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Find the unit tangent vector \(\mathbf{T}\) and the principal unit normal vector \(\mathbf{N}\) for the following parameterized curves. In each case, verify that \(|\mathbf{T}|=|\mathbf{N}|=1\) and \(\mathbf{T} \cdot \mathbf{N}=0\). $$r(t)=\left\langle\cos t^{2}, \sin t^{2}\right\rangle$$.

Short Answer

Expert verified
Based on the solution, the unit tangent vector, \(\mathbf{T}\), for the given parameterized curve is \(\left\langle -\sin t^{2}, \cos t^{2} \right\rangle\), and the principal unit normal vector, \(\mathbf{N}\), is \(\left\langle -\cos t^{2}, -\sin t^{2} \right\rangle\). These vectors have a modulus of 1, and their dot product is 0, verifying their properties as unit tangent and principal unit normal vectors.

Step by step solution

01

Calculate the derivative of the curve with respect to t

We are given the curve \(r(t) = \left\langle\cos t^{2}, \sin t^{2}\right\rangle\). To find the tangent vector, we need to differentiate \(r(t)\) with respect to t. So, $$r'(t) = \left\langle \frac{d(\cos t^{2})}{dt}, \frac{d(\sin t^{2})}{dt} \right\rangle = \left\langle -2t\sin t^{2}, 2t\cos t^{2} \right\rangle.$$
02

Compute the unit tangent vector

To find the unit tangent vector, we need to normalize the tangent vector obtained in step 1. So, $$\mathbf{T} = \frac{r'(t)}{\vert r'(t) \vert} = \frac{ \left\langle -2t\sin t^{2}, 2t\cos t^{2}\right\rangle}{\sqrt{(-2t\sin t^{2})^{2} + (2t\cos t^{2})^{2}}},$$ $$\mathbf{T} = \frac{ \left\langle -2t\sin t^{2}, 2t\cos t^{2}\right\rangle}{2t},$$ $$\mathbf{T} = \left\langle -\sin t^{2}, \cos t^{2} \right\rangle .$$
03

Compute the derivative of the unit tangent vector with respect to t

To find the principal unit normal vector, we need to differentiate the unit tangent vector, \(\mathbf{T}\), with respect to t. So, $$\mathbf{T}'(t) = \left\langle -\frac{d(\sin t^{2})}{dt}, \frac{d(\cos t^{2})}{dt} \right\rangle = \left\langle -2t\cos t^{2}, -2t\sin t^{2} \right\rangle.$$
04

Compute the principal unit normal vector

To find the principal unit normal vector, we need to normalize the vector obtained in step 3. So, $$\mathbf{N} = \frac{\mathbf{T}'(t)}{\vert \mathbf{T}'(t) \vert} = \frac{ \left\langle -2t\cos t^{2}, -2t\sin t^{2}\right\rangle}{\sqrt{(-2t\cos t^{2})^{2} + (-2t\sin t^{2})^{2}}},$$ $$\mathbf{N} = \frac{ \left\langle -2t\cos t^{2}, -2t\sin t^{2}\right\rangle}{2t},$$ $$\mathbf{N} = \left\langle -\cos t^{2}, -\sin t^{2} \right\rangle .$$
05

