/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Find \(f_{x}, f_{y},\) and \(f_{... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find \(f_{x}, f_{y},\) and \(f_{z},\) for \(f(x, y, z)=x y+x z+y z\).

Short Answer

Expert verified
Question: Find the first-order partial derivatives of the function \(f(x, y, z) = xy + xz + yz\) with respect to each of the variables x, y, and z. Answer: The first-order partial derivatives are as follows: \(f_x = y + z\) \(f_y = x + z\) \(f_z = x + y\)

Step by step solution

01

Calculate \(f_x\) (Partial Derivative with respect to x)

To find the partial derivative of \(f(x, y, z)\) with respect to \(x\), treat \(y\) and \(z\) as constants and differentiate the function. Here we have: \(f_x = \frac{\partial}{\partial x}(xy + xz + yz)\) \(f_x = y + z\)
02

Calculate \(f_y\) (Partial Derivative with respect to y)

To find the partial derivative of \(f(x, y, z)\) with respect to \(y\), treat \(x\) and \(z\) as constants and differentiate the function. Here we have: \(f_y = \frac{\partial}{\partial y}(xy + xz + yz)\) \(f_y = x + z\)
03

Calculate \(f_z\) (Partial Derivative with respect to z)

To find the partial derivative of \(f(x, y, z)\) with respect to \(z\), treat \(x\) and \(y\) as constants and differentiate the function. Here we have: \(f_z = \frac{\partial}{\partial z}(xy + xz + yz)\) \(f_z = x + y\) To sum up, we found the first-order partial derivatives of the function \(f(x, y, z)=xy + xz + yz\): \(f_x = y + z\) \(f_y = x + z\) \(f_z = x + y\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Multivariable Functions
Multivariable functions involve more than one input variable. These functions are very common when modeling real-world phenomena where multiple factors influence an outcome. In our exercise, the function is \( f(x, y, z) = xy + xz + yz \), which depends on three variables: \( x \), \( y \), and \( z \).
  • Functions of a single variable, like \( f(x) \), depend on just one input.
  • Multivariable functions, on the other hand, incorporate two or more variables.

Each variable can represent different dimensions. For example, \( x \) could be time, \( y \) could be temperature, and \( z \) could be another influential factor like pressure. This makes multivariable calculus essential for studying how changes in multiple factors affect a function's outcome. With such functions, you can calculate different types of derivatives, which is where partial differentiation comes in.
The Role of Calculus in Multivariable Functions
Calculus is the mathematical study of change, and it is essential for understanding how multivariable functions behave. It helps quantify the rate and nature of change over a range of conditions. With a function like \( f(x, y, z) = xy + xz + yz \), calculus allows us to make precise statements about how the function changes when any of the variables change.
  • In single-variable calculus, derivative calculations help find the slope of a curve or the rate of change of a function at any point.
  • In multivariable calculus, these concepts extend to functions of more than one variable using techniques such as partial differentiation.

Through these derivatives, we can uncover insights on how altering one variable affects the function, which is critical in fields like physics and engineering, where understanding such interactions is crucial.
Grasping Partial Differentiation
Partial differentiation is a core concept when working with multivariable functions in calculus. It involves differentiating a function with respect to one variable while keeping the others constant. This technique provides a way to see how a specific variable impacts a function, holding other variables unchanged.
In the given function \( f(x, y, z) = xy + xz + yz \):
  • To find the partial derivative with respect to \( x \), treat \( y \) and \( z \) as constants and differentiate: \( f_x = y + z \).
  • Similarly, to find \( f_y \), treat \( x \) and \( z \) as constants: \( f_y = x + z \).
  • For \( f_z \), treat \( x \) and \( y \) as constants: \( f_z = x + y \).

This method is pivotal for examining the isolated effect of each variable. By focusing on one variable at a time, partial differentiation helps to solve optimization problems, predict system behavior, and analyze various real-world scenarios where multiple inputs are involved.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Among all triangles with a perimeter of 9 units, find the dimensions of the triangle with the maximum area. It may be easiest to use Heron's formula, which states that the area of a triangle with side length \(a, b,\) and \(c\) is \(A=\sqrt{s(s-a)(s-b)(s-c)},\) where \(2 s\) is the perimeter of the triangle.

Graph several level curves of the following functions using the given window. Label at least two level curves with their z-values. $$z=2 x-y ;[-2,2] \times[-2,2]$$

Steiner's problem for three points Given three distinct noncollinear points \(A, B,\) and \(C\) in the plane, find the point \(P\) in the plane such that the sum of the distances \(|A P|+|B P|+|C P|\) is a minimum. Here is how to proceed with three points, assuming the triangle formed by the three points has no angle greater than \(2 \pi / 3\left(120^{\circ}\right)\) a. Assume the coordinates of the three given points are \(A\left(x_{1}, y_{1}\right)\) \(B\left(x_{2}, y_{2}\right),\) and \(C\left(x_{3}, y_{3}\right) .\) Let \(d_{1}(x, y)\) be the distance between \(A\left(x_{1}, y_{1}\right)\) and a variable point \(P(x, y) .\) Compute the gradient of \(d_{1}\) and show that it is a unit vector pointing along the line between the two points. b. Define \(d_{2}\) and \(d_{3}\) in a similar way and show that \(\nabla d_{2}\) and \(\nabla d_{3}\) are also unit vectors in the direction of the line between the two points. c. The goal is to minimize \(f(x, y)=d_{1}+d_{2}+d_{3}\) Show that the condition \(f_{x}=f_{y}=0\) implies that \(\nabla d_{1}+\nabla d_{2}+\nabla d_{3}=0\) d. Explain why part (c) implies that the optimal point \(P\) has the property that the three line segments \(A P, B P\), and \(C P\) all intersect symmetrically in angles of \(2 \pi / 3\) e. What is the optimal solution if one of the angles in the triangle is greater than \(2 \pi / 3\) (just draw a picture)? f. Estimate the Steiner point for the three points (0,0),(0,1) and (2,0)

a. Determine the domain and range of the following functions. b. Graph each function using a graphing utility. Be sure to experiment with the window and orientation to give the best perspective on the surface. $$p(x, y)=1-|x-1|+|y+1|$$

Gradient of a distance function Let \((a, b)\) be a given point in \(\mathbb{R}^{2}\), and let \(d=f(x, y)\) be the distance between \((a, b)\) and the variable point \((x, y)\) a. Show that the graph of \(f\) is a cone. b. Show that the gradient of \(f\) at any point other than \((a, b)\) is a unit vector. c. Interpret the direction and magnitude of \(\nabla f\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.