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Evaluate the following limits. $$\lim _{(x, y) \rightarrow(1,-2)} \frac{y^{2}+2 x y}{y+2 x}$$

Short Answer

Expert verified
Answer: The limit of the expression as \((x, y) \rightarrow(1, -2)\) is \(-2\).

Step by step solution

01

Preparing to find the limit

First, we analyze the given limit: $$\lim _{(x, y) \rightarrow(1,-2)} \frac{y^{2}+2 x y}{y+2 x}$$ This means as \((x, y)\) approaches \((1, -2)\), we want to determine the value of \(\frac{y^2+2xy}{y+2x}\), if it exists.
02

Substituting the values

Substitute the values for \(x\) and \(y\) in the given limit expression: $$\frac{(-2)^{2} + 2(1) (-2)}{-2+2 (1)}$$
03

Simplifying the expression

Simplify the expression by performing the operations: $$\frac{4 - 4}{-2+2}$$ This simplifies to: $$\frac{0}{0}$$
04

Factoring and canceling terms

The expression \(\frac{0}{0}\) means that there might be a common factor present in both the numerator and the denominator. We can try to factor the original limit expression to see if anything cancels out: $$\lim _{(x, y) \rightarrow(1,-2)} \frac{y^{2}+2 x y}{y+2 x} =\lim _{(x, y) \rightarrow(1,-2)} \frac{y(y+2x)}{y+2x}$$
05

Canceling common factors

Now, we can cancel out the common factor \((y+2x)\) from both the numerator and the denominator: $$\lim _{(x, y) \rightarrow(1,-2)} \frac{y(y+2x)}{y+2x} = \lim _{(x, y) \rightarrow(1,-2)} y$$
06

Finding the limit

Now that we have simplified the expression, we can find the limit by substituting the values of \(x\) and \(y\) again as they approach \((1, -2)\): $$\lim _{(x, y) \rightarrow(1,-2)} y = -2$$ Therefore, the limit of the given expression as \((x, y) \rightarrow(1, -2)\) is \(-2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multivariable Calculus
Multivariable Calculus is a branch of calculus that deals with functions of multiple variables. Unlike single-variable calculus, it allows us to explore how functions behave and change in relation to more than one variable. This is crucial for understanding real-world phenomena where multiple factors are involved.

In the context of limits, multivariable calculus helps determine how a function behaves as the variables approach certain points. We analyze the function's behavior by looking at paths that the variables might take as they move towards the target point. This widens our understanding beyond single-variable limits, which only consider approaching a point from the left or the right.

For our exercise, we are interested in how the function behaves as \((x, y)\) approaches \((1, -2)\). By studying limits in this way, we gain insights into the continuity and differentiability of the function across two dimensions.
Indeterminate Forms
Indeterminate forms appear when attempting to evaluate certain limits results in expressions like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\). These forms provide no clear answer, prompting further examination through algebraic manipulation or advanced calculus techniques.

In our exercise, substituting \((1, -2)\) into \(\frac{y^2 + 2xy}{y + 2x}\) initially results in the indeterminate form \(\frac{0}{0}\). This doesn't mean the limit does not exist, but rather requires additional steps to unravel the true value.

Thus, recognizing indeterminate forms is a cue to investigate deeper, often by simplifying or restructuring the function involved. Handling these forms adeptly is a vital skill in multivariable calculus.
Factoring and Simplification
Factoring and simplification are powerful tools in calculus to manage complex expressions and reveal solutions obscured by initial indeterminate forms. By changing the expression's structure, we can often cancel terms and uncover the true limit.

In our problem, factoring the original expression \(\frac{y^2+2xy}{y+2x}\) into \(\frac{y(y+2x)}{y+2x}\) is essential for removing the indeterminate form. This factorization allows us to cancel \(y+2x\), leading us to a simplified form: \(\lim_{(x, y) \rightarrow(1,-2)} y\).

This process shows how simplification doesn't merely make the expression more manageable; it transforms it to a point where a clear limit evaluation becomes possible. This approach is crucial, especially when facing indeterminate forms.
Approaching a Point
Approaching a point involves understanding how the variables in a function converge towards a specific target set of values. In mathematics, particularly calculus, we express this using the concept of limits, which capture the behavior of functions in such scenarios.

For the given exercise, as \((x, y)\) approaches \((1, -2)\), we observe the function \(y\). Once the numerator and denominator were simplified, we found the behavior of the function simplified to examining just \(y\). Direct substitution gave us the value of the limit as \(-2\).

This process of approaching a point and applying limits allows mathematicians and students to craft precise predictions of function values where direct evaluation fails. It elucidates the continuity and behavior near specific values, enriching our understanding of multivariable functions.

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