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At what points of \(\mathbb{R}^{2}\) are the following functions continuous? $$f(x, y)=\frac{x y}{x^{2} y^{2}+1}$$

Short Answer

Expert verified
The function \(f(x, y) = \frac{xy}{x^2y^2 + 1}\) is continuous at all points in \(\mathbb{R}^2\) because the limit of the function exists at every point, and the function is well-defined with a non-zero denominator.

Step by step solution

01

Definition of continuity

Recall that a function is continuous at a point \((x, y)\) if the limit at that point exists and is equal to the function evaluated at that point: $$\lim_{(x', y') \to (x, y)} f(x', y') = f(x, y)$$
02

Checking the limit

We must find the limit as \((x', y')\) approaches \((x, y)\): $$\lim_{(x', y') \to (x, y)} \frac{x'y'}{x'^2y'^2 + 1}$$ To check if this limit exists, we must analyse whether the function is well-defined and whether the denominator becomes non-zero.
03

Analysis of the denominator

The denominator of the function is: $$x'^2y'^2 + 1$$ Since the square of any real number is always non-negative, it's clear that the denominator will never be zero for any \((x', y') \in \mathbb{R}^2\). Thus, the function is well-defined and the given function has no points with undefined values.
04

Evaluating the limit

We now need to check whether the limit exists for every point in \(\mathbb{R}^2\). Observe that: $$\left|\frac{x'y'}{x'^2y'^2 + 1}\right| \leq \frac{|x'y'|}{|x'^2y'^2|} \leq \frac{|x'y'|}{|x'^{2}|} \leq \frac{|x'|}{|x'|} = 1$$ Since the function is always well-defined and the limit exists at every point in the domain, we can conclude that the function is continuous.
05

Final Answer

The function \(f(x, y) = \frac{xy}{x^2y^2 + 1}\) is continuous at every point in \(\mathbb{R}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit of a function
Limits are crucial when discussing the continuity of a function. To determine the limit of a multivariable function like \( f(x, y)=\frac{x y}{x^{2} y^{2}+1} \), we inspect how the function behaves as \((x', y')\) approaches a particular point \((x, y)\). The limit is essentially the value the function is expected to reach as the input pairs get arbitrarily close to \((x, y)\).
For the function in our original exercise, the examiners are checking if as \((x', y')\) approaches \((x, y)\),the function value converges to a specific number, which should also correspond to \( f(x, y) \). The presence of a well-defined limit is the first step in confirming a function's continuity at a point. This means that if the calculated limit equals the function's evaluation at that point, the function is continuous there.
This condition can be represented mathematically as: \[\lim_{(x', y') \to (x, y)} f(x', y') = f(x, y) \]
Limits involve calculating how close a function output can get to a designated value, given inputs that are close to a particular point. Hence, confirming that the denominator in our function doesn't quite reach zero verifies this step in the solution.
Real-valued functions
Real-valued functions are those that output real numbers given real inputs. In simpler terms, these functions operate within the framework of real numbers \((\mathbb{R})\), both as inputs and outputs. Our exercise deals with such a function, where it's defined for pairs of real numbers \((x, y)\), and the result is also a real number.
These functions, like \( f(x, y) = \frac{xy}{x^2y^2 + 1} \), are elementary to problems in calculus, especially when scrutinizing behaviors over all real-number coordinates. One key attribute of a real-valued function is its domain and range, which are subsets of \( \mathbb{R}^2 \) for multivariable functions.
No matter the complexity, managing the continuity of a real-valued function demands confirming that the function is defined across its entire domain. Our problem demonstrates that the function's denominator never touches zero due to the addition of 1, thus ensuring real outcomes for all real inputs.
Multivariable calculus
Multivariable calculus extends single-variable calculus concepts to functions with more than one input variable. It allows for the exploration of functions involving, for instance, two or more dimensions which is applicable in our problem.
In this field, understanding the behavior of functions such as \( f(x, y) = \frac{xy}{x^2y^2 + 1} \)involves more complex operations, including partial differentiation and gradient calculations. Continuity in multivariable calculus, therefore, requires evaluating functions across planes rather than just along lines, as with single-variable functions.
One of the primary interests in this realm is understanding how these functions tend toward specific points in space, thanks to the principle of limits. The continuity check for our problem examines if this function maintains its expected real-valued result while conditions shift in a multi-directional path, proving it remains sound over the entirety of \( \mathbb{R}^2 \). This assures us that no matter how \((x', y')\) approach \((x, y)\), the given function remains consistent and thus continuous throughout its defined space.

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Most popular questions from this chapter

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