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Find the volume of the solid that is bounded between the planes \(z=0\) and \(z=3\) and the cylinders \(y=x^{2}\) and \(y=2-x^{2}\).

Short Answer

Expert verified
Answer: The volume of the solid is 10 cubic units.

Step by step solution

01

Identify bounds for x and y

First, we need to find the intersection points of the cylinders \(y=x^{2}\) and \(y=2-x^{2}\). Set the two functions equal to each other: $$x^2 = 2 - x^2$$ Solve for x: $$2x^2 = 2$$ $$x^2 = 1$$ $$x = -1, 1$$ Now, find the corresponding y values when x=-1 and x=1: $$y=(1)^2=1$$ $$y=(-1)^2=1$$ The region we are integrating over is \(-1 \le x \le 1\) and \(0 \le y \le 2-x^2\).
02

Set up the double integral

Now, we set up the double integral using the bounds we found in step 1. The volume of the solid can be found by integrating: $$V = \int_{-1}^{1}\int_{0}^{2-x^2}(3) dy dx$$
03

Evaluate the inner integral

Integrate with respect to y: $$V = \int_{-1}^{1}[3y]_{0}^{2-x^2} dx$$ Simplify: $$V = \int_{-1}^{1} 3(2-x^2) dx$$
04

Evaluate the outer integral

Integrate with respect to x: $$V = [3(2x - \frac{x^3}{3})]_{-1}^{1}$$ Evaluate the expression at the limits of integration: $$=3(2(1)-\frac{1}{3})-3(2(-1)-\frac{1}{3})$$ Simplify: $$=3(\frac{5}{3}+\frac{5}{3})$$ $$V=10$$ The volume of the solid bounded between the planes \(z=0\) and \(z=3\) and the cylinders \(y=x^{2}\) and \(y=2-x^{2}\) is 10 cubic units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Double Integral
The double integral is a powerful tool in calculus used to calculate the volume under a surface or the area of a plane region. In the context of volume calculation, the double integral allows us to sum up infinitely many infinitesimally small volumes of slices to find the total volume of a solid.

When we set up a double integral for volume, we're essentially looking at the solid one slice at a time, each represented by an area element. Each slice has a small area, and when we multiply it by the height, we get the volume of that thin slice. By integrating over the entire region of interest, we sum these tiny volumes to find the total volume.

Our exercise involves setting up a double integral over the region between two cylinders. We integrate the height function, which in this case is constant, across the area of interest, which gives us the volume of the solid between the specified bounds.
Volume Calculation
Volume calculation in mathematics is the process of determining the amount of space inside a three-dimensional shape. Various techniques exist to calculate volumes, depending on the complexity and symmetry of the objects involved.

For regular shapes, formulas derived from geometry are typically used. However, for irregular or bounded solids, integrals become indispensable. The double integral we've seen is specifically useful when we cannot easily dissect the solid into simpler geometric figures. It's especially helpful when dealing with volumes bounded by curves or surfaces that aren't flat.

In the textbook solution, the volume was calculated using a double integral. Such problems generally require evaluating two successive integrals, as shown in the solution, where we integrated first with respect to y and then with respect to x.
Cylindrical Coordinates
Cylindrical coordinates are a set of three coordinates that define a point in space by how far away it is from a reference axis (radius), the angle around that axis from a reference direction (azimuth), and the distance above or below a reference plane (height). These coordinates are analogous to cylindrical shapes, hence the name.

Cylindrical coordinates are particularly useful when dealing with problems that exhibit cylindrical symmetry, as the equations describing the shapes or boundaries become more manageable. Although they were not directly used in this exercise, understanding them can be very helpful in similar volume calculations. If the problem required integrating over a circular region, or if the heights of the solid had variation depending on radial position, then transforming the problem into cylindrical coordinates would be advantageous.
Solid Boundaries
Solid boundaries in the context of volume calculations refer to the limits beyond which the solid does not extend. Determining the solid boundaries is crucial for setting up the correct limits of integration for calculating volumes.

In the given exercise, the solid boundaries are the planes at z=0 and z=3, and the cylinders defined by the equations y=x^2 and y=2-x^2. By finding where these cylinders intersect, we define the limits for x, which turn out to be -1 to 1. Moreover, the bounds for y are determined by the values of x within the region of these intersections.

Identifying these boundaries allows us to integrate across the correct limits, leading to the accurate volume of the solid. Properly understanding and identifying the boundaries are essential steps before performing any volume calculation with an integral.

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