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Evaluate the Jacobians \(J(u, v, w)\) for the following transformations. $$x=v+w, y=u+w, z=u+v$$

Short Answer

Expert verified
Answer: The Jacobian matrix for the given transformation is: $$J(u, v, w) = \begin{bmatrix} 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{bmatrix}$$

Step by step solution

01

Write down the transformation equations

These are the given transformations: $$x = v + w$$ $$y = u + w$$ $$z = u + v$$
02

Compute the partial derivatives

We need to compute the following partial derivatives: $$\frac{\partial x}{\partial u}, \ \frac{\partial x}{\partial v}, \ \frac{\partial x}{\partial w},$$ $$\frac{\partial y}{\partial u}, \ \frac{\partial y}{\partial v}, \ \frac{\partial y}{\partial w},$$ $$\frac{\partial z}{\partial u}, \ \frac{\partial z}{\partial v}, \ \frac{\partial z}{\partial w}.$$ Using the transformation equations, we can compute the partial derivatives as follows: $$\frac{\partial x}{\partial u} = 0, \ \frac{\partial x}{\partial v} = 1, \ \frac{\partial x}{\partial w} = 1,$$ $$\frac{\partial y}{\partial u} = 1, \ \frac{\partial y}{\partial v} = 0, \ \frac{\partial y}{\partial w} = 1,$$ $$\frac{\partial z}{\partial u} = 1, \ \frac{\partial z}{\partial v} = 1, \ \frac{\partial z}{\partial w} = 0.$$
03

Organize the partial derivatives in a matrix

The Jacobian matrix \(J(u, v, w)\) is: $$J(u, v, w) = \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} & \frac{\partial x}{\partial w} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} & \frac{\partial y}{\partial w} \\ \frac{\partial z}{\partial u} & \frac{\partial z}{\partial v} & \frac{\partial z}{\partial w} \end{bmatrix} = \begin{bmatrix} 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{bmatrix}$$ The Jacobian for this transformation is: $$J(u, v, w) = \begin{bmatrix} 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{bmatrix}$$

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