/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 At what points of \(\mathbb{R}^{... [FREE SOLUTION] | 91Ó°ÊÓ

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At what points of \(\mathbb{R}^{2}\) are the following functions continuous? $$f(x, y)=\sin x y$$

Short Answer

Expert verified
The function \(f(x,y) = \sin{xy}\) is continuous at every point in \(\mathbb{R}^2\), because it is a product of two continuous functions.

Step by step solution

01

Definition of Continuity

In general, a function of two variables, \(f(x, y)\), is continuous at a point \((x_0, y_0)\) in its domain if the limit as \((x, y)\) approaches \((x_0, y_0)\) exists and equals \(f(x_0, y_0)\). Formally, this is written as: $$\lim_{(x, y) \to (x_0, y_0)} f(x, y) = f(x_0, y_0)$$
02

Properties of Trigonometric Functions

We know that the sine function is a smooth function, which means that it is continuous everywhere. This implies that any function composed of a product of sine with some other function will also be continuous, as long as the other function is continuous. This is because the product of continuous functions is also continuous.
03

Identifying Continuity in \(f(x, y)\)

Since \(\sin x\) and \(\sin y\) are continuous everywhere, their product, \(\sin x \cdot y\), must also be continuous everywhere. Therefore, the function \(f(x, y) = \sin xy\) is continuous at every point \((x, y)\) in \(\mathbb{R}^{2}\).
04

Conclusion

The given function, \(f(x, y) = \sin xy\), is continuous at all points in \(\mathbb{R}^{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Functions
Trigonometric functions are fundamental in mathematics, primarily dealing with angles and periodic phenomena. Among these functions, the sine function is especially significant. It relates an angle in a right triangle to the ratio of the length of the opposite side to the hypotenuse. Trigonometric functions such as sine, cosine, and tangent are periodic, meaning they repeat values in regular intervals. The sine and cosine functions, in particular, have a period of \(2\pi\), repeating every \(2\pi\) units. This periodicity makes them incredibly useful in modeling cyclic patterns, such as sound waves, light waves, and tides. Additionally, these functions extend beyond right-angled triangles into unit circle definitions, making them applicable in calculus and various other mathematical fields. This extension allows us to explore their behavior in multivariable scenarios, as seen in functions like \(f(x, y) = \sin xy\). Understanding these properties paves the way for analyzing their continuity across different domains.
Properties of Sine Function
The sine function, \(\sin\theta\), possesses several unique properties that make it a continuous and differentiable function. Key properties of the sine function include:
  • **Periodicity**: As mentioned, the sine function has a period of \(2\pi\), meaning \(\sin(\theta + 2\pi) = \sin \theta\) for any angle \(\theta\).
  • **Range**: The sine function's range is limited to \([-1, 1]\). This implies that regardless of the input, the outcome will always fall within this interval.
  • **Odd Function**: The sine function is odd, indicated by \(\sin(-\theta) = -\sin \theta\). This symmetry exhibits a unique reflection property about the origin.
  • **Smoothness**: The sine function is not just continuous but infinitely differentiable, making it smooth throughout its domain.
These properties ensure that functions involving components like \(\sin xy\) in multivariable calculus are continuous, provided other parts of the function are also continuous. The inherent smoothness and periodic nature grant the sine function an important role in continuous transformations and equations.
Continuity in Multivariable Calculus
Continuity in multivariable calculus extends the concept of single-variable continuity to functions of several variables. For a function \(f(x, y)\), continuity at a point \((x_0, y_0)\) means the limit of \(f(x, y)\) as \((x, y)\) approaches \((x_0, y_0)\) must equal \(f(x_0, y_0)\). In simpler terms, small changes in \(x\) and \(y\) result in small changes in \(f(x, y)\). This definition hinges on the function's behavior across polynomials, rational functions, roots, and trigonometric functions.

The function \(f(x, y) = \sin xy\) demonstrates continuity across its entire domain, \(\mathbb{R}^2\), due to several reasons:
  • First, the sine function, as noted, is continuous everywhere.
  • Second, polynomials (like the product \(xy\)) are also continuous.
  • Lastly, the composition of these continuous functions remains continuous by extension.
This analysis that demonstrates the function \(f(x, y)\) is continuous at all points further showcases the seamless transition from single-variable to multivariable frameworks, retaining all pivotal principles of continuity.

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Most popular questions from this chapter

Use Lagrange multipliers in the following problems. When the constraint curve is unbounded, explain why you have found an absolute maximum or minimum value. Maximum volume cylinder in a sphere Find the dimensions of the right circular cylinder of maximum volume that can be inscribed in a sphere of radius 16

Using gradient rules Use the gradient rules of Exercise 85 to find the gradient of the following functions. $$f(x, y)=\ln \left(1+x^{2}+y^{2}\right)$$

Looking ahead- tangent planes Consider the following surfaces \(f(x, y, z)=0,\) which may be regarded as a level surface of the function \(w=f(x, y, z) .\) A point \(P(a, b, c)\) on the surface is also given. a. Find the (three-dimensional) gradient of \(f\) and evaluate it at \(P\). b. The set of all vectors orthogonal to the gradient with their tails at \(P\) form a plane. Find an equation of that plane (soon to be called the tangent plane). $$f(x, y, z)=e^{x+y-z}-1=0 ; P(1,1,2)$$

Use what you learned about surfaces in Sections 13.5 and 13.6 to sketch a graph of the following functions. In each case, identify the surface and state the domain and range of the function. $$G(x, y)=-\sqrt{1+x^{2}+y^{2}}$$

Check assumptions Consider the function \(f(x, y)=x y+x+y+100\) subject to the constraint \(x y=4\) a. Use the method of Lagrange multipliers to write a system of three equations with three variables \(x, y,\) and \(\lambda\) b. Solve the system in part (a) to verify that \((x, y)=(-2,-2)\) and \((x, y)=(2,2)\) are solutions. c. Let the curve \(C_{1}\) be the branch of the constraint curve corresponding to \(x>0 .\) Calculate \(f(2,2)\) and determine whether this value is an absolute maximum or minimum value of \(f\) over \(C_{1} \cdot(\text {Hint}: \text { Let } h_{1}(x), \text { for } x>0, \text { equal the values of } f\) over the \right. curve \(C_{1}\) and determine whether \(h_{1}\) attains an absolute maximum or minimum value at \(x=2 .\) ) d. Let the curve \(C_{2}\) be the branch of the constraint curve corresponding to \(x<0 .\) Calculate \(f(-2,-2)\) and determine whether this value is an absolute maximum or minimum value of \(f\) over \(C_{2} .\) (Hint: Let \(h_{2}(x),\) for \(x<0,\) equal the values of \(f\) over the curve \(C_{2}\) and determine whether \(h_{2}\) attains an absolute maximum or minimum value at \(x=-2 .\) ) e. Show that the method of Lagrange multipliers fails to find the absolute maximum and minimum values of \(f\) over the constraint curve \(x y=4 .\) Reconcile your explanation with the method of Lagrange multipliers.

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