Chapter 4: Problem 1
Find the derivatives of the following functions from definition. (a) \(f(x)=(2 x+3)^{2}\) (b) \(g(x)=x^{3 / 2}\)
Short Answer
Expert verified
(a) \(f'(x) = 8x + 12\); (b) \(g'(x) = \frac{3}{2}x^{1/2}\).
Step by step solution
01
Understand the Definition of the Derivative
The derivative of a function \( f(x) \) from its definition is given by the limit formula: \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]This formula will be used to find the derivatives of the given functions.
02
Apply the Limit Formula for \(f(x)=(2x+3)^2\)
First, substitute \( f(x) = (2x+3)^2 \) into the limit formula:\[ f'(x) = \lim_{h \to 0} \frac{(2(x+h)+3)^2 - (2x+3)^2}{h} \]Simplify the expression \((2(x+h)+3)^2 = (2x + 2h + 3)^2\). Use the formula \((a+b)^2 = a^2 + 2ab + b^2\) to expand it:\[ = (2x+3)^2 + 2(2x+3)(2h) + (2h)^2 \]Subtract \( (2x+3)^2 \) to find:\[ 2(2x+3)(2h) + (2h)^2 \]Divide each term by \(h\) and then take the limit as \(h\) approaches 0.
03
Simplify and Evaluate the Limit for \(f(x)=(2x+3)^2\)
The expression becomes:\[ = \lim_{h \to 0} \left(4(2x+3) + 4h\right) \]As \( h \to 0 \), the term with \( h \) vanishes:\[ f'(x) = 4(2x + 3) \]Thus, the derivative is:\[ f'(x) = 8x + 12 \]
04
Apply the Limit Formula for \(g(x)=x^{3/2}\)
Substitute \( g(x) = x^{3/2} \) into the derivative definition:\[ g'(x) = \lim_{h \to 0} \frac{(x+h)^{3/2} - x^{3/2}}{h} \]Use the binomial approximation or another algebraic approach to simplify \((x+h)^{3/2}\) if necessary.Express the difference as:\[ (x+h)^{3/2} - x^{3/2} = (\sqrt{x+h})^3 - (\sqrt{x})^3 \]This can be simplified using algebra intended to deal with cube roots.
05
Simplify and Evaluate the Limit for \(g(x)=x^{3/2}\)
Using binomial approximation or another algebraic method like the binomial expansion, simplify the expression and then divide by \(h\):After simplification, divide by \( h \) and take the limit as \( h \to 0 \).The leading term from the expansion should reveal that:\[ g'(x) = \frac{3}{2} x^{\frac{1}{2}} \]This involves using properties of limits and algebra simplification.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit Formula
The limit formula is a fundamental concept in calculus used to find the derivative of a function. The derivative from the definition is an expression involving a limit, written as \( f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \). This formula captures the idea of the instantaneous rate of change of a function at any given point.
It essentially measures how a function changes as its input changes, by examining the slope of the tangent line to the function’s graph at a point.
It essentially measures how a function changes as its input changes, by examining the slope of the tangent line to the function’s graph at a point.
- First, we replace \(x\) with \(x+h\) in the function.
- Then, we calculate the difference \(f(x+h) - f(x)\).
- We divide this difference by \(h\).
- Finally, we take the limit as \(h\) approaches zero to find the derivative.
Polynomial Differentiation
Polynomial differentiation refers to the process of finding the derivative of a polynomial function. These types of functions are characterized by terms like \(ax^n\), where \(a\) is a coefficient and \(n\) is a non-negative integer. In our example, we differentiated the function \(f(x) = (2x + 3)^2\).
To differentiate a polynomial, we use the power rule, which states that if \(f(x) = x^n\), then \(f'(x) = nx^{n-1}\). In combination with algebraic expansion, this rule allows us to find derivatives efficiently.
To differentiate a polynomial, we use the power rule, which states that if \(f(x) = x^n\), then \(f'(x) = nx^{n-1}\). In combination with algebraic expansion, this rule allows us to find derivatives efficiently.
- Start by expanding the polynomial, if necessary.
- Apply the power rule to each term of the polynomial.
- Combine like terms to find the simplest form of the derivative.
Radical Functions
Radical functions involve roots, such as square roots or cube roots, and finding their derivatives can be a bit more challenging than polynomials. In the exercise, we worked with the function \(g(x) = x^{3/2}\) which includes a square root raised to the power of three.
To differentiate radical functions, we often rewrite them using exponent notation. For instance, \( \sqrt{x} \) can be expressed as \( x^{1/2} \), making it easier to apply the differentiation rules.
To differentiate radical functions, we often rewrite them using exponent notation. For instance, \( \sqrt{x} \) can be expressed as \( x^{1/2} \), making it easier to apply the differentiation rules.
- Convert all radical terms to exponents.
- Apply the derivative power rule \( nx^{n-1} \) to differentiate.
- Simplify the expression if required.