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Find a function \(\mathbf{r}(t)\) that describes the curve where the following surfaces intersect. Answers are not unique. $$z=4 ; z=x^{2}+y^{2}$$ GRAPH CANT COPY

Short Answer

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Question: Find a vector function that describes the curve where the two surfaces z = 4 and z = x^2 + y^2 intersect. Answer: A possible vector function that describes the curve where the two surfaces z = 4 and z = x^2 + y^2 intersect is: $$\mathbf{r}(t) = \langle 2\cos(t), 2\sin(t), 4 \rangle$$

Step by step solution

01

Set the equations equal to each other.

Since both expressions are equal to \(z\), we can set them equal to each other: $$4 = x^2 + y^2$$
02

Parametrize the resulting equation.

We can re-write this equation in polar coordinates. By doing so, we can parametrize it easily: $$x = r \cos(\theta)$$ $$y = r \sin(\theta)$$ Substitute these expressions into the equation from step 1: $$4 = (r\cos(\theta))^2 + (r\sin(\theta))^2$$
03

Solve for r

Now, factor the equation: $$4 = r^2(\cos^2(\theta) + \sin^2(\theta))$$ Since \(\cos^2(\theta) + \sin^2(\theta) = 1\), we have: $$4 = r^2$$ Solve for r: $$r = 2$$
04

Define the vector function \(\mathbf{r}(t)\)

Now that we have the value of \(r\), we can create the vector function \(\mathbf{r}(t)\) using the polar coordinates and \(z=4\). We can let \(t=\theta\): $$\mathbf{r}(t) = \langle 2\cos(t), 2\sin(t), 4 \rangle$$ This is one possible vector function that describes the curve where the two surfaces intersect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
To understand how the intersection curve of two surfaces is found, we first need to grasp the underlying coordinate system used in the solution. Polar coordinates are an alternative to the Cartesian (rectangular) coordinate system most students are familiar with, where points are located based on an 'x' and 'y' grid.

Polar coordinates describe a point on a plane using a radius and an angle relative to the positive x-axis. These two values are typically denoted as \(r\) for the radius — the distance from the origin to the point — and \(\theta\) (theta) for the angle, measured in radians or degrees. The conversion between Cartesian and polar coordinates is crucial for solving many mathematical problems, especially when dealing with circles or curves:
  • \( x = r \cdot \cos(\theta) \)<\/li>
  • \( y = r \cdot \sin(\theta) \)<\/li>
Using these equations helps simplify the problem of finding intersections in circular or spherical scenarios, explaining why we opted for polar coordinates when trying to find the function describing our curve of intersection.
Vector Functions
In the solution process, we transitioned from a static representation of a point to a dynamic one using vector functions. A vector function is expressed in terms of a parameter (often time, denoted as \(t\)), producing a vector for each value of that parameter. In our context, the vector indicates the position of a point along a curve in three-dimensional space as the parameter changes.

For example, a vector function in the form \( \mathbf{r}(t) = \langle f(t), g(t), h(t) \rangle \) describes a curve by creating a vector from the origin to the point \( (f(t), g(t), h(t)) \) in 3D space for each \(t\). The components \(f(t)\), \(g(t)\), and \(h(t)\) correspond to the \(x\), \(y\), and \(z\) coordinates, which vary with the parameter \(t\). By using vector functions, we gain a powerful tool to map the motion or the path of a point (in our case, the curve of intersection) in a more generalized and visually descriptive manner.
Parametric Equations
Parametric equations are a set of equations that express a set of quantities as explicit functions of a number of independent variables, known as parameters. In the context of our intersection problem, the parametric equations are used to describe the geometry of curves and surfaces.

The process of parametrization involves expressing the coordinates of the points that lie on a curve by equations involving a parameter \(t\) that varies over an interval. This is beneficial since it allows for the tracing of a path in the plane or in space, providing a clear picture of the curve's shape and direction. Parametric equations, therefore, offer a flexible approach to describe complex curves that might be difficult to express with conventional functions.
In the solution, we used \(t\) as a stand-in for \(\theta\) in the polar coordinate system, which gave us the parametric equations needed to define the vector function \(\mathbf{r}(t) = \langle 2\cos(t), 2\sin(t), 4 \rangle\). This function succinctly encodes the entire path of the intersection curve in a form that's useful for further mathematical analysis or graphical representation.

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Most popular questions from this chapter

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