Chapter 13: Problem 9
Where does the plane \(-2 x-3 y+4 z=12\) intersect the coordinate axes?
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Chapter 13: Problem 9
Where does the plane \(-2 x-3 y+4 z=12\) intersect the coordinate axes?
These are the key concepts you need to understand to accurately answer the question.
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Symmetric equations for a line \(1 f\) we solve for t in the parametric equations of the line \(x=x_{0}+a t, y=y_{0}+b t, z=z_{0}+c t\) we obtain the symmetric equations $$ \frac{x-x_{0}}{a}=\frac{y-y_{0}}{b}=\frac{z-z_{0}}{c}$$ provided a, b, and c do not equal 0 Find parametric and symmetric equations of the line passing through the points \(P(1,-2,3)\) and \(Q(2,3,-1)\)
Prove that \(|c \mathbf{v}|=|c||\mathbf{v}|,\) where \(c\) is a scalar and \(\mathbf{v}\) is a vector.
Intersecting planes Find an equation of the line of intersection of the planes \(Q\) and \(R\) $$Q:-x+2 y+z=1 ; R: x+y+z=0$$
Prove the following identities. Assume \(\mathbf{u}, \mathbf{v}, \mathbf{w},\) and \(\mathbf{x}\) are nonzero vectors in \(\mathbb{R}^{3}\). $$(\mathbf{u} \times \mathbf{v}) \cdot(\mathbf{w} \times \mathbf{x})=(\mathbf{u} \cdot \mathbf{w})(\mathbf{v} \cdot \mathbf{x})-(\mathbf{u} \cdot \mathbf{x})(\mathbf{v} \cdot \mathbf{w})$$
Prove the following vector properties using components. Then make a sketch to illustrate the property geometrically. Suppose \(\mathbf{u}, \mathbf{v}\) and w are vectors in the xy-plane and a and c are scalars. $$(a+c) \mathbf{v}=a \mathbf{v}+c \mathbf{v} \quad \text { Distributive property } 2$$
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