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Which has a greater horizontal component, a \(100-\mathrm{N}\) force directed at an angle of \(60^{\circ}\) above the horizontal or a \(60-\mathrm{N}\) force directed at an angle of \(30^{\circ}\) above the horizontal?

Short Answer

Expert verified
Answer: The 60-N force directed at an angle 30° above the horizontal has a greater horizontal component (approximately 51.96 N) compared to the 100-N force directed at an angle 60° above the horizontal (50 N).

Step by step solution

01

Calculate the horizontal component of the first force

To find the horizontal component of the \(100\mathrm{-N}\) force, we will use the formula \(F_x = F \cos \theta\). In this case, we have \(F = 100\mathrm{-N}\) and \(\theta = 60^{\circ}\). Let's plug these values into the formula: \(F_x = 100\mathrm{-N} \cdot \cos 60^{\circ}\) Keep in mind to convert degrees to radians before using the cosine function. We know that \(60^{\circ}\) is equal to \(\frac{\pi}{3}\) radians, so the calculation becomes: \(F_x = 100\mathrm{-N} \cdot \cos \frac{pi}{3}\) After calculating this, we have: \(F_x = 50\mathrm{-N}\) So, the horizontal component for the first force is \(50\mathrm{-N}\).
02

Calculate the horizontal component of the second force

Now, let's find the horizontal component of the \(60\mathrm{-N}\) force using the same formula \(F_x = F \cos \theta\). This time, we have \(F = 60\mathrm{-N}\) and \(\theta = 30^{\circ}\). Plug these values into the formula: \(F_x = 60\mathrm{-N} \cdot \cos 30^{\circ}\) Again, convert degrees to radians, so \(30^{\circ}\) is equal to \(\frac{\pi}{6}\) radians. The calculation becomes: \(F_x = 60\mathrm{-N} \cdot \cos \frac{pi}{6}\) After calculating this, we have: \(F_x = 60\mathrm{-N}\cdot \frac{\sqrt{3}}{2}\) \(F_x \approx 51.96\mathrm{-N}\) So, the horizontal component for the second force is approximately \(51.96\mathrm{-N}\).
03

Compare the horizontal components

Now that we have the horizontal components for both forces, we can compare them: - First force horizontal component: \(50\mathrm{-N}\) - Second force horizontal component: \(51.96\mathrm{-N}\) (approximately) Since \(51.96\mathrm{-N}\) is greater than \(50\mathrm{-N}\), the \(60\mathrm{-N}\) force directed at an angle of \(30^{\circ}\) above the horizontal has a greater horizontal component.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Functions
Trigonometric functions are vital in physics when analyzing forces. They help us break down complex problems into more manageable components. When dealing with forces at an angle, the cosine function is particularly useful. It relates the angle of a force to its horizontal component. For a force vector at an angle \(\theta\), the horizontal component, denoted as \(F_x\), can be calculated using the formula \(F_x = F \cos \theta\). Here, \(F\) represents the magnitude of the force.

By using the cosine function, you can easily determine how much of a force is directed along the horizontal axis. This is essential when you're trying to understand the total impact of angled forces in practical situations. Cosine, being a periodic function, ensures that the angle measurement accurately reflects the true horizontal impact of any force.

Whenever you're addressing a problem involving force deconstruction, it is crucial to grasp how cosine can assist in understanding how much of the force impacts the horizontal plane.
Vector Decomposition
Vector decomposition is a technique used in physics to simplify the analysis of forces. When a force is applied at an angle, it can be broken down into two perpendicular components: horizontal and vertical. By doing this, we can evaluate each component individually, making problem-solving more approachable.

To decompose a force vector, imagine a right triangle, where the force is the hypotenuse. The horizontal component is adjacent to the angle, while the vertical component is opposite. The trigonometric functions, cosine, and sine are used, respectively. We calculate the horizontal component as \(F_x = F \cos \theta\) and the vertical component as \(F_y = F \sin \theta\).

Understanding vector decomposition is essential, as it allows students to assess the direction and magnitude of forces more accurately. This skill is especially useful when analyzing physical systems where forces do not act purely along one axis. With vector decomposition, determining resultant forces becomes an accessible task.
Angle Conversion
Angle conversion often plays a crucial role when working with trigonometric functions related to physics problems. In mathematics, angles can be measured in degrees or radians. However, many trigonometric calculations, especially those involving scientific calculators or programming, require angles to be measured in radians.

Converting from degrees to radians involves multiplying the degree measurement by \(\frac{\pi}{180}\). This conversion ensures that functions like cosine and sine are applied correctly. For example, to convert \(60^{\circ}\) to radians, we calculate \(60\times\frac{\pi}{180} = \frac{\pi}{3}\) radians. Similarly, \(30^{\circ}\) becomes \(\frac{\pi}{6}\) radians.

Being comfortable converting between degrees and radians is a valuable skill in physics and engineering. It helps you adapt to various calculation requirements and ensures the accuracy of your results. Mastering angle conversion also builds a foundation for exploring more advanced topics involving rotational motion and periodic functions.

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