Chapter 12: Problem 5
Find parametric equations for the complete parabola \(x=y^{2} .\) Answers are not unique.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 12: Problem 5
Find parametric equations for the complete parabola \(x=y^{2} .\) Answers are not unique.
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Find the arc length of the following curves on the given interval. $$x=2 t \sin t-t^{2} \cos t, y=2 t \cos t+t^{2} \sin t ; 0 \leq t \leq \pi$$
Suppose two hyperbolas with eccentricities \(e\) and \(E\) have perpendicular major axes and share a set of asymptotes. Show that \(e^{-2}+E^{-2}=1\).
Let \(C\) be the curve \(x=f(t)\), \(y=g(t),\) for \(a \leq t \leq b,\) where \(f^{\prime}\) and \(g^{\prime}\) are continuous on \([a, b]\) and C does not intersect itself, except possibly at its endpoints. If \(g\) is nonnegative on \([a, b],\) then the area of the surface obtained by revolving C about the \(x\)-axis is $$S=\int_{a}^{b} 2 \pi g(t) \sqrt{f^{\prime}(t)^{2}+g^{\prime}(t)^{2}} d t$$. Likewise, if \(f\) is nonnegative on \([a, b],\) then the area of the surface obtained by revolving C about the \(y\)-axis is $$S=\int_{a}^{b} 2 \pi f(t) \sqrt{f^{\prime}(t)^{2}+g^{\prime}(t)^{2}} d t$$ (These results can be derived in a manner similar to the derivations given in Section 6.6 for surfaces of revolution generated by the curve \(y=f(x)\).) Consider the curve \(x=3 \cos t, y=3 \sin t+4,\) for \(0 \leq t \leq 2 \pi\) a. Describe the curve. b. If the curve is revolved about the \(x\) -axis, describe the shape of the surface of revolution and find the area of the surface.
Graph the following equations. Then use arrows and labeled points to indicate how the curve is generated as \(\theta\) increases from 0 to \(2 \pi\). $$r=\frac{1}{1-2 \cos \theta}$$
Use polar coordinates to determine the area bounded on the right by the unit circle \(x^{2}+y^{2}=1\) and bounded on the left by the vertical line \(x=\sqrt{2} / 2\).
What do you think about this solution?
We value your feedback to improve our textbook solutions.