/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 Evaluate the following limits. ... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following limits. $$\lim _{(x, y, z) \rightarrow(1,1,1)} \frac{x-\sqrt{x z}-\sqrt{x y}+\sqrt{y z}}{x-\sqrt{x z}+\sqrt{x y}-\sqrt{y z}}$$

Short Answer

Expert verified
Answer: The limit does not exist.

Step by step solution

01

Examine the denominator

Check if the denominator becomes zero as (x, y, z) approaches (1,1,1). If so, then the limit would be indeterminate and we have to take a different approach: $$ x - \sqrt{xz} + \sqrt{xy} - \sqrt{yz} = 1 - \sqrt{1 \cdot 1} + \sqrt{1 \cdot 1} - \sqrt{1 \cdot 1} = 1 $$ Since the denominator does not become zero, we can proceed with the usual process of finding limits.
02

Simplify the expression

Rewrite the expression into a simpler form so that we can find the limit: \begin{align*} \frac{x-\sqrt{x z}-\sqrt{x y}+\sqrt{y z}}{x-\sqrt{x z}+\sqrt{x y}-\sqrt{y z}} &= \frac{(\sqrt{x}-\sqrt{z})(\sqrt{x}+\sqrt{y})}{(\sqrt{x}-\sqrt{z})(\sqrt{x}-\sqrt{y})} \\ \end{align*} Now, we can cancel the common factor \((\sqrt{x}-\sqrt{z})\) from the numerator and the denominator: $$ = \frac{\sqrt{x}+\sqrt{y}}{\sqrt{x}-\sqrt{y}} $$
03

Evaluate the limit

Now, as (x, y, z) approaches (1,1,1), substitute these values into the simplified expression to find the limit: $$ \lim_{(x, y, z) \rightarrow(1,1,1)} \frac{\sqrt{x}+\sqrt{y}}{\sqrt{x}-\sqrt{y}} = \frac{\sqrt{1}+\sqrt{1}}{\sqrt{1}-\sqrt{1}} = \frac{1+1}{1-1} $$ Since the denominator is now equal to 0, the limit does not exist.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Evaluation
Limit evaluation refers to the process of finding the value that a function approaches as the input approaches some point. In the context of multivariable calculus, this involves determining the value a function approaches as multiple variables approach their respective points simultaneously.

To evaluate a multivariable limit, such as \(\text{\textbackslash lim \textunderscore{(x, y, z) \textbackslash rightarrow(1,1,1)}} \frac{x-\text{\textbackslash sqrt{x z}}-\text{\textbackslash sqrt{x y}}+\text{\textbackslash sqrt{y z}}}{x-\text{\textbackslash sqrt{x z}}+\text{\textbackslash sqrt{x y}}-\text{\textbackslash sqrt{y z}}}\), one must consider the behavior of the function around the point of interest from all possible paths. If the limit exists, the function will approach the same value from all paths. However, if different paths result in different values, the limit does not exist.

In simplifying such expressions, one should first check if direct substitution of the approaching points leads to an indeterminate form. If the function remains well-defined, direct substitution is often the simplest method to evaluate the limit.
Indeterminate Forms
Indeterminate forms occur when the direct substitution in a limit results in an expression that is not immediately apparent in determining the limit's value. Common indeterminate forms include \(0/0\), \(\text{\textbackslash infty}/\text{\textbackslash infty}\), \(0 \times \text{\textbackslash infty}\), and others like \(1^\text{\textbackslash infty}\) and \(\text{\textbackslash infty} - \text{\textbackslash infty}\).

In our example, after simplification, we encounter the indeterminate form \(2/0\) because the denominator becomes zero after substitution. This suggests we need to apply further analytical methods, such as finding a common factor which can be canceled out or using L'Hôpital's Rule, if applicable, to resolve the indeterminate form and evaluate the limit.
Simplifying Expressions
Simplifying expressions is a critical step in evaluating limits, especially in calculus where the direct evaluation may not be straightforward. Simplification often includes factoring, canceling common terms, expanding, and employing algebraic identities.

In our exercise, we factor the numerator and denominator to identify \(\text{\textbackslash sqrt{x}}-\text{\textbackslash sqrt{z}}\) as a common factor that can be canceled out. Only after this simplification can we see that the limit leads to an indeterminate form that prompts us to reassess the existence of the limit.
Limits of Functions
The limit of a function is the value that the function's output approaches as the input approaches a certain value. Limits are foundational in calculus and are used to define many of the core concepts, including derivatives, integrals, and continuity.

For functions of several variables, the concept of a limit is more complex than for single-variable functions, as we must ensure the output approaches the same number regardless of how the input values approach their target. The example from our exercise necessitates considering all possible paths by which \((x, y, z)\) could approach \((1,1,1)\), ultimately revealing the limit does not exist due to the denominator approaching zero.
Calculus
Calculus is a branch of mathematics focused on rates of change (differential calculus) and accumulation of quantities (integral calculus). One of the fundamental concepts in calculus is the notion of a limit, which is used to analyze the behavior of variables as they approach specific values. Calculus has a wide range of applications in science, engineering, economics, statistics, and many other fields.

Understanding limits and how to evaluate them is essential for students as they are fundamental to understanding more complex concepts in calculus such as derivatives and integrals. The ability to simplify and solve problems using limit evaluation, like in our textbook exercise, is a crucial skill developed in calculus coursework.

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Most popular questions from this chapter

Problems with two constraints Given a differentiable function \(w=f(x, y, z),\) the goal is to find its absolute maximum and minimum values (assuming they exist) subject to the constraints \(g(x, y, z)=0\) and \(h(x, y, z)=0,\) where \(g\) and \(h\) are also differentiable. a. Imagine a level surface of the function \(f\) and the constraint surfaces \(g(x, y, z)=0\) and \(h(x, y, z)=0 .\) Note that \(g\) and \(h\) intersect (in general) in a curve \(C\) on which maximum and minimum values of \(f\) must be found. Explain why \(\nabla g\) and \(\nabla h\) are orthogonal to their respective surfaces. b. Explain why \(\nabla f\) lies in the plane formed by \(\nabla g\) and \(\nabla h\) at a point of \(C\) where \(f\) has a maximum or minimum value. c. Explain why part (b) implies that \(\nabla f=\lambda \nabla g+\mu \nabla h\) at a point of \(C\) where \(f\) has a maximum or minimum value, where \(\lambda\) and \(\mu\) (the Lagrange multipliers) are real numbers. d. Conclude from part (c) that the equations that must be solved for maximum or minimum values of \(f\) subject to two constraints are \(\nabla f=\lambda \nabla g+\mu \nabla h, g(x, y, z)=0,\) and \(h(x, y, z)=0\)

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Probability of at least one encounter Suppose in a large group of people, a fraction \(0 \leq r \leq 1\) of the people have flu. The probability that in \(n\) random encounters you will meet at least one person with flu is \(P=f(n, r)=1-(1-r)^{n} .\) Although \(n\) is a positive integer, regard it as a positive real number. a. Compute \(f_{r}\) and \(f_{n^{*}}\) b. How sensitive is the probability \(P\) to the flu rate \(r ?\) Suppose you meet \(n=20\) people. Approximately how much does the probability \(P\) increase if the flu rate increases from \(r=0.1\) to \(r=0.11(\text { with } n \text { fixed }) ?\) c. Approximately how much does the probability \(P\) increase if the flu rate increases from \(r=0.9\) to \(r=0.91\) with \(n=20 ?\) d. Interpret the results of parts (b) and (c).

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