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Use the Divergence Test, the Integral Test, or the p-series test to determine whether the following series converge. $$\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{27 k^{2}}}$$

Short Answer

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#Answer# The series $$\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{27 k^{2}}}$$ diverges.

Step by step solution

01

Simplify the given series

First, let's simplify the given series to better understand which convergence test can be used: $$\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{27 k^{2}}} = \sum_{k=1}^{\infty} \frac{1}{(27k^{2})^{1/3}} = \sum_{k=1}^{\infty} \frac{1}{(3k)^{2/3}}$$ Now that we have the series in a simpler form, it is easier to see that we have a p-series where p = 2/3.
02

Apply the p-series Test

Recall that the p-series test is used to determine the convergence of series in the form: $$\sum_{k=1}^{\infty} \frac{1}{k^p}$$ A p-series converges if \(p > 1\) and diverges if \(0 \le p \le 1\). In our case, \(p = \frac{2}{3}\), which is in the range \(0 < p \le 1\). Using the p-series test, we can conclude that the series diverges: $$\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{27 k^{2}}} = \sum_{k=1}^{\infty} \frac{1}{(3k)^{2/3}}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence of Series
Understanding the convergence of series is fundamental for anyone dealing with infinite sequences and sums. A series is a summation of a sequence of terms, and it is said to converge if the partial sums tend to a specific value as more terms are added. In other words, as the series progresses towards infinity, it approaches a finite number rather than growing without bound.

When dealing with the convergence of series, we're essentially asking whether there's a finite limit to the sum of all terms in an infinite sequence. If a series converges, it's important to understand that individual terms must become smaller as the series goes on. This is because, for a sum to settle at a finite value, the contributions of additional terms need to be insignificant in the grand scheme of the entire series.

In the exercise provided, the series in question is \[\begin{equation}\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{27 k^{2}}}\end{equation}\].To determine if this series converges, we apply specific convergence tests that analyze the behavior of the series' terms as they progress towards infinity.
Divergence Test
The Divergence Test is often the first test applied when trying to determine the convergence of a series. It is a simple yet powerful tool that can quickly show whether a series definitely diverges. The core principle of the Divergence Test is based on the observation that if the limit of the series' terms doesn't equal zero, then the series must diverge.

The Divergence Test

Suppose we have a series \[\begin{equation}\sum_{n=1}^{\infty} a_n\end{equation}\],the Divergence Test states the series diverges if:\[\begin{equation}\lim_{n \to \infty} a_n eq 0\end{equation}\].This is based on the rationale that, for a series to converge to a finite value, the individual terms must eventually become infinitesimally small—essentially zero. If this is not the case, the sum cannot stabilize to a limit.

However, if the limit is zero, the Divergence Test is inconclusive, and we must rely on other tests to determine convergence.
Integral Test
In cases where the Divergence Test is inconclusive, the Integral Test can be applied as a method to check for series convergence. The test is particularly useful when dealing with series whose terms are formed from a function that is positive, continuous, and decreasing.

To apply the Integral Test, we consider a series \[\begin{equation}\sum_{n=1}^{\infty} a_n\end{equation}\],where the terms are represented as a function \[\begin{equation}\sum_{n=1}^{\infty} f(n) = a_n\end{equation}\].The Integral Test states that if the integral\[\begin{equation}\int_1^{\infty} f(x) dx\end{equation}\]is finite, then the series converges. Conversely, if the integral is infinite, the series diverges.

This test translates the problem of summing an infinite series into one of calculating an improper integral, which is sometimes easier to evaluate. It is essential, however, to ensure the function meets the criteria for the Integral Test to be valid: namely, that it is positive, continuous, and decreasing over the interval from 1 to infinity. If these conditions aren't met, the results from the Integral Test may not be applicable.

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Most popular questions from this chapter

Here is a fascinating (unsolved) problem known as the hailstone problem (or the Ulam Conjecture or the Collatz Conjecture). It involves sequences in two different ways. First, choose a positive integer \(N\) and call it \(a_{0} .\) This is the seed of a sequence. The rest of the sequence is generated as follows: For \(n=0,1,2, \ldots\) $$a_{n+1}=\left\\{\begin{array}{ll} a_{n} / 2 & \text { if } a_{n} \text { is even } \\ 3 a_{n}+1 & \text { if } a_{n} \text { is odd } \end{array}\right.$$ However, if \(a_{n}=1\) for any \(n,\) then the sequence terminates. a. Compute the sequence that results from the seeds \(N=2,3\) 4,...., 10. You should verify that in all these cases, the sequence eventually terminates. The hailstone conjecture (still unproved) states that for all positive integers \(N\), the sequence terminates after a finite number of terms. b. Now define the hailstone sequence \(\left\\{H_{k}\right\\}\), which is the number of terms needed for the sequence \(\left\\{a_{n}\right\\}\) to terminate starting with a seed of \(k .\) Verify that \(H_{2}=1, H_{3}=7,\) and \(H_{4}=2\) c. Plot as many terms of the hailstone sequence as is feasible. How did the sequence get its name? Does the conjecture appear to be true?

Express each sequence \(\left\\{a_{n}\right\\}_{n=1}^{\infty}\) as an equivalent sequence of the form \(\left\\{b_{n}\right\\}_{n=3}^{\infty}\). $$\left\\{n^{2}+6 n-9\right\\}_{n=1}^{\infty}$$

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