/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 Find the arc length of the follo... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the arc length of the following curves on the given interval. $$x=3 \cos t, y=3 \sin t+1 ; 0 \leq t \leq 2 \pi$$

Short Answer

Expert verified
Answer: The arc length of the curve is \(6\pi\).

Step by step solution

01

Derivative of x(t) with respect to t

To find the derivative of \(x(t) = 3\cos{t}\) with respect to \(t\), differentiate the given function using the chain rule: $$ \frac{dx}{dt}=-3 \sin{t} $$
02

Derivative of y(t) with respect to t

To find the derivative of \(y(t) = 3\sin{t} + 1\) with respect to \(t\), differentiate the function with respect to \(t\): $$ \frac{dy}{dt}=3 \cos{t} $$ Step 2: Square the derivatives and add them
03

Squaring the derivatives and adding them

Square the derivatives calculated in step 1 and add them as per the formula: $$ \left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2=(-3\sin{t})^2+(3\cos{t})^2=9\sin^2{t}+9\cos^2{t} $$ Step 3: Calculate the square root of the sum
04

Square root of the sum

Take the square root of the sum found in step 2: $$ \sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2}=\sqrt{9\sin^2{t}+9\cos^2{t}}=3\sqrt{\sin^2{t}+\cos^2{t}} $$ Since \(\sin^2{t}+\cos^2{t}=1\), we get: $$ \sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2}=3 $$ Step 4: Integrate the result over the interval \(0 \leq t \leq 2\pi\)
05

Integrating the square root

Now integrate the square root of the sum over the interval \(0 \leq t \leq 2\pi\) using the arc length formula: $$ L=\int_{0}^{2\pi}3\,dt $$ This is a simple integral, resulting in: $$ L = 3t\Big|_0^{2\pi}=3(2\pi)-3(0)=6\pi $$ Therefore, the arc length of the curve on the given interval is \(6\pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Parametric equations are a powerful way to describe shapes and curves in the plane. Instead of using just one equation involving \(x\) and \(y\), parametric equations express both \(x\) and \(y\) as functions of a third variable, commonly \(t\), called the parameter. This parameter often represents time or another changing quantity that determines the position of a point on a curve.
In the given exercise, the pair of equations \(x=3\cos t\) and \(y=3\sin t+1\) describe a circle with a radius of 3, centered at the point (0,1). As the parameter \(t\) varies from \(0\) to \(2\pi\), the point (x,y) traces a complete circle in the plane.
Using parametric equations can make it easier to work with curves involving circles, ellipses, and other complex shapes. They allow for seamless differentiation and integration, which are essential for finding properties like arc length, as shown in this problem.
Integration
Integration is a fundamental mathematical tool used to calculate many properties, including areas under curves and arc lengths. It allows us to sum up infinitesimally small quantities to find a total effect or quantity over an interval.
In our problem, once the derivatives are squared and summed, we need to find its integral to compute the arc length. The arc length \(L\) for a curve described by parametric equations \(x(t)\) and \(y(t)\) over the interval \(t=a\) to \(t=b\) is given by:
  • \(L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2} \, dt\)
Here, the integral collects the infinitesimal lengths along the curve from start to finish. It's noted in our solution that integrating \(3\) over the interval \([0, 2\pi]\) yields \(6\pi\), giving us the total arc length of the circle.
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all values where both sides of the equality are defined. They are extremely useful in simplifying calculations and solving problems involving trigonometric functions.
One of the most fundamental identities used in this problem is the Pythagorean Identity, which states:
  • \(\sin^2 t + \cos^2 t = 1\)
This identity was used to simplify the expression \(9\sin^2 t + 9\cos^2 t\) to \(9\), aiding in the calculation of the arc length. Understanding and mastering these identities make manipulating and simplifying trigonometric expressions much easier, especially when involved in integration and differentiation tasks as seen here.

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Most popular questions from this chapter

Parametric equations of ellipses Find parametric equations (not unique) of the following ellipses. Graph the ellipse and find a description in terms of \(x\) and \(y\). An ellipse centered at the origin with major axis of length 6 on the \(x\) -axis and minor axis of length 3 on the \(y\) -axis, generated counterclockwise

Use a graphing utility to graph the parabolas \(r=\frac{d}{1+\cos \theta}\) for \(d=0.25,0.5,1,2,3,\) and 4 on the same set of axes. Explain how the shapes of the curves vary as \(d\) changes.

Show that an ellipse and a hyperbola that have the same two foci intersect at right angles.

A idealized model of the path of a moon (relative to the Sun) moving with constant speed in a circular orbit around a planet, where the planet in turn revolves around the Sun, is given by the parametric equations $$x(\theta)=a \cos \theta+\cos n \theta, y(\theta)=a \sin \theta+\sin n \theta$$ The distance from the moon to the planet is taken to be 1 , the distance from the planet to the Sun is \(a\), and \(n\) is the number of times the moon orbits the planet for every 1 revolution of the planet around the Sun. Plot the graph of the path of a moon for the given constants; then conjecture which values of \(n\) produce loops for a fixed value of \(a\) a. \(a=4, n=3\) b. \(a=4, n=4\) c. \(a=4, n=5\)

Show that an equation of the line tangent to the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) at the point \(\left(x_{0}, y_{0}\right)\) is $$\frac{x x_{0}}{a^{2}}+\frac{y y_{0}}{b^{2}}=1$$

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