Chapter 12: Problem 79
Find the length of the entire spiral \(r=e^{-a \theta},\) for \(\theta \geq 0\) and \(a>0\).
Short Answer
Expert verified
Answer: The length of the entire spiral is given by \(L = \frac{\sqrt{1 + a^2}}{a}\).
Step by step solution
01
Find the derivative of r with respect to θ
First, we need to find the derivative of \(r\) with respect to \(\theta\). Given the polar equation \(r = e^{-a \theta}\), we have:
$$\frac{dr}{d\theta} = -ae^{-a \theta}$$
02
Substitute r and dr/dθ into the arc length formula
Now we will substitute \(r = e^{-a \theta}\) and \(\frac{dr}{d\theta} = -ae^{-a \theta}\) into the arc length formula:
$$L = \int_0^\infty \sqrt{\left(e^{-a \theta}\right)^2 + \left(-ae^{-a \theta}\right)^2} d\theta$$
03
Simplify the integrand
Simplify the expression inside the square root:
$$L = \int_0^\infty \sqrt{e^{-2a \theta} + a^2e^{-2a \theta}} d\theta$$
Factor out \(e^{-2a\theta}\):
$$L = \int_0^\infty \sqrt{e^{-2a \theta}(1 + a^2)} d\theta$$
Take out the constant factor from the square root:
$$L = \int_0^\infty \sqrt{1 + a^2} \cdot e^{-a \theta} d\theta$$
04
Calculate the integral
Now we calculate the integral:
$$L = \sqrt{1 + a^2} \int_0^\infty e^{-a \theta} d\theta$$
This is an exponential integral, which can be solved using integration by part or by looking up in a table of integrals. The result is:
$$L = \sqrt{1 + a^2} \left[-\frac{1}{a}e^{-a \theta}\right]_0^\infty$$
05
Evaluate the integral
Now we evaluate the integral at the limits:
$$L = \sqrt{1 + a^2} \left[\left(-\frac{1}{a}e^{-a \infty}\right) - \left(-\frac{1}{a}e^{-a \cdot 0}\right)\right]$$
Simplifying the terms:
$$L = \sqrt{1 + a^2} \left[0 - \left(-\frac{1}{a}\right)\right]$$
$$L = \frac{\sqrt{1 + a^2}}{a}$$
06
Present the final result
The length of the entire spiral for the given polar equation \(r = e^{-a \theta}\), where \(\theta \geq 0\) and \(a > 0\), is:
$$L = \frac{\sqrt{1 + a^2}}{a}$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates are an alternative way to represent points on a plane, different from the familiar Cartesian (x, y) coordinates. Instead of using horizontal and vertical distances from a reference point, polar coordinates use:
Polar coordinates can be converted to Cartesian coordinates with equations:
- The distance from the origin, represented by \(r\).
- The angle \(\theta\) from the positive x-axis.
Polar coordinates can be converted to Cartesian coordinates with equations:
- \(x = r \cos(\theta)\)
- \(y = r \sin(\theta)\)
Exponential Functions
Exponential functions are mathematical functions of the form \(f(x) = a^x\), where \(a\) is a constant and \(x\) is the variable. In our spiral equation, we have an exponential function \(r = e^{-a\theta}\), where \(e\) is the base of natural logarithms, approximately equal to 2.71828. The significance of exponential functions includes:
- Rapid growth (if the exponent is positive).
- Rapid decay (if the exponent is negative).
Integration Techniques
Integration is a fundamental concept in calculus used to find areas under curves and solve differential equations. When calculating arc lengths, like for the spiral \(r = e^{-a\theta}\), integration is crucial to determine the length along the curved path. The arc length formula in polar coordinates is:
- \(L = \int_a^b \sqrt{\left(\frac{dr}{d\theta}\right)^2 + r^2} \,d\theta\).
- Integration by parts.
- Simplifying the integrand using algebraic techniques.
- Using known integral tables for exponential and trigonometric functions.