Chapter 16: Problem 5
Let \(E\) be the volume described by \(x^{2}+y^{2}+z^{2} \leq 4,\) and \(f=\left\langle x^{3}, y^{3}, z^{3}\right\rangle .\) Compute \(\iint_{\partial E} f\). \(\boldsymbol{N} d S .\)
Short Answer
Expert verified
The integral evaluates to \(\frac{256\pi}{5}\).
Step by step solution
01
Understand the Problem
The problem involves calculating the surface integral of the vector field \( f = \langle x^3, y^3, z^3 \rangle \) over the surface of a sphere defined by \( x^2 + y^2 + z^2 = 4 \), which is a sphere of radius 2. We need to find \( \iint_{\partial E} f \cdot \boldsymbol{N} \, dS \), where \( \boldsymbol{N} \) is the outward unit normal.
02
Identify the Divergence Theorem
The Divergence Theorem states \( \iint_{\partial E} f \cdot \boldsymbol{N} \, dS = \iiint_{E} abla \cdot f \, dV \), where \( abla \cdot f \) is the divergence of \( f \). We apply this theorem because the surface \( \partial E \) is the boundary of the solid sphere \( E \).
03
Compute the Divergence
Compute the divergence of \( f = \langle x^3, y^3, z^3 \rangle \). The divergence \( abla \cdot f = \frac{\partial}{\partial x}(x^3) + \frac{\partial}{\partial y}(y^3) + \frac{\partial}{\partial z}(z^3) = 3x^2 + 3y^2 + 3z^2 \).
04
Set Up the Integral
The integral we need to calculate is \( \iiint_{E} (3x^2 + 3y^2 + 3z^2) \, dV \), where \( E \) is the sphere \( x^2 + y^2 + z^2 \leq 4 \).
05
Change to Spherical Coordinates
Change the integral to spherical coordinates: \( x = \rho \sin \phi \cos \theta \), \( y = \rho \sin \phi \sin \theta \), \( z = \rho \cos \phi \). The Jacobian determinant for spherical coordinates is \( \rho^2 \sin \phi \).
06
Set Up the Integral in Spherical Coordinates
\[ \iiint_E (3\rho^2) (\sin^2 \phi \cos^2 \theta + \sin^2 \phi \sin^2 \theta + \cos^2 \phi) \rho^2 \sin \phi \, d\rho \, d\phi \, d\theta \] simplifies to \( 3\rho^4 \sin^3 \phi \, d\rho \, d\phi \, d\theta \).
07
Solve the Integral
The integral becomes \( 3 \int_0^{2\pi} d\theta \int_0^{\pi} \sin^3 \phi \, d\phi \int_0^2 \rho^4 \, d\rho \). Solving gives: \( \int_0^2 \rho^4 \, d\rho = \frac{32}{5} \), \( \int_0^{\pi} \sin^3 \phi \, d\phi = \frac{4}{3} \), and \( \int_0^{2\pi} d\theta = 2\pi \). Multiply these results.
08
Final Calculation
The integral evaluates to \[ 3 \times 2\pi \times \frac{4}{3} \times \frac{32}{5} = \frac{256\pi}{5} \]. This is the value of \( \iint_{\partial E} f \cdot \boldsymbol{N} \, dS \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Divergence Theorem
The Divergence Theorem is a pivotal concept in vector calculus, connecting the flow of a vector field through a closed surface to the behavior of the vector field within the volume encompassed by this surface. Imagine you have a sphere and a vector field flowing out of it like air blowing from a balloon. This theorem lets you calculate the total 'outflow' across the surface by focusing only on what's happening inside the sphere.
The core equation of the Divergence Theorem is:
The core equation of the Divergence Theorem is:
- \( \iint_{\partial E} \mathbf{F} \cdot \boldsymbol{N} \, dS = \iiint_{E} abla \cdot \mathbf{F} \, dV \)
- \( \mathbf{F} \) is the vector field,
- \( \boldsymbol{N} \) is the outward unit normal vector to the surface \( \partial E \),
- and \( abla \cdot \mathbf{F} \) represents the divergence of \( \mathbf{F} \).
Exploring Spherical Coordinates
Spherical coordinates offer a compelling way to describe points in three-dimensional space, especially when dealing with spheres or problems exhibiting symmetry. Unlike Cartesian coordinates (\(x, y, z\)), spherical coordinates use three values:\ \(\rho\), \(\phi\), and \(\theta\).
- \(\rho\) represents the distance from the origin to a point, the radius.
- \(\phi\) is the angle down from the positive \(z\)-axis, similar to latitude.
- \(\theta\) is the angle in the \(xy\)-plane from the positive \(x\)-axis, akin to longitude.
- \(x = \rho \sin \phi \cos \theta\)
- \(y = \rho \sin \phi \sin \theta\)
- \(z = \rho \cos \phi\)
Understanding Vector Fields
A vector field assigns a vector to every point in space, much like a field of arrows, where each arrow has a direction and a magnitude based on its location. Vector fields are fundamental in modeling physical phenomena, such as magnetic fields, fluid flow, and gravity. Imagine each vector in the field pointing in a direction that a particle at that location would move.
The vector field \( f = \langle x^3, y^3, z^3 \rangle \) in our exercise creates a scenario where the vectors become longer as they move away from the origin, aligning with each point's coordinate values cubed. This kind of representation helps visualize how a variable might change or flow through space.
The vector field \( f = \langle x^3, y^3, z^3 \rangle \) in our exercise creates a scenario where the vectors become longer as they move away from the origin, aligning with each point's coordinate values cubed. This kind of representation helps visualize how a variable might change or flow through space.
Divergence of a Vector Field
The divergence of a vector field describes how much a vector field spreads out or converges at a point. Think of divergence as a measure of a field's tendency to originate from or converge into a point, similar to water flowing out of or into a drain.
Mathematically, for a vector field \( \mathbf{F} = \langle F_1, F_2, F_3 \rangle \), the divergence is given by:
Mathematically, for a vector field \( \mathbf{F} = \langle F_1, F_2, F_3 \rangle \), the divergence is given by:
- \( abla \cdot \mathbf{F} = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z} \)