/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Sketch the curves. Identify clea... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the curves. Identify clearly any interesting features, including local maximum and minimum points, inflection points, asymptotes, and intercepts. $$ y=e^{x}-\sin x $$

Short Answer

Expert verified
The curve has a y-intercept at \((0, 1)\), a critical point near \(x = -0.5\), and rises to infinity as \(x\) approaches infinity.

Step by step solution

01

Find the y-intercept

To find the y-intercept, set \( x = 0 \) and solve for \( y \). So, \( y = e^{0} - \sin(0) = 1 - 0 = 1 \). The y-intercept is the point \((0, 1)\).
02

Calculate the derivatives

Calculate the first and second derivatives to find critical points and inflection points. * First derivative: \[ y' = \frac{d}{dx}(e^{x} - \sin x) = e^{x} - \cos x \] * Second derivative:\[ y'' = \frac{d}{dx}(e^{x} - \cos x) = e^{x} + \sin x \]
03

Find critical points

Critical points occur where the first derivative is zero.Solve \( e^x - \cos x = 0 \) for \( x \). This requires numerical methods or estimation. There is a critical point near \( x \approx -0.5 \).
04

Find inflection points

Inflection points occur where the second derivative is zero.Solve \( e^x + \sin x = 0 \) for \( x \). This also requires numerical approximations. An inflection point might exist, it requires verification near \( x = 0 \).
05

Check for asymptotes

As \( x \to \infty \), \( e^x \to \infty \) and \(-\sin x\) oscillates between -1 and 1. Therefore, \( y \to \infty \). As \( x \to -\infty \), \( e^x \to 0 \) and \(-\sin x\) still oscillates between -1 and 1. This suggests no horizontal asymptotes or oblique/asymptotes.
06

Sketch the curve

Plot the key points found: y-intercept \((0, 1)\), estimated critical point near \(x \approx -0.5\), and recognition of \( y \to \infty \) as \( x \to \infty \).Show the behavior of the function as it approaches \( y \) increasing and decreasing based on the derivative estimates.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivatives
Derivatives allow us to understand how a function changes. They are crucial for sketching graphs and identifying important features like slopes and direction of curves. Calculating derivatives involves finding the rate at which a function changes at any given point.

To sketch the curve for the function \( y = e^x - \sin x \), we first compute its first derivative as \( y' = e^x - \cos x \). This derivative tells us how the function is increasing or decreasing depending on the sign of the derivative. Knowing the first derivative helps determine critical points, which we'll discuss later.
  • First derivative: Helps identify slopes and tangent lines.
  • Second derivative: Needed for concavity and inflection points.
Calculating derivatives is fundamental in understanding and analyzing the shape of a graph.
Inflection Points
Inflection points are where a curve changes its concavity; that is, from concave up to concave down or vice versa. These are pivotal in sketching smooth transitions between hills and troughs in a graph.

To find inflection points in the function \( y = e^x - \sin x \), we examine the second derivative \( y'' = e^x + \sin x \). Inflection points occur where this second derivative is zero, indicating a switch in concavity. This can be tricky as it might require numerical methods to find exact points. For this function, an inflection point may exist near \( x = 0 \), although further verification is needed.
  • Identifies changes in the graph's bending.
  • Determines where the curve transitions smoothly between hill and valley.
Understanding inflection points can enrich the detail and accuracy when sketching graphs.
Critical Points
Critical points of a function happen where the first derivative is zero or undefined. These points can indicate local maximums, local minimums, or saddle points.

For the function \( y = e^x - \sin x \), critical points are found by setting the first derivative \( y' = e^x - \cos x \) to zero. Solving \( e^x - \cos x = 0 \) requires estimation or numeric methods. In this case, a critical point appears near \( x \approx -0.5 \). At this point, the curve pauses its increase or decrease, offering potential peaks or troughs.
  • Helps identify maxima and minima.
  • Useful for sketching curves accurately and identifying peaks.
Recognizing and calculating critical points sharpen our overall understanding of a graph's behavior.
Asymptotes
Asymptotes are lines that a graph approaches but never touches or crosses. They provide an understanding of the behavior of functions at extreme values of \( x \).

For the function \( y = e^x - \sin x \), examining asymptotes reveals its end behavior. As \( x \to \infty \), \( e^x \to \infty \) while \(-\sin x\) fluctuates between -1 and 1, causing \( y \to \infty \). As \( x \to -\infty \), \( e^x \to 0 \) and \(-\sin x\) also oscillates, suggesting no horizontal asymptotes exist here. This information is vital when sketching to depict how the graph behaves at infinity.
  • Indicates end behavior.
  • Helps visualize how the graph behaves at limits.
Understanding asymptotes is essential for a complete sketch of a function's graph.
Intercepts
Intercepts are the points where the graph of a function crosses the axes. They are crucial for creating a basic framework of how the curve interacts with its surroundings.

To find the y-intercept of the function \( y = e^x - \sin x \), set \( x = 0 \): \( y = e^0 - \sin(0) = 1 \), giving us the intercept at \((0, 1)\). This means the curve crosses the y-axis at this point.
  • X-intercepts: Points where the graph crosses the x-axis.
  • Y-intercepts: Points where the graph crosses the y-axis.
Determining intercepts offers a starting blueprint for sketching the entire curve, helping to place the graph within the coordinate system.

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