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For what values of \(p\) does the series \(\sum_{k=10}^{\infty} \frac{1}{k^{p}}\) converge (initial index is 10 )? For what values of \(p\) does it diverge?

Short Answer

Expert verified
Answer: The series converges for \(p > 1\) and diverges for \(p \leq 1\).

Step by step solution

01

Identify the given series

The given series is \(\sum_{k=10}^{\infty} \frac{1}{k^{p}}\). This is a p-series with the initial index of 10.
02

Apply the p-series convergence test

According to the p-series convergence test, a series in the form of \(\sum_{k=1}^{\infty} \frac{1}{k^{p}}\) converges if \(p > 1\) and diverges if \(p \leq 1\). Since the initial index 10 does not affect the convergence behavior, we can directly apply the p-series convergence test to our given series.
03

Determine the values of \(p\) for convergence and divergence

From the p-series convergence test, we have the following conditions for convergence and divergence: Convergence: \(p > 1\) Divergence: \(p \leq 1\) Thus, the series \(\sum_{k=10}^{\infty} \frac{1}{k^{p}}\) converges for \(p > 1\) and diverges for \(p \leq 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Convergence
The concept of series convergence is vital when dealing with infinite series. An infinite series is a sum of an infinite sequence of terms. For a series to converge, the total sum of its terms must approach a specific finite number as more terms are added.
Convergence depends on the series's features. In mathematical terms, an infinite series \(\sum_{k=1}^{\infty} a_k\) converges if the sequence of partial sums \(S_n = a_1 + a_2 + \cdots + a_n\) approaches a limit as \(n\) tends towards infinity.
  • If the limit \(\lim_{n\to\infty} S_n\) is a finite number, the series converges.
  • Otherwise, if the partial sums increase without bound or oscillate without settling, the series diverges.
Understanding convergence is crucial for analyzing series behavior, especially in calculus and mathematical analysis.
Series Divergence
Divergence is the opposite of convergence in series. When an infinite series diverges, it means that as you add more terms, the total sum does not zero in on a finite value. Instead, it might continue growing indefinitely, or the values might fluctuate without approaching a single number.
A divergent series doesn't have a sum in the traditional sense. It often indicates that the terms don't decrease to zero fast enough or have oscillating terms that prevent settling.
  • In terms of partial sums, if \(\lim_{n\to\infty} S_n\) does not exist or is infinite, the series is divergent.
  • Some common divergent series are the harmonic series or geometric series with a ratio greater than 1.
Understanding divergence helps us to know when a series does not sum up to a well-defined number, immensely important in mathematical predictions and computations.
P-Series Test
The p-series test is a method used to determine the convergence or divergence of a specific type of series known as p-series. A p-series takes the form \(\sum_{k=1}^{\infty} \frac{1}{k^p}\) where \(p\) is a positive constant.
The determining factor for the convergence of a p-series is the value of \(p\). According to the p-series test:
  • The series converges if \(p > 1\).
  • The series diverges if \(p \leq 1\).

The initial index in a series like \(\sum_{k=10}^{\infty} \frac{1}{k^{p}}\) doesn't alter the convergence outcome. For example, this series will still converge for \(p > 1\), covering the same logic as the classical p-series starting from 1.
By identifying and using the appropriate p-series test, one can easily determine if the series converges or diverges based on the value of \(p\), which simplifies analysis significantly.

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Most popular questions from this chapter

Identify a convergence test for each of the following series. If necessary, explain how to simplify or rewrite the series before applying the convergence test. You do not need to carry out the convergence test. $$\sum_{k=1}^{\infty}\left(\tan ^{-1} 2 k-\tan ^{-1}(2 k-2)\right)$$

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Determine whether the following series converge. Justify your answers. $$\sum_{k=1}^{\infty} \frac{(-1)^{k} k}{k^{3}+1}$$

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