Verify the properties

We need to check if \(|\mathbf{T}| = |\mathbf{N}| = 1\) and \(\mathbf{T} \cdot \mathbf{N} = 0\). Modulus of unit tangent vector: $$|\mathbf{T}| = \sqrt{(-\sin t^{2})^{2} + (\cos t^{2})^{2}} = \sqrt{\sin^2 t^{2} + \cos^2 t^{2}} = 1.$$ Modulus of principal unit normal vector: $$|\mathbf{N}| = \sqrt{(-\cos t^{2})^{2} + (-\sin t^{2})^{2}} = \sqrt{\cos^2 t^{2} + \sin^2 t^{2}} = 1.$$ Dot product of unit tangent vector and principal unit normal vector: $$\mathbf{T} \cdot \mathbf{N} = (-\sin t^{2})(-\cos t^{2}) + (\cos t^{2})(-\sin t^{2}) = 0.$$ Thus, \(|\mathbf{T}|=|\mathbf{N}|=1\) and \(\mathbf{T} \cdot \mathbf{N}=0\) are verified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parameterization
Parameterization is a way to represent curves and surfaces by defining a set of equations that depend on one or more parameters. In the context of curves, we often use a parameter like \(t\) to describe a curve's position with vector functions. For instance, the function \(r(t) = \langle \cos t^2, \sin t^2 \rangle\) describes a parameterized curve. Here, \(t\) varies over an interval, and as it does, the points generated outline the curve in a plane.
\[r(t)\] represents the curve, where \(\cos t^2\) and \(\sin t^2\) are the coordinates of points on the curve. Parameterization is crucial as it makes it simpler to explore the properties of the curve, like calculating tangents and normals. By having an explicit form dependent on \(t\), we can easily differentiate to find velocities and directions.
Curve Differentiation
Curve Differentiation refers to finding the derivatives of a curve鈥檚 components to study how the curve 鈥渕oves鈥 in space. This process involves calculating the derivatives of vector functions, allowing us to find velocity vectors. These are tangent to the curve, providing information on direction and magnitude.
  • Given a curve \(r(t) = \langle \cos t^2, \sin t^2 \rangle\), we differentiate each component with respect to \(t\) to determine its tangent vector \(r'(t)\).
  • Here, the derivative \( r'(t) = \langle -2t\sin t^2, 2t\cos t^2 \rangle\) shows the direction and steepness of the curve as \(t\) changes.
Understanding how to differentiate curves is fundamental, as it helps us analyze dynamic behaviors and calculate further derivatives for other important vectors like normals.
Unit Vectors
Unit vectors are vectors with a magnitude of one. They are used to represent directions without concern for magnitude. This is crucial when dealing with tangents and normals; unit vectors provide the direction of the curve at a point without length.
The process of creating a unit vector involves normalization, which means dividing a vector by its own magnitude:
  • For example, the unit tangent vector \(\mathbf{T}\) from \(\mathbf{T} = \frac{r'(t)}{|r'(t)|}\).
  • Similarly, the principal unit normal vector \(\mathbf{N}\) also involves normalizing another derivative vector.
This ensures that these vectors only describe direction, simplifying the analysis when studying orthogonal vectors and testing orthogonality.
Vector Magnitude
Vector Magnitude, also known as the length of a vector, is calculated using the Pythagorean theorem. For a vector \(\langle a, b \rangle\), its magnitude \(|\langle a, b \rangle|\) is \(\sqrt{a^2 + b^2}\). This concept is used in verifying unit vectors and ensuring normality between vectors.
In the problem, the magnitude is used in these checks:
  • For the unit vectors \(\mathbf{T}\) and \(\mathbf{N}\), verifying \(|\mathbf{T}| = |\mathbf{N}| = 1\) ensures they are correctly normalized.
Verifying magnitudes of unit vectors allows us to confirm their correctness, essential for maintaining orthogonality between vectors.
Dot Product
The Dot Product is an algebraic operation that takes two equal-length sequences of numbers (usually coordinate vectors) and returns a single number. This number can be interpreted as a measure of vectors' alignment.
For two vectors \(\mathbf{A} = \langle a_1, a_2 \rangle\) and \(\mathbf{B} = \langle b_1, b_2 \rangle\), the dot product is \(a_1b_1 + a_2b_2\).
In our problem, the dot product is used to confirm that two vectors are orthogonal:
  • For unit tangent vector \(\mathbf{T}\) and principal unit normal vector \(\mathbf{N}\), \(\mathbf{T} \cdot \mathbf{N} = 0\) verifies they are perpendicular.
This property is useful in vector mathematics and physics, where understanding perpendicularity and projection comes into play.

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