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Describe the plane \(x=4\)

Short Answer

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Question: Describe the unique properties of the plane with the equation \(x=4\), including its orientation, points that lie on the plane, and perpendicular vector. Answer: The plane \(x=4\) has the following unique properties: It is parallel to the \(yz\)-plane, has points such as \((4, 0, 0)\) lying on it, and has a perpendicular vector of \(\begin{bmatrix}1 \\ 0 \\ 0 \end{bmatrix}\).

Step by step solution

01

Identify the orientation of the plane

The given equation is \(x=4\). We can directly identify the plane's orientation by analyzing the equation. Since there is only one variable (\(x\)) and its coefficient is 1, this plane is parallel to the \(yz\)-plane. It's important to remember that planes parallel to the \(yz\)-plane have equations of the form \(x=k\), where \(k\) is a constant value.
02

Find a point on the plane

Since the plane's equation is \(x=4\), any point with an \(x\)-coordinate of 4 will lie on the plane. An easy point to choose is \((4, 0, 0)\), however, other points such as \((4, 1, 1)\), \((4, -2, 3)\), or \((4, y, z)\), where \(y\) and \(z\) are any real numbers, will also lie on the plane.
03

Determine the perpendicular vector

A vector that is perpendicular to the given plane can be used to describe the plane. Since the plane is parallel to the \(yz\)-plane, the normal vector can be directly determined as \(\begin{bmatrix}1 \\ 0 \\ 0 \end{bmatrix}\). This is because a vector parallel to the \(x\)-axis will be perpendicular to any plane parallel to the \(yz\)-plane. To summarize, the given plane \(x=4\) is parallel to the \(yz\)-plane, has points such as \((4, 0, 0)\) lying on it, and has a perpendicular vector of \(\begin{bmatrix}1 \\ 0 \\ 0 \end{bmatrix}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Plane Equations
Understanding the concept of plane equations in three-dimensional geometry is crucial when visualizing and solving problems in 3D space. A plane equation relates to a flat, two-dimensional surface that extends indefinitely in three-dimensional space. When we come across an equation like \(x=4\), it's an example of a plane that is parallel to the other two axes - in this case, the \(yz\)-plane. The reason this type of equation is so streamlined is due to the fact that the \(x\)-value is constant, meaning no matter what values of \(y\) or \(z\) you choose, the \(x\)-coordinate of any point on the plane will always be 4.

To more comprehensively visualize plane equations, it's beneficial to identify a particular point that lies on the plane as a reference. Any point with the \(x\)-coordinate of 4, such as \((4, 0, 0)\), will satisfy the equation \(x=4\). Thus, the equation itself represents an infinite set of points constituting a flat surface parallel to the \(yz\)-plane. This concept can be extended to all three dimensions, with variations such as \(y=k\) or \(z=k\) representing planes parallel to the other principal planes.
Three-dimensional Coordinate Geometry
Navigating through three-dimensional coordinate geometry is akin to exploring a space where every location can be pinpointed by three coordinates, \(x\), \(y\), and \(z\). This introduces an additional dimension to our conventional 2D plane, necessitating a greater understanding of how these coordinates interact to define points, lines, and planes in 3D space.

For example, the equation \(x=4\) serves to describe a plane in this 3D realm. This plane slices through the voluminous 3D space at every point where the \(x\)-coordinate value equals 4. It provides a clear illustration of how 3D coordinate geometry allows us to define endless flat surfaces—planes—within our three-dimensional environment. Using such plane equations aids in visualizing complex structures and facilitates solving geometric problems that involve multiple planes and their intersections.
Normal Vectors
In three-dimensional spaces, normal vectors are indispensable for identifying the orientation of planes. A normal vector is perpendicular (orthogonal) to the plane it represents. In our specific exercise, the normal vector to the plane \(x=4\) is \(\begin{bmatrix}1 \ 0 \ 0 \end{bmatrix}\), which suggests that it points along the positive direction of the \(x\)-axis.

Having a normal vector (vector perpendicular to a plane) is particularly practical when it comes to defining the plane's orientation. It's also a fundamental component in advanced geometric calculations, such as finding the angle between two planes or establishing the equation of a plane given three points. It all boils down to the pivotal role that normal vectors play in the application and comprehension of geometric concepts within the three-dimensional coordinate system.

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