Chapter 11: Problem 57
Representing functions by power series Identify the functions represented by the following power series. $$\sum_{k=0}^{\infty}(-1)^{k} \frac{x^{2 k}}{4^{k}}$$
Short Answer
Expert verified
Answer: The function represented by the given power series is \(f(x) = \frac{4}{4+ x^2}\), and it converges for \(|x^2|<4\).
Step by step solution
01
Rewrite the power series
First, let's rewrite the power series so that we can see the coefficients more clearly:
$$f(x) = \sum_{k=0}^{\infty}(-1)^{k} \frac{x^{2 k}}{4^{k}} = \sum_{k=0}^{\infty} \left(-\frac{x^2}{4}\right)^{k}$$
We can recognize the power series as a geometric series with \(a_0=1\) and common ratio \(r=-\frac{x^2}{4}\). The geometric series converges only if the absolute value of the common ratio is less than 1, i.e., \(|-\frac{x^2}{4}|<1\) or \(|x^2|<4\).
02
Find the general formula for a geometric series
Before going further, let's remind ourselves of the general formula for the sum of an infinite geometric series:
$$S_{\infty} = \frac{a_0}{1-r} \text{ if } |r|<1$$
03
Apply the general formula to our power series
Now we can apply the general formula to our power series we found in step 1:
$$f(x)= \frac{1}{1-\left(-\frac{x^2}{4}\right)}$$
Since this series converges only if \(|x^2|<4\), this formula for the function is valid only within the radius of convergence.
04
Simplify the function
Simplify the function to find the final answer:
$$f(x) = \frac{1}{1+\frac{x^2}{4}} = \frac{4}{4+ x^2}$$
So, the function represented by the given power series is:
$$f(x) = \frac{4}{4+ x^2}, \text{where } |x^2|<4$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a type of series where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. This series can be represented as:
- First Term (\( a_0 \))
- Common Ratio (\( r \))
- Total Sum (\( S \))
- First term \( a_0 = 1 \)
- Common ratio \( r = -\frac{x^2}{4} \)
Convergence
Convergence is a fundamental concept in calculus and series. It refers to the behavior of a series as the number of terms grows indefinitely. A series converges if the sum of its terms approaches a specific value.
A geometric series converges under the condition \(|r| < 1\), meaning the absolute value of the common ratio should be less than 1. For our power series, the condition for convergence is \(|-\frac{x^2}{4}|<1\) or further simplified, \(|x^2|<4\).
Once convergence is established, we can use the sum formula for the geometric series, \( S_{\infty} = \frac{a_0}{1-r} \), to find the sum of the series in question. Convergence is essential to ensure that the sum is well-defined and leads to a valid function representation.
A geometric series converges under the condition \(|r| < 1\), meaning the absolute value of the common ratio should be less than 1. For our power series, the condition for convergence is \(|-\frac{x^2}{4}|<1\) or further simplified, \(|x^2|<4\).
Once convergence is established, we can use the sum formula for the geometric series, \( S_{\infty} = \frac{a_0}{1-r} \), to find the sum of the series in question. Convergence is essential to ensure that the sum is well-defined and leads to a valid function representation.
Function Representation
The power of representing functions as series lies in the ability to express complex functions in simpler terms. A power series is essentially an infinite polynomial, which makes it adaptable for various functions.
In our example, the given series\( \sum_{k=0}^{\infty} \left(-\frac{x^2}{4}\right)^{k} \) is expressed as \( f(x) = \frac{4}{4+x^2} \).
By using the geometric series sum formula, we have transformed the infinite series into a simple rational function that is easier to work with. This representation is valid within the radius of convergence, offering a neat and effective way to deal with complex expressions.
In our example, the given series\( \sum_{k=0}^{\infty} \left(-\frac{x^2}{4}\right)^{k} \) is expressed as \( f(x) = \frac{4}{4+x^2} \).
By using the geometric series sum formula, we have transformed the infinite series into a simple rational function that is easier to work with. This representation is valid within the radius of convergence, offering a neat and effective way to deal with complex expressions.
Radius of Convergence
The radius of convergence is a measure that specifies the interval within which a power series converges to a function. When discussing power series, it's crucial to determine where the series converges.
For the power series \( \sum_{k=0}^{\infty} \left(-\frac{x^2}{4}\right)^{k} \), the condition \(|x^2|<4\) translates to \(|x|<2\) after taking the square root.
For the power series \( \sum_{k=0}^{\infty} \left(-\frac{x^2}{4}\right)^{k} \), the condition \(|x^2|<4\) translates to \(|x|<2\) after taking the square root.
- Within this interval (\(|x| < 2\)), the power series converges to the function \( f(x) = \frac{4}{4+x^2} \).