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Computing gradients Compute the gradient of the following functions and evaluate it at the given point \(P\). $$F(x, y)=e^{-x^{2}-2 y^{2}} ; P(-1,2)$$

Short Answer

Expert verified
Answer: The gradient of the function at point \(P(-1,2)\) is given by: \(\nabla F(-1,2) = \begin{bmatrix} 2 e^{-9} \\ -8 e^{-9} \end{bmatrix}\).

Step by step solution

01

Compute the partial derivative with respect to x

To compute the partial derivative of \(F(x, y)\) with respect to \(x\), we need to differentiate the function with respect to \(x\) while treating \(y\) as a constant: $$\frac{\partial F}{\partial x} = \frac{\partial}{\partial x} (e^{-x^2-2y^2}) = e^{-x^2-2y^2} \frac{\partial}{\partial x} (-x^2-2y^2)$$ Next, we differentiate the exponent term: $$-2x$$ So, we have: $$\frac{\partial F}{\partial x} = -2x e^{-x^2-2y^2}$$
02

Compute the partial derivative with respect to y

To compute the partial derivative of \(F(x, y)\) with respect to \(y\), we need to differentiate the function with respect to \(y\) while treating \(x\) as a constant: $$\frac{\partial F}{\partial y} = \frac{\partial}{\partial y} (e^{-x^2-2y^2}) = e^{-x^2-2y^2} \frac{\partial}{\partial y} (-x^2-2y^2)$$ Next, we differentiate the exponent term: $$-4y$$ So, we have: $$\frac{\partial F}{\partial y} = -4y e^{-x^2-2y^2}$$
03

Compute the gradient

Now that we have the partial derivatives, we can compute the gradient of the function \(F(x, y)\) by collecting them as components of a vector: $$\nabla F(x,y) = \begin{bmatrix} \frac{\partial F}{\partial x} \\ \frac{\partial F}{\partial y} \end{bmatrix} = \begin{bmatrix} -2x e^{-x^2-2y^2} \\ -4y e^{-x^2-2y^2} \end{bmatrix}$$
04

Evaluate the gradient at point P

We are now asked to evaluate the gradient at point \(P(-1,2)\). To do this, we substitute the coordinates of point \(P\) into the gradient expression: $$\nabla F(-1, 2) = \begin{bmatrix} -2(-1) e^{-(1)^2-2(2)^2} \\ -4(2) e^{-(1)^2-2(2)^2} \end{bmatrix} = \begin{bmatrix} 2 e^{-1-8} \\ -8 e^{-1-8} \end{bmatrix} = \begin{bmatrix} 2 e^{-9} \\ -8 e^{-9} \end{bmatrix}$$ So, the gradient at point \(P(-1,2)\) is given by: $$\nabla F(-1,2) = \begin{bmatrix} 2 e^{-9} \\ -8 e^{-9} \end{bmatrix}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are a core concept in multivariable calculus. They represent the rate of change of a multivariable function with respect to one variable at a time, while keeping all other variables constant. When computing a partial derivative, you focus on the variation along a single axis in the n-dimensional space that represents the function's domain.

For example, in the given exercise, to find the rate of change of the function \(F(x, y) = e^{-x^2 - 2y^2}\) with respect to \(x\), we differentiate with respect to \(x\) and treat \(y\) as a constant. This process is akin to examining how the function's value changes as you move east or west on a map, not caring about the movement in the north or south direction.

Similarly, the partial derivative with respect to \(y\) shows how the function changes as you move north or south, while staying on the same east-west line. Understanding how to calculate these derivatives is essential for analyzing functions that have several independent variables, and is pivotal for tasks like finding the gradient, which we explore next.
Multivariable Calculus
Multivariable calculus extends the concepts of single-variable calculus to functions with more than one input. In the context of this discipline, the gradient is a vital concept. The gradient of a multivariable function is a vector containing all of the function’s first partial derivatives. It points in the direction of the greatest rate of increase of the function and its magnitude corresponds to the steepness of the ascent.

In our exercise, the gradient \(abla F(x,y)\) is found by combining the partial derivatives \(\frac{\partial F}{\partial x}\) and \(\frac{\partial F}{\partial y}\) into a vector. This is analogous to taking measurements in different directions to determine the slope of a hill at a specific point. Gradients are fundamental in numerous applications, including optimizing functions in economics, modeling physical processes, and training machine learning algorithms.
Exponential Functions
Exponential functions, such as \( e^x \), are widely used in various fields, including science, finance, and engineering because of their unique properties. In our exercise, the function \( F(x, y) = e^{-x^2 - 2y^2} \) is an example of a two-variable exponential function where the exponent itself is a function of both \(x\) and \(y\).

An important characteristic of exponential functions is that their rate of change is proportional to the function's value, which is why derivatives of these functions involve the original exponential term. This self-similarity is a distinctive attribute that makes exponential functions particularly helpful when modelling processes that grow or decay at rates proportional to their size, such as radioactive decay and population growth. Understanding exponential functions and their derivatives enables us to analyze these real-world phenomena with precision.

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Most popular questions from this chapter

Geometric and arithmetic means Given positive numbers \(x_{1}, \ldots, x_{n},\) prove that the geometric mean \(\left(x_{1} x_{2} \cdots x_{n}\right)^{1 / n}\) is no greater than the arithmetic mean \(\frac{x_{1}+\cdots+x_{n}}{n}\) in the following cases. a. Find the maximum value of \(x y z,\) subject to \(x+y+z=k\) where \(k\) is a positive real number and \(x>0, y>0,\) and Use the result to prove that $$(x y z)^{1 / 3} \leq \frac{x+y+z}{3}$$ b. Generalize part (a) and show that$$\left(x_{1} x_{2} \cdots x_{n}\right)^{1 / n} \leq \frac{x_{1}+\cdots+x_{n}}{n$$

a. Determine the domain and range of the following functions. b. Graph each function using a graphing utility. Be sure to experiment with the window and orientation to give the best perspective on the surface. $$g(x, y)=e^{-x y}$$

A baseball pitcher's earned run average (ERA) is \(A(e, i)=9 e / i\), where \(e\) is the number of earned runs given up by the pitcher and \(i\) is the number of innings pitched. Good pitchers have low ERAs. Assume \(e \geq 0\) and \(i>0\) are real numbers. a. The single-season major league record for the lowest ERA was set by Dutch Leonard of the Detroit Tigers in \(1914 .\) During that season, Dutch pitched a total of 224 innings and gave up just 24 earned runs. What was his ERA? b. Determine the ERA of a relief pitcher who gives up 4 earned runs in one- third of an inning. c. Graph the level curve \(A(e, i)=3\) and describe the relationship between \(e\) and \(i\) in this case.

Let \(P\) be a plane tangent to the ellipsoid \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}+\frac{z^{2}}{c^{2}}=1\) at a point in the first octant. Let \(T\) be the tetrahedron in the first octant bounded by \(P\) and the coordinate planes \(x=0, y=0,\) and \(z=0 .\) Find the minimum volume of \(T .\) (The volume of a tetrahedron is one-third the area of the base times the height.)

a. Determine the domain and range of the following functions. b. Graph each function using a graphing utility. Be sure to experiment with the window and orientation to give the best perspective on the surface. $$G(x, y)=\ln (2+\sin (x+y))$$

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