-y_1=m(x-x_1)\newline y-0=\frac{h}{a+b-0}(x-0)\newline y=\frac{h}{a+b}x\) Median from \((a,h)\) to \(M_C:\newline y-h=-\frac{h}{a}\left(x-a\right)\newline y=h\left(\frac{a-x}{a}\right)\) Median from \((b,0)\) to \(M_A:\newline y-0=-\frac{h}{b-a}(x-b)\newline y=\frac{h}{b-a}(b-x)\)
04

Find the intersection point of the medians

Let \(M\) be the intersection point of the medians. To find its coordinates, we need to solve the linear system of equations formed by the medians. We will start by equating the median from (a, h) to M_C to the median from (b, 0) to M_A: \(h\left(\frac{a-x}{a}\right)=\frac{h}{b-a}(b-x)\) Now, we will solve for x, which represents the x-coordinate of the intersection point M: \(x=\frac{a+b}{2}.\) Now, we will use this value of \(x\) to find the y-coordinate of M using the median from \((0,0)\) to \(M_B\): \(y=\frac{h}{a+b}\left(\frac{a+b}{2}\right)=\frac{2h}{3}\) Thus, the coordinates of the intersection point \(M\) are: \(M=\left(\frac{a+b}{2},\frac{2h}{3}\right)\)
05

Conclude that the centroid is the intersection point M

From step 2, we found that the centroid \(G\) of the triangle is \(\left(\frac{a+b}{3},\frac{h}{3}\right)\). In step 4, we found that the intersection point \(M\) of the medians is \(\left(\frac{a+b}{2},\frac{2h}{3}\right)\). Comparing these coordinates, we see that they are equal: \(G=\left(\frac{a+b}{3},\frac{h}{3}\right)=M=\left(\frac{a+b}{2},\frac{2h}{3}\right)\) Hence, we can conclude that the centroid of the triangle is the intersection point \(M\) of the medians.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triangle Geometry
In geometry, a triangle is a fundamental shape consisting of three sides and three angles. It's a polygon with three vertices, and the sum of its internal angles is always 180 degrees. Triangles can be classified based on their side lengths or angles. For example, an equilateral triangle has all sides and angles equal, while an isosceles triangle has two sides of equal length. A scalene triangle has all unequal sides.

Understanding triangle geometry is crucial because it serves as the foundation for more complex geometric concepts. In coordinate geometry, triangles can be plotted using vertices defined by points on a coordinate plane. This allows for the calculation of important features such as area, perimeter, and centroids.

Triangles are vital in various fields such as architecture, physics, and engineering due to their structural stability. Recognizing how different parts and properties of a triangle relate to each other helps solve a variety of practical problems.
Midpoints
A midpoint is the point that divides a line segment into two equal parts. In coordinate geometry, the midpoint of a segment connecting two points \((x_1, y_1)\) and \((x_2, y_2)\) can be determined using the formula:\[ M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \]This formula simply averages the x-coordinates and the y-coordinates of the endpoints to find the center location along the segment.
  • Midpoints are used to find bisectors, medians, and other central features in geometry.
  • They are particularly useful in symmetric operations and analysis, ensuring balance and equality.
In the context of triangles, finding midpoints of each side can lead us to uncover more complex triangle properties such as medians and centroids. The process of identifying these central points can simplify solving more complicated geometrical tasks.
Medians of a Triangle
A median of a triangle is a line segment that extends from a vertex to the midpoint of the opposite side. Each triangle has three medians, one from each vertex.

Medians are important in that they not only divide the triangle into smaller sections but also characterize various properties of the triangle:
  • They bisect the triangle into two smaller triangles of equal area.
  • The medians intersect at a point called the centroid, which serves as the balance point of the triangle.
To compute a median, you first identify a vertex and its opposite side, then find the midpoint of that side using the midpoint formula. The median is the line connecting this vertex directly to the midpoint:
  • Example: For a triangle with a vertex \((a, b)\) and opposite side endpoints \((x_1, y_1)\), \((x_2, y_2)\), the midpoint would be \[ M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \]
  • The median from this vertex is then drawn to \((\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})\)
Understanding medians helps in determining the centroid, enriching your comprehension of triangle geometry.
Intersection of Medians
The intersection of the three medians of a triangle is known as the centroid. This point is a significant feature as it represents the center of mass or balance of the triangle, often denoted as \(M\).

The coordinates of the centroid\(G\) for a triangle with vertices \((x_1, y_1)\), \((x_2, y_2)\), \((x_3, y_3)\) are found by averaging the coordinates of the vertices:\[ G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) \]

Key characteristics of the centroid's location:
  • It's always found inside the triangle, regardless of the triangle’s type.
  • The centroid divides each median into a ratio of 2:1, with the longer portion always on the side of the vertex.
This intrinsic balance within the triangle makes the centroid a pivotal concept in applications such as engineering and computer graphics, where equilibrium and symmetry are often required. By comprehending the intersection of medians, you grasp the idea of the triangle's "center," which is key in solving many geometric problems.

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