/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Define the points \(P(-4,1), Q(3... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Define the points \(P(-4,1), Q(3,-4),\) and \(R(2,6)\). Express \( {P Q}\) in the form \(a \mathbf{i}+b \mathbf{j}\)

Short Answer

Expert verified
Question: Determine the vector that starts from point P(-4, 1) and ends at point Q(3, -4). Answer: The vector PQ is given as \(\mathbf{PQ} = 7\mathbf{i}-5\mathbf{j}\).

Step by step solution

01

Find the position vectors of P and Q

The position vector of point P is denoted by \(\mathbf{P} = -4 \mathbf{i} + 1 \mathbf{j}\) and the position vector of point Q is \(\mathbf{Q} = 3 \mathbf{i} - 4 \mathbf{j}\).
02

Find the difference between the position vectors

To find the vector from point P to Q, subtract the position vector of P from the position vector of Q as follows:$$\mathbf{PQ} = \mathbf{Q} - \mathbf{P}$$
03

Calculate the vector PQ

Now, calculate the vector PQ using the information from step 2:$$\mathbf{PQ} = (3 \mathbf{i} - 4 \mathbf{j}) - (-4 \mathbf{i} + 1 \mathbf{j}) = 7 \mathbf{i} - 5 \mathbf{j}$$ The vector PQ is given as \(\mathbf{PQ} = 7\mathbf{i}-5\mathbf{j}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position Vectors
A position vector is a vector that denotes a specific location in space. It is often depicted in terms of components, such as along the horizontal and vertical axes in a coordinate system. For example, the position vector of a point in a two-dimensional plane is represented as \( a \mathbf{i} + b \mathbf{j} \), where \( a \) and \( b \) are the coordinates of the point on the x-axis and y-axis, respectively.

Position vectors are fundamental in understanding the location of a point and providing a basis to perform vector operations, such as addition or subtraction. Since each position vector originates from the origin and extends to a point in the plane, it provides insight into how the point is positioned relative to the origin. In this exercise, the position vectors of points \(P(-4,1)\) and \(Q(3,-4)\) are \(\mathbf{P} = -4 \mathbf{i} + 1 \mathbf{j}\) and \(\mathbf{Q} = 3 \mathbf{i} - 4 \mathbf{j}\) respectively. This representation frames the points in a way that sets the stage for operations, such as vector subtraction, that can determine directional relationships between points.
Vector Subtraction
Vector subtraction is an essential operation when dealing with vectors. It allows you to find the direction and magnitude from one point to another in space. To subtract one vector from another, you simply subtract the corresponding components of the vectors.

In the context of position vectors, subtracting the vector of one point from the vector of another gives you the vector that points from the first to the second point. For instance, to find vector \( \mathbf{PQ} \), which represents the vector from point \( P \) to point \( Q \), we perform the subtraction: \( \mathbf{PQ} = \mathbf{Q} - \mathbf{P} \).

Here's a breakdown of our exercise:
  • The position vector of \(Q\) is \(3 \mathbf{i} - 4 \mathbf{j}\).
  • The position vector of \(P\) is \(-4 \mathbf{i} + 1 \mathbf{j}\).
  • We calculate \( \mathbf{PQ} = (3 \mathbf{i} - 4 \mathbf{j}) - (-4 \mathbf{i} + 1 \mathbf{j}) \).
Performing this subtraction, we get \( 7 \mathbf{i} - 5 \mathbf{j} \), which gives us both the direction and the "distance" from \(P\) to \(Q\).
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a field of mathematics that uses algebraic equations to describe and analyze geometric shapes and their properties in a coordinate system.

This system allows the use of coordinates to uniquely position points in the plane, which is integral for solving many geometric problems. Through the coordinate system, the connections and interactions of geometric figures, like lines and curves, with algebraic equations are established.

For example, consider points \(P(-4,1)\) and \(Q(3,-4)\) in the exercise. These points are identified with a coordinate pair indicating their location on the plane relative to the axes. The application of vector operations, such as finding the vector \(\mathbf{PQ}\), becomes feasible through the simplicity of these coordinate representations.

Using coordinate geometry, we also define geometric features like distances, midpoints, and slopes through coordinate systems, enhancing our ability to comprehend and demonstrate geometric relationships via vector operations in a straightforward manner.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe with a sketch the sets of points \((x, y, z)\) satisfing the following equations. $$x^{2} y^{2} z^{2}>0$$

Parallel vectors of varying lengths Find vectors parallel to \(\mathbf{v}\) of the given length. $$\mathbf{v}=\langle 3,-2,6\rangle ; \text { length }=10$$

In contrast to the proof in Exercise \(83,\) we now use coordinates and position vectors to prove the same result. Without loss of generality, let \(P\left(x_{1}, y_{1}, 0\right)\) and \(Q\left(x_{2}, y_{2}, 0\right)\) be two points in the \(x y\) -plane, and let \(R\left(x_{3}, y_{3}, z_{3}\right)\) be a third point such that \(P, Q,\) and \(R\) do not lie on a line. Consider \(\Delta P Q R\) a. Let \(M_{1}\) be the midpoint of the side \(P Q .\) Find the coordinates of \(M_{1}\) and the components of the vector \(R M_{1}\) b. Find the vector \(\overrightarrow{O Z}_{1}\) from the origin to the point \(Z_{1}\) two-thirds of the way along \(\hat{R} \vec{M}_{1}\) c. Repeat the calculation of part (b) with the midpoint \(M_{2}\) of \(R Q\) and the vector \(P M_{2}\) to obtain the vector \(\overline{O Z}_{2}\) d. Repeat the calculation of part (b) with the midpoint \(M_{3}\) of \(P R\) and the vector \(Q M_{3}\) to obtain the vector \(\overline{O Z}_{3}\) e. Conclude that the medians of \(\Delta P Q R\) intersect at a point. Give the coordinates of the point. f. With \(P(2,4,0), Q(4,1,0),\) and \(R(6,3,4),\) find the point at which the medians of \(\Delta P Q R\) intersect.

Lines normal to planes Find an equation of the following lines. The line passing through the point \(P_{0}(0,-10,-3)\) that is normal to the plane \(x+4 z=2\)

Intersecting planes Find an equation of the line of intersection of the planes \(Q\) and \(R\) $$Q: x+2 y-z=1 ; R: x+y+z=1$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.