/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 Convert the following expression... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Convert the following expressions to the indicated base. \(a^{1 / / \log _{10} a}\) using base \(10,\) for \(a>0\) and \(a \neq 1\)

Short Answer

Expert verified
Answer: The simplified form of the expression is \(a\).

Step by step solution

01

Identify the change of base formula

We know that the change of base formula is: \(\log _{b} x = \frac{\log _{a} x}{\log _{a} b}\), where \(a\), \(b\), and \(x\) are positive and \(a \neq 1\). So, we can use this formula to convert the given expression to base \(10\).
02

Convert the expression to base \(10\)

Now, let's rewrite the given expression using the change of base formula: \(a^{\frac{1}{\log_{10} a}}\) Since we want to convert to base \(10\), we can rewrite this as: \(a^{\frac{\log_{10}a}{\log_{10}a}}\), by applying the change of base formula.
03

Simplify the expression

Now, we have an expression that is in terms of base \(10\). We can further simplify the expression by using the exponent rules. \(a^{\frac{\log_{10}a}{\log_{10}a}} = a^1\), since the exponent and the base in the denominator cancel out. So, the final expression is simply: \(a^1 = a\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Exponents
Exponents are a fundamental concept in mathematics that help us express repeated multiplication easily. For instance, instead of writing \( a \times a \times a \), we can simply write \( a^3 \), which is read as "\( a \) raised to the power of 3." Exponents are crucial for handling large numbers and are heavily used in scientific notations.

When dealing with exponents, we should remember a few key properties:
  • Product of powers: \( a^m \times a^n = a^{m+n} \)
  • Quotient of powers: \( \frac{a^m}{a^n} = a^{m-n} \)
  • Power of a power: \((a^m)^n = a^{m \times n}\)
  • Zero exponent: \( a^0 = 1 \) if \( a eq 0 \)
Understanding these rules can simplify calculations and allow easy manipulation of expressions involving exponents. These properties are also essential when converting expressions between different bases, as seen in the exercise above.
Exploring Logarithms
Logarithms are the inverse operations of exponents. While exponents ask the question, "What power do we need to raise \( a \) to get \( x \)?", logarithms answer it by giving us the exponent. For instance, if \( a^b = x \), then \( \log_a x = b \).

Logarithms have several properties that make them a powerful tool for simplifying complex problems:
  • Product logarithm: \( \log_a(x \times y) = \log_a x + \log_a y \)
  • Quotient logarithm: \( \log_a\left(\frac{x}{y}\right) = \log_a x - \log_a y \)
  • Power logarithm: \( \log_a(x^b) = b \times \log_a x \)
  • Change of base: \( \log_b x = \frac{\log_a x}{\log_a b} \)
The change of base formula is particularly useful when we need to calculate logarithms in a non-standard base using a calculator or a table that only supports base 10 (common logarithms) or base \( e \) (natural logarithms).

Applying these properties helps in restructuring expressions and makes it easier to handle complex equations as illustrated in the original exercise.
Base Conversion Methods
Base conversion is an essential math skill, particularly in informatics and computer science, where systems often interchange between bases like binary, decimal, and hexadecimal.

In mathematical terms, converting bases is sometimes necessary, especially in logarithms and exponents. One primary tool for base conversion is the change of base formula. This formula allows you to convert a logarithm from one base to another, using a formula you might be more familiar with (e.g., base 10). Here’s the formula again for clarity:
  • Change of base formula: \( \log_b x = \frac{\log_a x}{\log_a b} \)
Sometimes in mathematics, you want to convert the expression involving exponents and logarithms to a base more practical or easier to handle based on the specific problem.

In the provided exercise, the expression \( a^{\frac{1}{\log_{10} a}} \) was converted using base 10. This makes simplifying equations easier because most calculators and mathematical tools are designed to work efficiently in this base. Ultimately, base conversion simplifies calculations, which is why understanding it is crucial for various fields that deal with logarithms and exponents.

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Most popular questions from this chapter

Daylight function for \(40^{\circ} \mathrm{N}\) Verify that the function $$D(t)=2.8 \sin \left(\frac{2 \pi}{365}(t-81)\right)+12$$ has the following properties, where \(t\) is measured in days and \(D\) is the number of hours between sunrise and sunset. a. It has a period of 365 days. b. Its maximum and minimum values are 14.8 and \(9.2,\) respectively, which occur approximately at \(t=172\) and \(t=355\) respectively (corresponding to the solstices). c. \(D(81)=12\) and \(D(264) \approx 12\) (corresponding to the equinoxes).

Shifting and scaling Use shifts and scalings to graph the given functions. Then check your work with a graphing utility. Be sure to identify an original function on which the shifts and scalings are performed. $$h(x)=|3 x-6|+1$$

Square wave Graph the square wave defined by $$f(x)=\left\\{\begin{array}{ll} 0 & \text { if } x<0 \\\1 & \text { if } 0 \leq x<1 \\\0 & \text { if } 1 \leq x<2 \\ 1 & \text { if } 2 \leq x<3 \\\\\vdots\end{array}\right.$$

In each exercise, a function and an interval of its independent variable are given. The endpoints of the interval are associated with points \(P\) and \(Q\) on the graph of the finction. a. Sketch a graph of the function and the secant line through \(P\) and \(Q\) b. Find the slope of the secant line in part \((a),\) and interpret your answer in terms of an average rate of change over the interval. Include units in your answer. The volume \(V\) of an ideal gas in cubic centimeters is given by \(V=2 / p,\) where \(p\) is the pressure in atmospheres and \(0.5 \leq p \leq 2\).

Imagine a lidless box with height \(h\) and a square base whose sides have length \(x .\) The box must have a volume of \(125 \mathrm{ft}^{3}\) a. Find and graph the function \(S(x)\) that gives the surface area of the box, for all values of \(x>0\) b. Based on your graph in part (a), estimate the value of \(x\) that produces the box with a minimum surface area.

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