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Find an equation of the plane tangent to the following surfaces at the given points (two planes and two equations). $$x y+x z+y z-12=0 ;(2,2,2) \text { and }(2,0,6)$$

Short Answer

Expert verified
The equations of the tangent planes for the given points are: 1. $$x + y + z = 6$$ for point (2, 2, 2) 2. $$3x + 4y + (z - 6) = 6$$ for point (2, 0, 6)

Step by step solution

01

Find the gradient of the surface at the given points

First, let's find the partial derivatives of the given surface equation $$x y + x z + y z - 12 = 0$$ with respect to x, y, and z. To find the partial derivatives, differentiate the equation with respect to each variable while considering the other variables as constant. Partial derivative with respect to x: $$\frac{\partial}{\partial x} (x y + x z + y z - 12) = y + z$$ Partial derivative with respect to y: $$\frac{\partial}{\partial y} (x y + x z + y z - 12) = x + z$$ Partial derivative with respect to z: $$\frac{\partial}{\partial z} (x y + x z + y z - 12) = x + y$$ Now, let's find the gradient of the surface at each of the given points. At point (2, 2, 2), $$\nabla f(2, 2, 2) = (y + z, x + z, x + y)|_{(2,2,2)} = (4, 4, 4)$$ At point (2, 0, 6), $$\nabla f(2, 0, 6) = (y + z, x + z, x + y)|_{(2,0,6)} = (6, 8, 2)$$
02

Find the equation of the tangent plane using the gradient

Now that we have the gradients at the given points, we can find the equations of the tangent planes using the formula $$A(x - x_0) + B(y - y_0) + C(z - z_0) = 0$$ where $$A, B, C$$ are the components of the gradient, and $$(x_0, y_0, z_0)$$ is the point at which the tangent plane is to be found. For the point (2, 2, 2) with gradient (4, 4, 4), $$4(x - 2) + 4(y - 2) + 4(z - 2) = 0$$ Simplify the equation: $$x + y + z = 6$$ This is the equation of the tangent plane at point (2, 2, 2). For the point (2, 0, 6) with gradient (6, 8, 2), $$6(x - 2) + 8(y - 0) + 2(z - 6) = 0$$ Simplify the equation: $$3x + 4y + (z - 6) = 6$$ This is the equation of the tangent plane at point (2, 0, 6). So, the tangent plane equations for the given points are: 1. $$x + y + z = 6$$ for point (2, 2, 2) 2. $$3x + 4y + (z - 6) = 6$$ for point (2, 0, 6)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gradient in Calculus
The concept of a gradient is crucial when working with functions of multiple variables. In simple terms, the gradient of a function describes the direction and rate at which the function increases most rapidly. It is a vector that contains all the partial derivatives of the function. This makes the gradient particularly useful for determining the tangent plane to a surface at a specific point.

For a surface defined by the equation \(f(x, y, z) = 0\), the gradient \(abla f\) at any point \((x_0, y_0, z_0)\) represents the normal vector to the surface. The components of this gradient are obtained by taking the partial derivatives of the function with respect to each variable \(x, y,\) and \(z\).

When you compute the gradient at a point, you effectively find the direction of steepest ascent from that point on the surface. The gradient also serves as the set of coefficients \((A, B, C)\) in the equation of the tangent plane \(A(x - x_0) + B(y - y_0) + C(z - z_0) = 0\).

In our exercise, we calculated the gradient for the points (2, 2, 2) and (2, 0, 6) and used these to find the equations of the tangent planes at these points.
Understanding Partial Derivatives
Partial derivatives are a core component of calculus when dealing with functions that have more than one variable. A partial derivative measures how a function changes as one of its input variables changes, keeping the other variables constant. Think of it as peeling away layers to understand how change happens in one specific direction.

To find a partial derivative, you differentiate with respect to one variable and treat all other variables as constants. For example, if you have a surface given by the equation \(f(x, y, z) = xy + xz + yz - 12\), the partial derivative with respect to \(x\) would be \(\frac{\partial f}{\partial x} = y + z\). Similarly, you can find derivatives concerning \(y\) and \(z\), leading to \(\frac{\partial f}{\partial y} = x + z\) and \(\frac{\partial f}{\partial z} = x + y\), respectively.

These derivatives help in forming the gradient vector, which we can utilize to determine crucial characteristics of the surface, such as tangent planes at specific points as done in the original exercise. Understanding partial derivatives is essential for examining how functions behave and change in multiple dimensions.
Defining the Surface Equation
A surface equation in mathematics represents a set of points in three dimensions that satisfy a particular formula. This equation can be seen as defining a surface in a 3D space. Surface equations are integral to multivariable calculus as they represent the geometric places we study.

In the given exercise, the surface is defined by the equation \(xy + xz + yz - 12 = 0\). This surface is essentially a collection of all points \((x, y, z)\) that satisfy that specific equation. Defining such equations is fundamental for determining properties of the surfaces, such as identifying points where tangent planes can be drawn.

Understanding the role of a surface equation is crucial when you want to investigate characteristics like curvature and change along different directions. It forms the basis for calculating gradients and ultimately, for analyzing and representing 3D shapes mathematically, as demonstrated in the exercise.

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