Chapter 7: Problem 20
Find the antiderivatives. \(\int x^{3} e^{x} d x\)
Short Answer
Expert verified
The antiderivative is \( x^3 e^x - 3x^2 e^x + 6xe^x - 6e^x + C \).
Step by step solution
01
Integration by Parts
To find the antiderivative of \( \int x^3 e^x \, dx \), we can use the method of integration by parts. The formula for integration by parts is \( \int u \, dv = uv - \int v \, du \). In this case, we choose \( u = x^3 \) and \( dv = e^x \, dx \). This gives us \( du = 3x^2 \, dx \) and \( v = e^x \), since the antiderivative of \( e^x \) is \( e^x \).
02
Apply Integration by Parts
Substitute \( u \), \( du \), \( v \), and \( dv \) into the integration by parts formula. This gives us: \[ \int x^3 e^x \, dx = x^3 e^x - \int 3x^2 e^x \, dx. \] We now have a new integral, \( \int 3x^2 e^x \, dx \), which requires another application of integration by parts.
03
Second Integration by Parts
Repeat the integration by parts for \( \int 3x^2 e^x \, dx \). Choose \( u = x^2 \) and \( dv = 3e^x \, dx \). Thus, \( du = 2x \, dx \) and \( v = 3e^x \). Substitute these into the formula to get: \[ \int 3x^2 e^x \, dx = 3x^2 e^x - \int 6x e^x \, dx. \] Simplify and substitute this expression back into our equation from Step 2.
04
Third Integration by Parts
For the integral \( \int 6x e^x \, dx \), apply integration by parts again with \( u = x \) and \( dv = 6e^x \, dx \). Then \( du = dx \) and \( v = 6e^x \). Therefore, \[ \int 6x e^x \, dx = 6xe^x - \int 6e^x \, dx. \] The remaining integral \( \int 6e^x \, dx \) is straightforward.
05
Solve Remaining Integral
The remaining integral \( \int 6e^x \, dx \) is a basic exponential integral. The antiderivative of \( 6e^x \) is simply \( 6e^x \). Substitute this back into the solution from Step 4 and simplify:
06
Combine and Simplify
Substitute all computed parts back to the original expression:\[ \begin{align*} \int x^3 e^x \, dx &= x^3 e^x - \left(3x^2 e^x - 6xe^x + 6e^x \right) \ &= x^3 e^x - 3x^2 e^x + 6xe^x - 6e^x \end{align*} \] Finally, ensure correct simplification and represent the solution with the constant of integration \( C \):\[ x^3 e^x - 3x^2 e^x + 6xe^x - 6e^x + C. \]
07
Final Answer
The antiderivative of \( \int x^3 e^x \, dx \) is given by the expression: \[ x^3 e^x - 3x^2 e^x + 6xe^x - 6e^x + C, \] where \( C \) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Antiderivative
The antiderivative, also known as the indefinite integral, is a foundational concept in calculus. It represents the inverse operation of differentiation, meaning it seeks to find a function whose derivative is the given function. In simple terms, the antiderivative of a function gives a new function that describes the accumulated area under the curve of the original function.When finding antiderivatives, we often encounter a constant of integration, denoted as "C." This constant reflects the fact that there are infinitely many functions differing by a constant that have the same derivative. In mathematics, the general form of an antiderivative is expressed as:
- If the derivative of a function is known as \( f(x) \), the antiderivative is represented by:\[\int f(x) \, dx = F(x) + C,\]where \( F(x) \) is the antiderivative and \( C \) is the constant of integration.
Exponential Function
One important family of functions in calculus is the exponential function, particularly \( e^x \). The exponential function is special because it is its own derivative. This unique property makes calculus involving exponential functions more straightforward in some cases.Why are exponential functions important?
- The exponential function \( e^x \) is defined as the limit:\[e^x = \lim_{n\to\infty} \left(1 + \frac{x}{n} \right)^n.\]
- It represents continuous growth or decay processes, making it vital in scientific disciplines such as biology, physics, and economics.
- In integration, knowing that the derivative and the integral of \( e^x \) are both \( e^x \) simplifies many problems. For instance, in the integral \( \int 6e^x \, dx \), the antiderivative is easily found to be \( 6e^x + C \).
Integration Techniques
When faced with the task of finding an antiderivative, various integration techniques can be employed based on the function's form. A commonly used technique is **integration by parts**, especially suitable for products of functions, such as polynomials multiplied by exponentials.Integration by Parts:
- Integration by parts is based on the product rule for differentiation. The formula is:\[\int u \, dv = uv - \int v \, du.\]
- This technique is crucial when an integral involves multiplying a function that simplifies upon differentiation \( (u) \) by another that is easily integrated \( (dv) \).
- For the exercise \( \int x^3 e^x \, dx \), the successive application of integration by parts reduces a complex integral into smaller, more manageable pieces.